WAEC SSCE - Chemistry - 1997
Ajụjụ 1 Ripọtì
If an element R belongs to the same group as sodium, an aqueous solution of ROH will
Akọwa Nkọwa
If an element R belongs to the same group as sodium, then it is likely to have similar properties as sodium. Sodium hydroxide (NaOH) is an alkali and a base. When a group 1 metal hydroxide dissolves in water, it forms an alkaline solution. Hence, if an aqueous solution of ROH is similar to NaOH, it will also form an alkaline solution. An alkaline solution has a pH greater than 7 and turns red litmus paper blue. Therefore, the correct option is "have pH greater than 7".
Ajụjụ 2 Ripọtì
A given volume of methane diffuses in 20 seconds. How long will it take the same volume of sulphur (IV) oxide to diffuse under the same conditions? [CH4 = 16; SO2 = 64]
Akọwa Nkọwa
The rate of diffusion of a gas is inversely proportional to the square root of its molar mass. This means that the heavier the gas, the slower it diffuses. The molar mass of methane (CH4) is 16, while the molar mass of sulphur (IV) oxide (SO2) is 64. Therefore, the ratio of the square root of the molar masses of methane to sulphur (IV) oxide is: √(64/16) = √4 = 2 This means that sulphur (IV) oxide diffuses at a rate that is 2 times slower than methane under the same conditions. Since it takes methane 20 seconds to diffuse, it will take sulphur (IV) oxide 2 times longer, which is: 20 x 2 = 40 seconds Therefore, the answer is 40 seconds.
Ajụjụ 3 Ripọtì
Which of the following is used widely in the manufacture of flavours and perfumes?
Akọwa Nkọwa
Alkanoates are widely used in the manufacture of flavours and perfumes. These are organic compounds that contain the functional group -COO- and are also known as esters. They are often used in the food industry to create fruity or sweet flavours and in the perfume industry to create floral or fruity scents. Alkanones, alkanes, complex sugars, and aliphatic compounds are not commonly used in the manufacture of flavours and perfumes.
Ajụjụ 4 Ripọtì
The loss of molecules of water of crystallization to the atmosphere by some crystalline salts is known as
Akọwa Nkọwa
Efflorescence is the loss of water of crystallization to the atmosphere by some crystalline salts. This occurs when the salt is exposed to dry air, causing the water molecules to evaporate and leaving the salt in a dry and powdery form. The process is the opposite of hygroscopy, which is the ability of a substance to absorb moisture from the atmosphere. The word "efflorescence" comes from the Latin word "efflorescere," which means "to flower out."
Ajụjụ 5 Ripọtì
What is the value of x in the following equation? MnO- 4 + 4H+ + xe- → MnO 2 + 2H2O
Ajụjụ 6 Ripọtì
A mixture of NaCI(s) and CaCO3(s) is best separated by
Akọwa Nkọwa
The best method to separate a mixture of NaCl and CaCO3 is dissolution followed by filtration. This is because NaCl is soluble in water, while CaCO3 is not. By dissolving the mixture in water, NaCl will dissolve, while CaCO3 remains undissolved. Filtration can then be used to separate the insoluble CaCO3 from the solution containing the dissolved NaCl. The other options are not suitable because sublimation is not effective for separating NaCl and CaCO3, and dissolution followed by crystallization and evaporation will only work for the soluble component (NaCl) and not the insoluble component (CaCO3).
Ajụjụ 7 Ripọtì
Which of the following statements is correct about sodium chloride in the solid state?
Akọwa Nkọwa
Ajụjụ 8 Ripọtì
If the value of ∆H for a reaction is negative, it means that the reaction is
Akọwa Nkọwa
If the value of ∆H for a reaction is negative, it means that the reaction is exothermic. An exothermic reaction releases heat to the surroundings. ∆H is the change in enthalpy during a reaction, and when ∆H is negative, it means that the products have lower enthalpy than the reactants. This implies that energy is released during the reaction, which results in the increase in temperature of the surroundings. Exothermic reactions are spontaneous, and they occur on their own without any external energy input.
Ajụjụ 9 Ripọtì
From the following equations, what is the order of decreasing reactivity of X, Y and Z? Y (s) + X2+(aq) → Y2+(aq) + X(s) X(s) + Z2+(aq) → X2+(aq) + Z(s)
Akọwa Nkọwa
Ajụjụ 11 Ripọtì
Which of the following is used as water softener?
Ajụjụ 13 Ripọtì
The valence electrons of element 12Mg are in the
Akọwa Nkọwa
The valence electrons of element 12 (Mg) are in the 3s orbital. Valence electrons are the electrons in the outermost energy level (or shell) of an atom. In the case of magnesium, which has an atomic number of 12, the electron configuration is 1s2 2s2 2p6 3s2. This means that magnesium has 2 electrons in its 3s orbital, which is its outermost energy level. The 3s orbital is located in the third energy level (or shell) of the magnesium atom. The 1s and 2s orbitals are located in the first and second energy levels, respectively, and the 2px and 2py orbitals are also located in the second energy level. Valence electrons are important because they are involved in chemical bonding and reactions. In the case of magnesium, having 2 valence electrons in its 3s orbital allows it to form chemical bonds with other atoms by either losing or sharing those electrons. Therefore, the valence electrons of element 12 (Mg) are in the 3s orbital, which is located in the outermost energy level of the atom.
