Trigonometric Ratios And The Pythagorean Theorem
Overview
Right triangles hide a powerful pattern: fix one angle and the ratios of the sides are locked in, no matter how big the triangle is. Those ratios are sine, cosine and tangent, and with the Pythagorean theorem they let you find unknown sides and angles.
In this lesson you will use the three trigonometric ratios and the Pythagorean theorem to solve right triangles: finding a missing side or a missing angle from the information you are given.
Objectives
- Use the sine, cosine and tangent ratios and the Pythagorean theorem to solve right-angled triangles in applied problems.
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Lesson Note
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Lesson Evaluation
Congratulations on completing the lesson on Trigonometric Ratios And The Pythagorean Theorem. Now that youve explored the key concepts and ideas, its time to put your knowledge to the test. This section offers a variety of practice questions designed to reinforce your understanding and help you gauge your grasp of the material.
You will encounter a mix of question types, including multiple-choice questions, short answer questions, and essay questions. Each question is thoughtfully crafted to assess different aspects of your knowledge and critical thinking skills.
Use this evaluation section as an opportunity to reinforce your understanding of the topic and to identify any areas where you may need additional study. Don't be discouraged by any challenges you encounter; instead, view them as opportunities for growth and improvement.
- In a right triangle with legs 3 and 4, the hypotenuse is: A. 5 B. 7 C. 12 D. 25 Answer: A
- Which ratio equals opposite over hypotenuse? A. cosine B. tangent C. sine D. none Answer: C
- tan θ is equal to: A. opposite/hypotenuse B. adjacent/hypotenuse C. opposite/adjacent D. hypotenuse/opposite Answer: C
- If the hypotenuse is 10 and the angle is 30°, the opposite side is (sin 30° = 0.5): A. 5 B. 8.66 C. 10 D. 20 Answer: A
- To find an angle from a known ratio you use: A. the Pythagorean theorem B. an inverse trig function C. the slope D. the midpoint Answer: B
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