In the diagram above, PQ = 10 cm, PS = 8 cm and ∠PSR is 60∘ ∘ while ∠SRQ is a right angle. Find SR

In the diagram above, PQ = 10 cm, PS = 8 cm and ∠PSR is 60${}^{\circ }$ while ∠SRQ is a right angle. Find SR

Answer Details

In ΔPST; cos 60 = ST/8
ST = 8cos 60
ST = 8 x 1/2 = 4
TR = 10 cm (opp. sides of a rectangle PQRT)
SR = ST + TR
SR = 4 + 10
SR = 14 cm