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Evaluate ∫0−4(1−2x)dx

Question 1 Report

Evaluate $\int_{- 4}^{0} (1 - 2 x) d x$

-16

-20

20

10

Answer Details

∫0−4(1−2x)dx=[x−x2]0−4=(0−0+C)−(−4(−4)2+C)=C−(−4−16+C)=C−(−20+C)=C+20−C=20

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