The Venn diagram shows the number of members of a sports club who play badminton \(B\) and who play squash \(S\). (a) Find \(n(B)\). [1] (b) Find \(n\big((B...

Assessment: Mathematics 0580 | Paper 2 Mock 01 | Non-calculator (Extended) Subject: Mathematics - 0580

Question 1 Report

The Venn diagram shows the number of members of a sports club who play badminton \(B\) and who play squash \(S\).

(a) Find \(n(B)\). [1]

(b) Find \(n\big((B\cup S)'\big)\). [1]

(c) Find \(n(B'\cap S)\). [1]

(d) A member is chosen at random. Find the probability that this member plays both games. [1]

(e) Find the probability that this member plays exactly one of the two games. [2]

Answer Details

Reading a Venn diagram means recognising which regions each piece of set notation covers. Here the diagram's four regions are the badminton-only region, the overlap of the two circles, the squash-only region and the outside.

(a) \(n(B)\) is the whole badminton circle, both its own region and the overlap it shares with squash: \(n(B)=20\) [B1]

(b) \((B\cup S)'\) is the region outside both circles, the members who play neither game: \(9\) [B1]

(c) \(B'\cap S\) means not badminton and squash, so it is the squash-only region: \(11\) [B1]

Since the four regions total \(40\) members, the overlap holds \(6\) and the badminton-only region holds \(20-6=14\).

(d) Playing both games is the overlap: \(P=\frac{6}{40}=\frac{3}{20}\) [B1] oe, dividing numerator and denominator by \(2\).

(e) Exactly one game means the two "only" regions, deliberately excluding the overlap:

\(P=\frac{14+11}{40}\) [M1] \(=\frac{25}{40}=\frac{5}{8}\) [A1] oe

Note the difference between \(n(B)=20\), which includes the members who also play squash, and the badminton-only count of \(14\). The word "exactly" is the signal to exclude the overlap.

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