Further Pure Mathematics - 4PM1 PearsonEdexcel

Applications Of Calculus

Overview

Integration does far more than reverse differentiation. It lets you calculate the exact area enclosed by a curve, find the region trapped between two graphs, and even compute the volume of a solid formed by spinning a curve around an axis. These ideas turn abstract equations into concrete measurements.

You will also see how calculus drives kinematics: velocity is the derivative of displacement, and acceleration is the derivative of velocity. By integrating or differentiating, you can move freely between displacement, velocity and acceleration, solving motion problems that algebra alone cannot reach.

Objectives

  1. Understand how displacement, velocity and acceleration are related using calculus
  2. Determine areas under curves and between curves using integration
  3. Determine volumes of revolution about the coordinate axes

Mind map

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Lesson Note

How much paint covers a wall whose outline follows a curve? How fast is a particle moving at the instant it changes direction? These questions look very different, but both are answered by the same machinery: integration and differentiation applied to real quantities. In this topic you will connect the abstract tools of calculus to areas, volumes, and the physics of motion.

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Lesson Evaluation

Congratulations on completing the lesson on Applications Of Calculus. Now that youve explored the key concepts and ideas, its time to put your knowledge to the test. This section offers a variety of practice questions designed to reinforce your understanding and help you gauge your grasp of the material.

You will encounter a mix of question types, including multiple-choice questions, short answer questions, and essay questions. Each question is thoughtfully crafted to assess different aspects of your knowledge and critical thinking skills.

Use this evaluation section as an opportunity to reinforce your understanding of the topic and to identify any areas where you may need additional study. Don't be discouraged by any challenges you encounter; instead, view them as opportunities for growth and improvement.

  1. What does the definite integral of y = f(x) between x = a and x = b represent geometrically? A) The gradient of the curve B) The signed area between the curve and the x-axis C) The volume of revolution D) The length of the curve Answer: B
  2. The region under y = 3x from x = 0 to x = 2 is rotated about the x-axis. What is the volume? A) 12 pi B) 24 pi C) 36 pi D) 6 pi Answer: C
  3. A particle has displacement s = t^3 - 6t^2 + 9t. When is it instantaneously at rest? A) t = 1 and t = 3 B) t = 0 and t = 3 C) t = 2 only D) t = 3 only Answer: A
  4. To find the area between two curves y = f(x) and y = g(x), you calculate: A) The integral of f(x) times g(x) B) The integral of f(x) + g(x) C) The integral of f(x) - g(x) where f is above g D) The integral of f(x) divided by g(x) Answer: C
  5. The volume of revolution about the x-axis formula uses: A) pi times the integral of y dx B) pi times the integral of y squared dx C) The integral of pi y dx D) 2 pi times the integral of y dx Answer: B

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