Question 1 Report
During the electrolysis of water the volume of gas at each electrode was measured over time.
| time / min | volume at electrode A / cm3 | volume at electrode B / cm3 |
|---|---|---|
| 1 | 4 | 2 |
| 2 | 8 | 4 |
| 3 | 12 | 6 |
Positive ions travel to the negative electrode, and in acidified water the ion available there is H+, which gains electrons to give hydrogen: 2H+ + 2e- → H2. So the gas at electrode A is hydrogen.
The volumes confirm it. At each time the reading at A is exactly double the reading at B: 4 and 2, then 8 and 4, then 12 and 6, so the ratio is a constant 2 : 1. That is precisely what 2H2O → 2H2 + O2 predicts, since equal volumes of gases contain equal numbers of molecules under the same conditions.
Quoting 1 : 2 reverses the order asked for, and calling the cathode gas oxygen swaps the electrodes. Check the direction of the ratio against the wording before writing it down.
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