Solve y+24 - y−13 > 1

Question 1 Report

Solve $\frac{y + 2}{4}$ - $\frac{y - 1}{3}$ > 1

y < -10

y < -2

y < 2

y < 10

Answer Details

multiply both sides by the LCM

12 x $\frac{y + 2}{4}$ - 12 x $\frac{y - 1}{3}$ >12 x 1

3[y+2] - 4[y-1] > 12

3y + 6 - 4y + 4 > 12

-y + 2 > 12

-y > 12 - 10 = 2

y < -2