The length of a rectangle is 10 cm. If its perimeter is 28 cm, find the area
Answer Details
Let's start by using the formula for the perimeter of a rectangle: P = 2L + 2W, where L is the length and W is the width. We are given that the length L is 10 cm and the perimeter P is 28 cm. So we can substitute these values into the formula and solve for the width W:
P = 2L + 2W
28 = 2(10) + 2W
28 = 20 + 2W
2W = 8
W = 4
Now that we know the width of the rectangle is 4 cm, we can use the formula for the area of a rectangle: A = L x W, where L is the length and W is the width. We already know L is 10 cm and we just found that W is 4 cm. So we can substitute these values into the formula and solve for the area A:
A = L x W
A = 10 x 4
A = 40
Therefore, the area of the rectangle is 40 cm2.