The relation y = x2 + 2x + k passes through the point (2,0). Find the value of k

The relation y = x² + 2x + k passes through the point (2,0). Find the value of k

Answer Details

We know that the relation y = x² + 2x + k passes through the point (2,0), which means that when x=2, y=0. So, substituting these values in the relation, we get: 0 = 2² + 2(2) + k 0 = 4 + 4 + k 0 = 8 + k Therefore, k = -8. Hence, the value of k is -8.