If x + 0.4y = 3 and y = \(\frac{1}{2}\)x, find the value of (x + y)

Assessment: WAEC SSCE - General Mathematics - 2012 (Objective) Subject: General Mathematics

Question 1 Report

If x + 0.4y = 3 and y = \(\frac{1}{2}\)x, find the value of (x + y)
Answer Details
We are given that x + 0.4y = 3 and y = \(\frac{1}{2}\)x. Substitute y in the first equation: x + 0.4 * (\(\frac{1}{2}\)x) = 3 x + 0.2x = 3 1.2x = 3 x = 2.5 Substitute x in the equation for y: y = \(\frac{1}{2}\) * 2.5 = 1.25 Then, x + y = 2.5 + 1.25 = 3.75. Therefore, the value of (x + y) is 3\(\frac{3}{4}\). Hence, the correct option is (c) 3\(\frac{3}{4}\).
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