What is the mean deviation of 3, 5, 8, 11, 12 and 21?

Assessment: JAMB UTME - Mathematics - 2007 Subject: General Mathematics

Question 1 Report

What is the mean deviation of 3, 5, 8, 11, 12 and 21?
Answer Details
The mean deviation is a measure of the spread of a dataset. It is calculated by finding the average of the absolute deviations of the values from the mean. First, we need to find the mean of the given values: mean = (3+5+8+11+12+21)/6 = 60/6 = 10 Next, we find the absolute deviation of each value from the mean: |3-10| = 7 |5-10| = 5 |8-10| = 2 |11-10| = 1 |12-10| = 2 |21-10| = 11 The sum of these absolute deviations is: 7+5+2+1+2+11 = 28 Finally, we find the mean deviation by dividing the sum of absolute deviations by the number of values: mean deviation = 28/6 = 4.7 Therefore, the mean deviation of the given values is 4.7.

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