Work out \(\sqrt[3]{216} + \sqrt{169} - 2^4\).

This tests recognising a cube root, a square root and a power, then combining them in the correct order. Roots and indices are evaluated before the addition and subtraction.

1. \(\sqrt[3]{216} = 6\), because \(6 \times 6 \times 6 = 36 \times 6 = 216\) [B1].
2. \(\sqrt{169} = 13\), because \(13 \times 13 = 169\), and \(2^4 = 2 \times 2 \times 2 \times 2 = 16\) [B1].
3. Combine left to right: \(6 + 13 - 16 = 19 - 16 = 3\) [A1].

The values \(216\), \(169\) and \(16\) are all worth knowing by sight for a non-calculator paper. Note that \(\sqrt[3]{216}\) is \(6\), not \(72\); dividing by \(3\) instead of taking the cube root is a frequent error.