The relationship between the velocity (U) of gas molecules and their relative molecular mass (M) is shown by the equation

Assessment: JAMB UTME - Chemistry - 1986 Subject: Chemistry

Question 1 Report

U = (kM)

\frac{1}{2}

U = (kM)2

U =

\sqrt{k} m

U = (

\frac{k}{m}

)

^{\frac{1}{2}}

Answer Details

The relationship between (U) of a gas molecule and the relative molecular mass is

\bar{U}

= (

\frac{k}{m}

)

^{\frac{1}{2}}

or $\bar{U}$ = $\sqrt{k} m$

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