In triangle XYZ, ∠XYZ = 15∘ ∘ , ∠XZY = 45∘ ..

Question 1 Report

In triangle XYZ, ∠XYZ = 15 $^{\circ}$ , ∠XZY = 45 $^{\circ}$ and lXYl = 7 cm. Find lYZl.

14√2 cm

7 (\frac{\sqrt{6}}{2})

7√2 cm

7 cm

Answer Details

= 180 - 60
= 120

^{\circ}

Using sine rule

\frac{x}{s i n x} = \frac{7}{s i n z} \frac{x}{s i n 120} = \frac{7}{s i n 45} x = \frac{7 s i n 120}{s i n 45} x = \frac{7 s i n (180 - 120)}{s i n 45} x = \frac{7 s i n 60}{s i n 45} = (7 (\frac{\sqrt{3}}{2}) \div \frac{1}{\sqrt{2}}) x = (7 (\frac{\sqrt{3}}{2}) \div \frac{1}{\sqrt{2}}) x = 7 (\frac{\sqrt{6}}{2})

In triangle XYZ, ∠XYZ = 15∘ ∘ , ∠XZY = 45∘ ∘ and lXYl = 7 cm. Find lYZl.