The diagram shows a potential divider circuit. A 9 V battery is connected to two resistors R₁ and R₂ in series. The output voltage is taken across R₂. What ...
Question 1 Report
The diagram shows a potential divider circuit. A 9 V battery is connected to two resistors R₁ and R₂ in series. The output voltage is taken across R₂.
What is the output voltage across R₂?
Answer Details
In a potential divider, the output voltage across \( R_2 \) is:
\[ V_{\text{out}} = V_{\text{in}} \times \frac{R_2}{R_1 + R_2} = 9 \times \frac{6}{3 + 6} = 9 \times \frac{6}{9} = 6.0 \text{ V} \]The output voltage is 6.0 V. The larger resistor (\( R_2 = 6 \) k\(\Omega\)) takes a larger share of the total voltage. The remaining 3.0 V is dropped across \( R_1 \). A common error is to reverse the resistors in the formula, which would give 3.0 V instead.
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