The interior angles of a pentagon are 126o, 114o, y, 92o and 83o. Find the value of y.

Assessment: WAEC SSCE - General Mathematics - 1997 (Objective) Subject: General Mathematics

Question 1 Report

The interior angles of a pentagon are 126^o, 114^o, y, 92^o and 83^o. Find the value of y.

85^o

95^o

105^o

115^o

125^o

Answer Details

The sum of the interior angles of a pentagon is given by the formula (n-2) × 180^o where n is the number of sides of the polygon. In this case, n=5 since it's a pentagon. So, sum of interior angles = (5-2) × 180^o = 540^o We know that the other four angles measure 126^o, 114^o, 92^o, and 83^o. Therefore, 126^o + 114^o + y + 92^o + 83^o = 540^o Simplifying the above equation, we get: y = 125^o Therefore, the value of y is 125^o.

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