Given that log3 3 27 = 2x + 1, find the value of x.

Given that log3 ${}_3$ 27 = 2x + 1, find the value of x.

Answer Details

Recall that: log3 ${}_3$ 27 → log3 ${}_3$33 ${}^{\mathrm{<br>}}$

3log3 ${}_3$3 → 3 * 1

= 3

Then log3 ${}_3$ 27 = 2x + 1

→ 3 = 2x + 1 

3 - 1 = 2x

2 = 2x

1 = x