In the diagram, ∠ZWZY and WYX are right angles. Find the perimeter of WXYZ.

In ΔWYZ: 

hyp2 ${}^2$ = adj2 ${}^{\mathrm{<br>}}$ + opp2 ${}^{\mathrm{<br>}}$

hyp2 ${}^{\mathrm{<br>}}$ =32 ${}^{\mathrm{<br>}}$ + 42 ${}^{\mathrm{<br>}}$ → 9 + 16

hyp2 ${}^{\mathrm{<br>}}$ = 25

hyp = 5

In  ΔWXY:

hyp2 ${}^{\mathrm{<br>}}$ = adj2 ${}^{\mathrm{<br>}}$ + opp2 ${}^{\mathrm{<br>}}$

hyp2 ${}^{\mathrm{<br>}}$ = 122 ${}^{\mathrm{<br>}}$ + 52 ${}^{\mathrm{<br>}}$ = 144 +25

hyp2 ${}^{\mathrm{<br>}}$ = 169

hyp = 13

the perimeter of WXYZ. = 3+4+12+13 → 32cm