A student sets up a ripple tank experiment to compare the diffraction of waves through gaps of different widths. She uses a motor to generate plane waves an...

Assessment: Physics 0625 | Paper 3 Mock 01 | Theory (Core) Subject: Physics - 0625

Question 1 Report

A student sets up a ripple tank experiment to compare the diffraction of waves through gaps of different widths. She uses a motor to generate plane waves and records her observations.

Gap width / cmWavelength / cmRatio gap/wavelengthObserved pattern after gap
1.02.00.5almost fully circular wavefronts
2.02.01.0circular wavefronts with strong spreading
4.02.02.0moderate spreading at edges, mostly plane in centre
8.02.04.0slight edge spreading only
16.02.08.0very little spreading, nearly all plane
diagram

(a) State the conclusion the student can draw about the relationship between the gap/wavelength ratio and the amount of diffraction. [2]

(b) State the gap/wavelength ratio that produces the most effective diffraction (circular wavefronts). [1]

(c) The student wants to increase the wavelength without changing the motor. Describe how she could do this. [1]

(d) Calculate the wave speed if the motor vibrates at 5.0 Hz and the wavelength is 2.0 cm. [1]

(e) The student notices that at the widest gap (16.0 cm), the wavefronts are almost plane. Explain why this is similar to light passing through a window. [2]

(f) Suggest one improvement to make the experiment more quantitative. [1]

(g) State one safety precaution when using the ripple tank. [1]

(h) Explain why the student should use sloped edges (beaches) at the sides of the tank. [1]

Answer Details

(a)

  • As the ratio of gap width to wavelength increases, the amount of diffraction decreases. [1]
  • The most diffraction occurs when the ratio is close to 1 or less (gap width equal to or smaller than the wavelength). [1]

The table shows this trend clearly: at a ratio of 0.5, the wavefronts are almost fully circular (maximum spreading), while at a ratio of 8.0, there is very little spreading. Diffraction is strongest when the gap is comparable to the wavelength.

(b) The most effective diffraction (fully circular wavefronts) occurs at a gap/wavelength ratio of 0.5 (or 1.0). [1]

At ratio 0.5 the gap is smaller than the wavelength, forcing the waves to spread in all directions as if the gap were a point source.

(c) She could increase the depth of the water in the tank. [1]

Water waves travel faster in deeper water. Since the motor keeps the frequency constant, \(v = f\lambda\) means a higher speed produces a longer wavelength.

(d)

\(v = f \times \lambda = 5.0 \times 2.0 = 10\text{ cm/s}\) [1]

(e)

  • The wavelength of visible light is extremely small (about \(5 \times 10^{-7}\) m) compared to the width of a window (perhaps 1 m). [1]
  • The gap/wavelength ratio is therefore extremely large (around 2 000 000), so there is negligible diffraction and light passes through as a straight beam with sharp shadow edges. [1]

This is exactly the same physics as the 16.0 cm gap in the experiment: when the gap is many times larger than the wavelength, the waves pass through with almost no spreading.

(f) Measure the angle of spread of the diffracted wavefronts (e.g. using a protractor or by photographing the pattern and measuring digitally). [1]

Quantifying the angle allows a numerical comparison between different gap/wavelength ratios, rather than relying on qualitative descriptions.

(g) Mop up any water spills immediately to prevent slipping, or keep electrical connections away from the water. [1]

(h) The sloped edges (beaches) absorb the waves and prevent reflections from the tank walls. [1]

Without beaches, reflected waves would overlap with the incident waves and create a confused interference pattern, making it impossible to observe the diffraction clearly.

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