The sum of \(3\frac{7}{8}\) and \(1\frac{1}..

Question 1 Report

The sum of \(3\frac{7}{8}\) and \(1\frac{1}{3}\) is less than the difference between \(\frac{3}{8}\) and \(1\frac{2}{3}\) by:

3\(\frac{2}{3}\)

5\(\frac{1}{4}\)

6\(\frac{1}{2}\)

8\(\frac{1}{8}\)