A student added dilute sulfuric acid, a portion at a time, to green copper(II) carbonate in a beaker in order to prepare copper(II) sulfate. She recorded he...

Assessment: Chemistry 0620 | Paper 6 Mock 01 | Alternative to Practical Subject: Chemistry - 0620

Question 1 Report

A student added dilute sulfuric acid, a portion at a time, to green copper(II) carbonate in a beaker in order to prepare copper(II) sulfate. She recorded her observations in a results table. Table 2.1 shows the table with some observations missing.

Table 2.1

Stage of the experimentObservation
dilute sulfuric acid added to the green solid 
gas bubbled through limewater 
green solid added until no more reacts 

(a) Complete the table by writing the missing observation at each stage. [3]
(b) Name the gas that is produced and give the result of the test on the gas. [2]
(c) Explain why the student adds the green solid until it is in excess. [1]

Answer Details

This question tests the observations when a metal carbonate reacts with an acid to make a salt, and the test for the gas produced.

(a) The completed table is:

Stage of the experimentObservation
dilute sulfuric acid added to the green solideffervescence (bubbles); the green solid dissolves to give a blue solution
gas bubbled through limewaterthe limewater turns milky / cloudy
green solid added until no more reactsfizzing stops and some green solid stays undissolved

Acid on the carbonate gives effervescence and a blue solution [1]; the gas turns limewater milky [1]; in excess, the fizzing stops and solid remains [1]. [3]

(b) The gas is carbon dioxide [1]; it turns limewater milky [1]. This is the standard test for \(CO_2\), where \(CO_2 + Ca(OH)_2 \rightarrow CaCO_3 + H_2O\), the white calcium carbonate causing the cloudiness. [2]

(c) The green solid is added in excess to make sure all of the acid has reacted [1], so no acid is left to contaminate the salt. The leftover solid is later removed by filtering.

Exam tip: "blue solution" identifies a copper(II) salt, and "limewater turns milky" identifies carbon dioxide, so a carbonate is present.

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