Question

Which of these statements about y = 8$\sqrt{m}$ is correct?

Accepted Answer

log y = 3 log 2 + $\frac{1}{2}$ log m

Answer

log y = log 8 x log $\sqrt{m}$

Answer

log y = 3 log 2 x $\frac{1}{2}$ log m

Answer

log y = 3 log 2 - $\frac{1}{2}$ log m

Which of these statements about y = 8\(\sqrt{m}\) is correct?