(a)(i) What is 2 homologous series? (ii) Give two homologous series present in petroleum (iii) Give one example of a compound belonging to each of the homol...

Assessment: WAEC SSCE - Chemistry - 2007 (Essay) Subject: Chemistry

Question 1 Report

(a)(i) What is 2 homologous series?

(ii) Give two homologous series present in petroleum

(iii) Give one example of a compound belonging to each of the homologous series in (a)(ii).

(iv) Name two fractions obtained from the fractional distillation of petroleum

(v) Why is there a gradual change in the physical properties of petroleum fractions?

 

b) Write a two-step balanced chemical equation for the reaction of (i) ethanol with excess concentration traoxosulphate (VI) acid at high temperature

(ii) excess ethanol with concentrated tetraoxosulphate (VI) acid at lower temperature.

 

(c) An organic compound of relative molecular mass 46, on analysis vas ound to contain 52.0% carbon, 13.3% hydrogen and 34.7% oxygen.

(i) Determine its I. empirical formula, II. molecular formula.

(ii) Draw two possible structures of the compound and name one of them [O = 16; C = 12; H = 1 ] 

 

Answer Details

(a)(i) A homologous series is a family of organic compounds having the same general formula and similar chemical properties, in which successive members differ by a \(\mathrm{CH_2}\) unit.

(ii) Two homologous series present in petroleum are:

  1. Alkanes
  2. Cycloalkanes

(iii) Examples are:

  • Alkane: methane, \(\mathrm{CH_4}\)
  • Cycloalkane: cyclohexane, \(\mathrm{C_6H_{12}}\)

(iv) Two fractions obtained from the fractional distillation of petroleum are petrol (gasoline) and kerosene.

(v) There is a gradual change in physical properties because the fractions contain hydrocarbons with gradually increasing molecular masses and carbon-chain lengths. Consequently, the intermolecular forces and boiling points increase from one fraction to the next.


(b)(i) Ethanol with excess concentrated tetraoxosulphate(VI) acid at high temperature:

At about \(170^\circ\mathrm{C}\), ethanol is dehydrated to ethene in two steps:

\[\mathrm{C_2H_5OH + H_2SO_4 \rightarrow C_2H_5HSO_4 + H_2O}\]
\[\mathrm{C_2H_5HSO_4 \rightarrow C_2H_4 + H_2SO_4}\]

(ii) Excess ethanol with concentrated tetraoxosulphate(VI) acid at lower temperature:

At about \(140^\circ\mathrm{C}\), diethyl ether is formed in two steps:

\[\mathrm{C_2H_5OH + H_2SO_4 \rightarrow C_2H_5HSO_4 + H_2O}\]
\[\mathrm{C_2H_5HSO_4 + C_2H_5OH \rightarrow C_2H_5OC_2H_5 + H_2SO_4}\]

(c)(i)(I) Empirical formula

ElementCHO
Percentage composition52.013.334.7
Divide by atomic mass\(52.0/12=4.33\)\(13.3/1=13.3\)\(34.7/16=2.17\)
Divide by 2.17261

Empirical formula = \(\boxed{\mathrm{C_2H_6O}}\).

(c)(i)(II) Molecular formula

Empirical formula mass = \((2\times12)+(6\times1)+16=46\).

\[n=\frac{\text{relative molecular mass}}{\text{empirical formula mass}}=\frac{46}{46}=1\]

Molecular formula = \((\mathrm{C_2H_6O})_1=\boxed{\mathrm{C_2H_6O}}\).

(c)(ii) Two possible structural formulae of \(\mathrm{C_2H_6O}\)

figure
Structural formulae of the two possible compounds with molecular formula C₂H₆O.

The first structure is ethanol. The second structure is methoxymethane, also called dimethyl ether.

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