Question 1 Report
In the parallelogram PQRS given, find angle < SQR
Answer Details
< QRS = 30∘ ∘ (corresponding < ), < QSR = 50∘ ∘
< SQR = 180∘ ∘ - (30 + 50)∘ ∘ (Sum of < S in a △ △ )
180∘ ∘ - 80∘ ∘ = 100∘