A small circular membrane is 10cm below the surface of a pool of mercury when the barometric height is 76 cm of mercury. If the density of mercury is 13600\...
Question 1 Report
A small circular membrane is 10cm below the surface of a pool of mercury when the barometric height is 76 cm of mercury. If the density of mercury is 13600\(kgm^{-3}\), what is the pressure on the membrane in \(Nm^{-2}\)? \((g =10ms^{-2})\)
Answer Details
The pressure at any point in a fluid is given by the formula P = hρg, where P is the pressure at the point, h is the height of the fluid above the point, ρ is the density of the fluid and g is the acceleration due to gravity. In this problem, the height of the mercury column above the membrane is (76 - 10) = 66 cm = 0.66 m. The density of mercury is 13600 kg/m³ and the acceleration due to gravity is 10 m/s². Substituting these values into the formula gives: P = hρg = 0.66 x 13600 x 10 = 8976 N/m² = 8.98 x 10⁴ Nm⁻² (to 3 significant figures) Therefore, the correct option is: 1.17 x 105 Nm-2.
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