a lead bullet of mass 0.05kg is fired with a velocity of 200ms-1 into a lead block of mass 0.95kg. Given that the lead block can move freely, the final kine...
a lead bullet of mass 0.05kg is fired with a velocity of 200ms-1 into a lead block of mass 0.95kg. Given that the lead block can move freely, the final kinetic energy after impact is
Answer Details
From principle of conservation of linear momentum, (0.05 x 200) - (0.95 x 0) = (0.05 + 0.95) x V (since collision is inelastic).