In the diagram above, |QR| is the diameter of the semicircle QR. Find the area of the figure to the nearest whole number. {π=227 π = 22 7 }

Question 1 Report

In the diagram above, |QR| is the diameter of the semicircle QR. Find the area of the figure to the nearest whole number. { $π = \frac{22}{7}$ }

90cm2

89cm2

80cm2

70cm2

Answer Details

Area of PQRS = length x breath(7 x 10)cm2 = 70

Area of semi-circle $\frac{1}{2} π r^{2} = \frac{1}{2} \times \frac{22}{7} \times \frac{7}{2}$

= 19.5cm2 = 20cm2(appr.)

Area of the figure = (70 + 20)cm2

= 90cm2

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