If y = x2 - x - 12, find the range of values of x for which y ≥ ≥ 0

Question 1 Report

If y = x2 - x - 12, find the range of values of x for which y $\geq$ 0

x < -3 0r x > 4

x

\leq

-3 or x

\geq

4

-3 < x

\geq

4

-3

\leq

x

\leq

4

Answer Details

y = x2 - x - 12
= (x - 4)(x - 3)
∴ x = 4 or x = -3
-3 < x < 4

But y $\geq$ 0
∴ -3 < x $\leq$ 4

Read lesson note on Inequalities (JAMB)

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