Ajụjụ 14 Ripọtì
What quantity of electrons (in mole) is lost when one mole of iron (ll) ions is oxidized to iron (lll) ions?
Akọwa Nkọwa
When iron (II) ions (Fe²⁺) are oxidized to iron (III) ions (Fe³⁺), they lose one electron each. So, for one mole of Fe²⁺, there are 6.022 x 10²³ ions, and for each ion, one electron is lost during oxidation. Therefore, one mole of Fe²⁺ ions will lose one mole of electrons during oxidation. Therefore, the answer is 1 mole.
Ajụjụ 15 Ripọtì
An increase in the pressure of a gas results in a decrease in its
Akọwa Nkọwa
An increase in the pressure of a gas results in a decrease in its volume. This is known as Boyle's law, which states that at a constant temperature, the volume of a fixed amount of gas is inversely proportional to its pressure. In other words, as the pressure increases, the volume of the gas decreases and vice versa. This can be explained by the fact that increasing the pressure of a gas means that the gas particles are compressed closer together, resulting in less space between the particles and a smaller volume. Conversely, decreasing the pressure of a gas means that the gas particles are allowed to expand and take up more space, resulting in a larger volume.
Ajụjụ 17 Ripọtì
An acid is a substance which in the presence of water produces
Akọwa Nkọwa
An acid is a substance which in the presence of water produces hydroxonium ions. When an acid is dissolved in water, it dissociates into positively charged hydrogen ions (H+) and negatively charged ions. However, since the hydrogen ions are highly reactive, they immediately bond with water molecules to form hydroxonium ions (H3O+). This is why the presence of water is essential for acids to exhibit their acidic properties. The concentration of hydroxonium ions determines the acidity of a solution, and the more hydroxonium ions present, the stronger the acid. Salts, oxygen, effervescence, and hydrogen gas are not typically produced by the reaction between an acid and water.
Ajụjụ 18 Ripọtì
An atom 17 protons, 17 electrons and 18 neutrons has a mass number of
Akọwa Nkọwa
The mass number of an atom is the sum of the number of protons and the number of neutrons in the nucleus of the atom. Therefore, the mass number of the atom with 17 protons and 18 neutrons is: Mass number = number of protons + number of neutrons = 17 + 18 = 35 Hence, the correct option is 35.
Ajụjụ 19 Ripọtì
Which of the following is the relative molecular mass of a compound which has empirical formula CH2O? (H = 1; C = 12; O = 16)
Akọwa Nkọwa
Ajụjụ 20 Ripọtì
Lead and tin are the components of
Akọwa Nkọwa
Lead and tin are the components of "soft solder". Soft solder is a metal alloy that is used to join two metal pieces together, typically in electronics or plumbing applications. The most common composition of soft solder is 60% tin and 40% lead, although there are other compositions that can be used as well. The lead in soft solder helps to reduce the melting point of the alloy, making it easier to work with, while the tin provides strength and durability to the joint. Soft solder is called "soft" because it has a low melting point, usually around 180-190°C, which means it can be melted and applied with a soldering iron or torch. This makes it a useful material for a variety of applications where a strong, durable joint is needed, such as in electrical wiring or plumbing systems.
Ajụjụ 21 Ripọtì
Which of the following Group 1 elements has the highest ionization energy?
Akọwa Nkọwa
Ionization energy is the energy required to remove an electron from an atom. The higher the ionization energy, the more difficult it is to remove an electron. As we move down Group 1 of the periodic table, the atomic radius increases, and the outermost electron is farther away from the positively charged nucleus. As a result, the ionization energy decreases. Therefore, the element with the smallest atomic radius in Group 1, which is Li, will have the highest ionization energy. Therefore, the answer is: 3Li.
Ajụjụ 22 Ripọtì
The phenomenon observed when dust particles collide randomly in a beam of sunlight is known as
Akọwa Nkọwa
The phenomenon observed when dust particles collide randomly in a beam of sunlight is known as the Tyndall effect. When a beam of light passes through a transparent medium, such as air, the path of the light appears straight and unobstructed. However, when the light passes through a medium containing particles, such as dust or smoke, the path of the light becomes visible and appears as a beam. This phenomenon is known as the Tyndall effect. The Tyndall effect occurs because the particles in the medium scatter the light in all directions, making the beam of light visible. When the scattered light enters the eye, it creates a visible path that appears as a beam of light. In the case of dust particles in a beam of sunlight, the dust particles act as the scattering medium, causing the light to scatter in all directions and making the beam of light visible. This can be observed in everyday situations, such as when dust particles are present in a room and sunlight enters through a window. Therefore, the phenomenon observed when dust particles collide randomly in a beam of sunlight is known as the Tyndall effect, which is caused by the scattering of light by particles in a medium.
