If y = x2 - x - 12, find the range of value..

Question 1 Report

If y = x2 - x - 12, find the range of values of x for which y $\geq$ 0

x < -3 0r x > 4

\leq

-3 or x

\geq

-3 < x

\geq

-3

\leq

\leq

Answer Details

y = x2 - x - 12
= (x - 4)(x - 3)
∴ x = 4 or x = -3
-3 < x < 4

But y $\geq$ 0
∴ -3 < x $\leq$ 4

If y = x2 - x - 12, find the range of values of x for which y ≥ ≥ 0