(a) State Gay Lussac's law of combining volumes (b) Hydrogen reacts with oxygen according to the following equation; 2H\(_{2(g)}\) + O\(_{2(g)}\) ---> 2H\(_...
Question 1 Report
(a) State Gay Lussac's law of combining volumes
(b) Hydrogen reacts with oxygen according to the following equation;
2H\(_{2(g)}\) + O\(_{2(g)}\) ---> 2H\(_2\)O\(_{(g)}\). If 50cm\(^3\) of hydrogen were sparked with 30cm\(^{3}\) of oxygen, calculate the volume of unused oxygen after cooling to the initial temperature and pressure.
Answer Details
(a) Gay-Lussac's law of combining volumes: When gases react, they do so in volumes that bear a simple whole-number ratio to one another and to the volume of any gaseous product, provided the temperature and pressure remain constant.
(b) 2H2 + O2 → 2H2O. Hydrogen and oxygen react in the volume ratio 2 : 1.
50 cm3 of H2 requires \(\dfrac{50}{2}=25\ \text{cm}^3\) of O2.
Oxygen supplied = 30 cm3; oxygen used = 25 cm3.
\[ \text{Unused oxygen}=30-25=5\ \text{cm}^3 \]Download The App On Google Playstore
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