If y = 3 cos(x/3), find dy/dx when x = (3π/2)

If y = 3 cos(x/3), find dy/dx when x = (3π/2)

Answer Details

y = 3cos(x/3)
dy/dx = 3x(1/3)x - sin (x/3)
= - sin x/3
But x = 3π/2 ∴ -sin(x/3) = -sin(3π/6)
= -sin (3 * 180)/6
= - sin 90
= -1