A student added a portion of orange bromine water to four different hydrocarbons and shook each mixture. The observations are shown in Table 3.1. hydrocarbo...

Assessment: Chemistry (9-1) 0971 | Paper 6 Mock 01 | Alternative to Practical Subject: Chemistry (9-1) - 0971

Question 1 Report

A student added a portion of orange bromine water to four different hydrocarbons and shook each mixture. The observations are shown in Table 3.1.

hydrocarbonformulaobservation with bromine watersaturated or unsaturated
methaneCH4stays orangesaturated
etheneC2H4?unsaturated
propaneC3H8stays orange?
buteneC4H8orange to colourless?

(a) Complete Table 3.1 by filling in the three boxes marked with a question mark. [3]
(b) Name the type of reaction that takes place when bromine reacts with an alkene. [1]
(c) State which two compounds in the table are alkenes. [1]

Answer Details

This question tests the link between structure (saturated alkane vs unsaturated alkene) and the bromine water result. An alkene has a C=C double bond, so it decolourises bromine water; an alkane does not.

(a) The completed table is:

hydrocarbonformulaobservation with bromine watersaturated or unsaturated
methaneCH4stays orangesaturated
etheneC2H4orange to colourlessunsaturated
propaneC3H8stays orangesaturated
buteneC4H8orange to colourlessunsaturated

Ethene decolourises the bromine water (orange to colourless) because it is unsaturated [1]; propane fits the general formula \(C_nH_{2n+2}\) and leaves the colour, so it is saturated [1]; butene fits \(C_nH_{2n}\) and decolourises the bromine water, so it is unsaturated [1]. [3]

(b) When bromine reacts with an alkene, bromine atoms add across the double bond, so the reaction type is addition [1].

(c) The two alkenes are ethene and butene [1] (their names end in "-ene" and their formulae fit \(C_nH_{2n}\)).

Exam tip: a formula fitting \(C_nH_{2n}\) (twice as many H as C) is an alkene; \(C_nH_{2n+2}\) is an alkane.

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