Make x the subject of the relation d = \(\s..

Question 1 Report

Make x the subject of the relation d = \(\sqrt{\frac{6}{x} - \frac{y}{2}}\)

x = \(\frac{6 + 12}{d^2 + y}\)

x = \(\frac{12}{d^2 - y}\)

x = \(\frac{12}{y} - 2d^2\)

x = \(\frac{12}{2d^2 + y}\)