A manometer contains water of density 1000 kg/m3. The level on the gas side is 20 cm (0.20 m) lower than on the open side. Using g = 10 N/kg, by how much do...
Question 1 Report
A manometer contains water of density 1000 kg/m3. The level on the gas side is 20 cm (0.20 m) lower than on the open side. Using g = 10 N/kg, by how much does the gas pressure exceed atmospheric pressure?
Answer Details
The excess pressure of the gas above atmospheric pressure equals the pressure produced by the extra height of liquid on the open side. Using \( p = \rho g h \) with density = 1000 kg/m3, g = 10 N/kg, and \( h \) = 0.20 m:
\[ p = 1000 \times 10 \times 0.20 = 2000 \text{ Pa} \]
20000 Pa comes from using 2 m instead of 0.20 m. 200 Pa uses 0.02 m, and 20 Pa uses 0.002 m. The key step is converting 20 cm to 0.20 m before substituting.
Download The App On Google Playstore
Everything you need to excel in your exams
