If p varies inversely as the cube of q and q varies directly as the square of r, what is the relationship between p and r?
Answer Details
P ∝ 1/q3 P = K/q3 q3 = K/P q = K/p1/3 But q ∝ r2 q = Kr2K/p1/3 = Kr2 r2 = K/p1/3 x 1/K r2 = 1/p1/3 r = (1/p1/3)2 r = 1/p1/6 r ∝ 1/p1/6 ∴ r varies inversely as 6√P