Question 1 Report
| Ear type | Number of F2 piglets |
|---|---|
| Erect ears | 34 |
| Floppy ears | 14 |
| Total | 48 |
(a) In a breed of pig, the allele for erect ears (E) is dominant over the allele for floppy ears (e).
A pig farmer crossed a homozygous erect-eared boar with a floppy-eared sow. All of the F1 piglets had erect ears.
(i) State the genotypes of the boar and the sow. [2]
(ii) State the genotype of the F1 piglets. [1]
(iii) Two F1 piglets were crossed. Using a Punnett square, determine the expected genotype and phenotype ratios of the F2 generation. [4]
(b) The farmer recorded the ear type of 48 F2 piglets. The results are shown in the table.
(i) Calculate the ratio of erect-eared to floppy-eared piglets. Show your working. [2]
(ii) Suggest why this ratio is not exactly 3 : 1. [1]
(c) Explain what is meant by the term heterozygous. [1]
(d) Describe how a farmer could use a test cross to find out whether an erect-eared pig is homozygous or heterozygous. [4]
(a)(i) The genotypes of the parents are: boar = EE (homozygous dominant) [1]; sow = ee (homozygous recessive). [1] The boar is stated to be homozygous erect-eared, and the sow has floppy ears which can only occur with the genotype ee.
(a)(ii) The genotype of the F1 piglets is Ee (heterozygous). [1] Each F1 piglet inherits one E allele from the EE father and one e allele from the ee mother. All F1 piglets have erect ears because the dominant E allele masks the recessive e.
(a)(iii) Crossing two F1 piglets (Ee x Ee):
Parents: Ee x Ee
Gametes from each parent: E and e
| E | e | |
|---|---|---|
| E | EE | Ee |
| e | Ee | ee |
Offspring genotypes: EE, Ee, Ee, ee [1]
Expected genotype ratio: 1 EE : 2 Ee : 1 ee [1]
Expected phenotype ratio: 3 erect ears : 1 floppy ears [1] (EE and Ee both show the dominant erect-ear phenotype; only ee shows floppy ears.) [1]
(b)(i) Calculating the ratio of erect-eared to floppy-eared piglets from the data:
Erect ears = 34, Floppy ears = 14
\[ \text{Ratio} = \frac{34}{14} : \frac{14}{14} = 2.4 : 1 \] [1] for method (dividing both by the smaller number), [1] for arriving at approximately 2.4 : 1.
(b)(ii) The ratio is not exactly 3:1 because fertilisation is a random event, and the sample size (48 piglets) is relatively small. [1] Chance variation means the actual numbers will fluctuate around the expected ratio; a perfect 3:1 would require 36 erect : 12 floppy, but random sampling produced 34:14 instead.
(c) Heterozygous means having two different alleles for a particular gene - one dominant and one recessive (e.g. Ee). [1] The dominant allele determines the phenotype in a heterozygous individual.
(d) How to use a test cross to determine whether an erect-eared pig is homozygous or heterozygous:
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