TEST OF PRACTICAL KNOWLEDGE QUESTION Measure and record the emf, V\(_{o}\) of the cell provided. Connect a circuit as shown in the diagram above. With the k...

TEST OF PRACTICAL KNOWLEDGE QUESTION

1. Measure and record the emf, V\(_{o}\) of the cell provided.
2. Connect a circuit as shown in the diagram above.
3. With the key, K closed vary the rheostat, Rh to obtain a current 1 = 0.20A. Read and record the corresponding value of the potential difference, V on the voltmeter.
4. Evaluate 1\(^{-1}\) and V\(^{-1}\).
5. Repeat the procedure for four other values of l = 0.25, 0.30, 0.35 and 0.40 A. Tabulate your readings.
6. Plot a graph V\(^{-1}\) on the vertical axis against 1\(^{-1}\) on the horizontal axis.
7. Determine the slope, s, of the graph
8. Evaluate s\(^{-1}\).
9. State two precautions taken to ensure accurate results.

 (b)i. Explain Ohmic conductor:

ii. Explain resistivity of the material of a wire.

(a) Measurement and tabulation

The emf of the cell was measured with the voltmeter when the circuit was open:

\[ V_o = 3.0\ \text{V} \]

The circuit was connected as shown, with the ammeter in series and the voltmeter connected across the resistor/load. The key was closed briefly and the rheostat adjusted to obtain the stated current values. The corresponding voltmeter readings were recorded.

For the first reading:

\[ I=0.20\ \text{A} \]

\[ I^{-1}=\frac{1}{0.20}=5.00\ \text{A}^{-1} \]

If \(V=0.19\ \text{V}\), then:

\[ V^{-1}=\frac{1}{0.19}=5.26\ \text{V}^{-1} \]

Table of readings

S/N	\(I\) (A)	\(I^{-1}\) (A-1)	\(V\) (V)	\(V^{-1}\) (V-1)
1	0.20	5.00	0.19	5.26
2	0.25	4.00	0.23	4.35
3	0.30	3.33	0.28	3.57
4	0.35	2.86	0.33	3.03
5	0.40	2.50	0.38 Read lesson note on Current Electricity (JAMB) Answer Details (a) Measurement and tabulation The emf of the cell was measured with the voltmeter when the circuit was open: \[ V_o = 3.0\ \text{V} \] The circuit was connected as shown, with the ammeter in series and the voltmeter connected across the resistor/load. The key was closed briefly and the rheostat adjusted to obtain the stated current values. The corresponding voltmeter readings were recorded. For the first reading: \[ I=0.20\ \text{A} \] \[ I^{-1}=\frac{1}{0.20}=5.00\ \text{A}^{-1} \] If \(V=0.19\ \text{V}\), then: \[ V^{-1}=\frac{1}{0.19}=5.26\ \text{V}^{-1} \] Table of readings S/N \(I\) (A) \(I^{-1}\) (A-1) \(V\) (V) \(V^{-1}\) (V-1) 1 0.20 5.00 0.19 5.26 2 0.25 4.00 0.23 4.35 3 0.30 3.33 0.28 3.57 4 0.35 2.86 0.33 3.03 5 0.40 2.50 0.38 Read lesson note on Current Electricity (JAMB) Current Electricity View Answer Related Questions 1 TEST OF PRACTICAL KNOWLEDGE QUESTION Using the diagram above as a guide, carry out the following instructions. Place the meter rule provided on the knife edg... 2 TEST OF PRACTICAL KNOWLEDGE QUESTION Determine and record the approximate focal length f\(_{o}\) of the concave mirror provided. Arrange the ray box, the mir... Download The App On Google Playstore Everything you need to excel in JAMB, WAEC & NECO Personalized AI Learning Chat Assistant Thousands of JAMB, WAEC & NECO Past Questions Over 1200 Lesson Notes Offline Support - Learn Anytime, Anywhere Green Bridge Timetable Literature Summaries & Potential Questions Track Your Performance & Progress In-depth Explanations for Comprehensive Learning