X 2 3 4 5 F 2 5 2 1 What is the median of the distribution?
Question 1 Report
| X | 2 | 3 | 4 | 5 |
| F | 2 | 5 | 2 | 1 |
What is the median of the distribution?
Answer Details
When a group data is involved, cumulative frequency is used. The formula will be: Median=[(N+1)/2]th
For member of odd number items. That is, where N is odd
Median=([N/2]th + [N/2 + 1]th)/2
For member of odd number items. That is, where N is odd
Solution:
From the table, there are 20 members as indicated by the cumulative frequency. Since the members are odd (10) the median age will be ([N/2]th + [N/2 + 1]th)/2
Median=([10/2]th + [10/2 + 1]th)/2
=(5th + 6th)/2
The 5th member is 3 and the 6th member is on 3
Median=(3 + 3)/2
=6/2
Median = 3
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