If p = {prime factors of 210} and Q = {prime less than 10}, find p \(\cap\) Q

If p = {prime factors of 210} and Q = {prime less than 10}, find p \(\cap\) Q

Answer Details

The prime factors of 210 are 2, 3, 5, and 7. The prime numbers less than 10 are 2, 3, 5, and 7. The intersection (p ∩ Q) is the set of elements that are in both p and Q. Therefore, p ∩ Q is {2, 3, 5, 7}. So, the correct option is: - {2,3,5,7}