Question 1 Report
3 Fig. 3.1 shows a maize cob with grains of two different colours. In maize, purple grain colour (P) is dominant over yellow grain colour (p). A farmer crosses a homozygous purple-grained plant with a yellow-grained plant to produce an F1 generation.
Fig. 3.1
(a) State the genotype of the yellow-grained parent plant. [1]
(b) State the phenotype of the F1 offspring. [1]
(c) Give the genotype of all F1 plants. [1]
(d) The F1 plants are allowed to cross-pollinate with each other to produce an F2 generation.
(i) State the gametes produced by an F1 plant. [1]
(ii) Draw a Punnett square to show the expected genotypes of the F2 offspring. [2]
(iii) State the expected phenotypic ratio in the F2 generation. [1]
(e) Explain why a farmer might carry out a test cross on a purple-grained maize plant. [2]
(f) Describe how a test cross is carried out and state how the results would show whether the purple-grained plant is homozygous or heterozygous. [3]
Labelled answer diagram:
(a) The genotype of the yellow-grained parent plant is pp. [1] Yellow grain colour is the recessive trait, so the plant must carry two copies of the recessive allele to express it. There is no dominant P allele present to mask the yellow phenotype.
(b) The phenotype of all F1 offspring is purple-grained. [1] Since one parent is homozygous dominant (PP) and the other is homozygous recessive (pp), every F1 individual inherits one P allele and one p allele, making them all Pp. The dominant P allele produces the purple colour.
(c) The genotype of all F1 plants is Pp (heterozygous). [1]
(d)(i) The gametes produced by an F1 plant (Pp) are P and p. [1] During meiosis, the two alleles separate into different gametes, so each gamete carries only one allele.
(d)(ii) Punnett square for the F1 cross (Pp x Pp):
| P | p | |
|---|---|---|
| P | PP | Pp |
| p | Pp | pp |
The gametes P and p are shown across the top (from one parent) and down the side (from the other parent). [1] The four offspring genotypes are correctly placed: PP, Pp, Pp, and pp. [1]
(d)(iii) The expected phenotypic ratio in the F2 generation is 3 purple : 1 yellow (3:1). [1] Three of the four genotypes (PP, Pp, Pp) express the dominant purple phenotype; only pp expresses the recessive yellow phenotype.
(e) A farmer might carry out a test cross on a purple-grained plant because:
(f) How a test cross is carried out and interpreted:
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