If y varies directly as √n n and y = 4 when n = 4, find y when n = 179

If y varies directly as $\sqrt{n}$ and y = 4 when n = 4, find y when n = 1$\frac{7}{9}$

Answer Details

y $\alpha \sqrt{n}$
y = k$\sqrt{n}$
when y = 4, n = 4
4 = k$\sqrt{4}$
4 = 2k
k = 2
Therefore,
y = 2$\sqrt{n}$
y = 2$\sqrt{\frac{16}{9}}$
y = 2$\left(\frac{4}{3}\right)$
y = $\frac{8}{3}$