Green Bridge Learning Resource For Kinematics

Overview

Calculus describes motion exactly. Differentiating a displacement gives velocity, and differentiating velocity gives acceleration; integrating reverses each step. The area under a velocity-time graph is the distance travelled.

In this lesson you will apply differentiation and integration to kinematics problems involving displacement, velocity and acceleration, and draw and use the related motion graphs.

Lesson Evaluation

Congratulations on completing the lesson on Kinematics. Now that youve explored the key concepts and ideas, its time to put your knowledge to the test. This section offers a variety of practice questions designed to reinforce your understanding and help you gauge your grasp of the material.

You will encounter a mix of question types, including multiple-choice questions, short answer questions, and essay questions. Each question is thoughtfully crafted to assess different aspects of your knowledge and critical thinking skills.

Use this evaluation section as an opportunity to reinforce your understanding of the topic and to identify any areas where you may need additional study. Don't be discouraged by any challenges you encounter; instead, view them as opportunities for growth and improvement.

To get velocity from displacement you: A. integrate B. differentiate C. square D. add a constant Answer: B
Acceleration is the rate of change of: A. displacement B. velocity C. distance D. time Answer: B
The area under a velocity-time graph gives the: A. acceleration B. distance travelled C. speed D. time Answer: B
If s = 3t^3 - 10t^2 + 4t, then v at general t is: A. 9t^2 - 20t + 4 B. 6t - 10 C. 9t^2 - 20t D. 3t^2 - 10t Answer: A
The gradient of a velocity-time graph gives the: A. distance B. displacement C. acceleration D. speed Answer: C