The length of a rectangle is 10 cm. If its perimeter is 28 cm, find the area

Let's start by using the formula for the perimeter of a rectangle: P = 2L + 2W, where L is the length and W is the width. We are given that the length L is 10 cm and the perimeter P is 28 cm. So we can substitute these values into the formula and solve for the width W: P = 2L + 2W 28 = 2(10) + 2W 28 = 20 + 2W 2W = 8 W = 4 Now that we know the width of the rectangle is 4 cm, we can use the formula for the area of a rectangle: A = L x W, where L is the length and W is the width. We already know L is 10 cm and we just found that W is 4 cm. So we can substitute these values into the formula and solve for the area A: A = L x W A = 10 x 4 A = 40 Therefore, the area of the rectangle is 40 cm2.