Given that \(x = -\frac{1}{2}and \hspace{1mm} y = 4 \hspace{1mm} evaluate \hspace{1mm} 3x^2y+xy^2\)
Answer Details
Substituting the given values of x and y into the expression, we have:
\begin{align*}
3x^2y+xy^2 &= 3\left(-\frac{1}{2}\right)^2(4) + \left(-\frac{1}{2}\right)(4)^2\\
&= 3\left(\frac{1}{4}\right)(4) + \left(-\frac{1}{2}\right)(16)\\
&= 3 + (-8)\\
&= -5
\end{align*}
Therefore, the answer is -5.