Ajụjụ 23 Ripọtì
The following oxides react with both acids and bases to form salts except
Akọwa Nkọwa
The oxide that does not react with both acids and bases to form salts is carbon (IV) oxide. Carbon (IV) oxide is a neutral oxide, meaning it does not have acidic or basic properties. It does not ionize in water to form H+ or OH- ions and therefore does not react with acids or bases to form salts. Zinc oxide, lead (II) oxide, aluminium oxide and tin (IV) oxide are all basic oxides, which means they react with acids to form salts and with bases to form complex salts or basic salts.
Ajụjụ 24 Ripọtì
What volume of oxygen at s.t.p would react with carbon to form 4.40g of CO2 according to the following equation? C(s) + O2(g) → CO2(g) [O = 16; C =12; 1 mole of a gas occupies 22.4dm3 at s.t.p]
Akọwa Nkọwa
The balanced chemical equation is C(s) + O2(g) → CO2(g). From the equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen to produce 1 mole of carbon dioxide. The molar mass of CO2 is 12 + 2(16) = 44 g/mol. Given that 4.40 g of CO2 is formed, the number of moles of CO2 can be calculated as: number of moles = mass / molar mass = 4.40 g / 44 g/mol = 0.1 mol Since 1 mole of oxygen reacts with 1 mole of carbon to produce 1 mole of CO2, the number of moles of oxygen required is also 0.1 mol. Using the ideal gas equation PV = nRT, we can find the volume of oxygen required at standard temperature and pressure (s.t.p), where P = 1 atm, V = ?, n = 0.1 mol, R = 0.0821 L.atm/K.mol, and T = 273 K: V = nRT / P = 0.1 mol x 0.0821 L.atm/K.mol x 273 K / 1 atm = 2.24 L 1 mole of any gas occupies 22.4 L at s.t.p, so the volume of oxygen required is 2.24 L, which is.
Ajụjụ 25 Ripọtì
Which of the following is a general method of preparing acids?
Akọwa Nkọwa
The general method of preparing acids is the reaction between an anhydride and water. An anhydride is a compound that has had water removed from it, usually by heating. When water is added to an anhydride, it undergoes a reaction called hydration, which results in the formation of an acid. This is a general method for preparing acids because many different types of anhydrides can be used, resulting in a wide variety of acids being produced.
Ajụjụ 26 Ripọtì
Ethene undergoes mainly addition reactions because it is
Akọwa Nkọwa
Ethene undergoes mainly addition reactions because it is unsaturated. This means that it contains a double bond between two carbon atoms, which is a reactive site for the addition of other molecules. In an addition reaction, the double bond is broken and new atoms or groups are added to the carbon atoms of the ethene molecule. This results in the formation of a new compound that contains all the atoms of the original reactants. Addition reactions are characteristic of unsaturated compounds like ethene, which have reactive double or triple bonds that can be easily broken to form new bonds.
Ajụjụ 28 Ripọtì
Alkanes react with the halogens mainly by
Akọwa Nkọwa
Alkanes react with halogens mainly by substitution. In this type of reaction, one or more atoms or groups in a molecule are replaced by other atoms or groups. In the case of alkanes and halogens, a halogen atom substitutes a hydrogen atom in the alkane molecule, forming a halogenoalkane. The substitution occurs due to the greater reactivity of halogens compared to the alkane's carbon-hydrogen bonds. The process usually requires energy to initiate, such as heat or light. The reaction mechanism involves a free radical mechanism where the halogen molecule breaks into two halogen radicals, which react with alkane molecules to form alkyl radicals and hydrogen halides. The alkyl radicals react with halogen molecules to form halogenoalkanes and regenerate the halogen radicals, which continue the reaction.
Ajụjụ 29 Ripọtì
Separation of mixture of solids by physical methods can be based on differences in the following except
Akọwa Nkọwa
Physical methods of separation involve the use of physical properties to separate mixtures of substances. Some physical properties that can be used for separation include melting point, solubility, particle size, molar mass, and magnetic property. However, molar mass is not typically used as a basis for separation of mixtures of solids by physical methods, as it is a property that relates to the composition of individual substances, rather than the mixture as a whole. Therefore, the answer is "molar mass."
Ajụjụ 30 Ripọtì
The common feature of reactions at the anode is that
Akọwa Nkọwa
The common feature of reactions at the anode is that oxidation is involved. This means that the substance being oxidized loses electrons, resulting in an increase in its oxidation state. An anode is the positively charged electrode in an electrochemical cell, where oxidation takes place. During the process, the anode becomes negatively charged as electrons are released, leaving behind positively charged ions. Hence, the correct answer is oxidation is involved.
Ajụjụ 31 Ripọtì
What is the most probable group of an element which is a soft, silvery white solid and reacts violently with water?
Akọwa Nkọwa
The element described is likely to be an alkali metal because it is a soft, silvery white solid and reacts violently with water. Alkali metals are located in Group 1 of the periodic table, so the answer is Group 1. Group 1 elements are known for their low densities, low melting points, and high reactivity, particularly with water.
Ajụjụ 32 Ripọtì
The reaction between alkanoic acids and alkanols in the presence of a mineral acid is known as
Akọwa Nkọwa
The reaction between alkanoic acids and alkanols in the presence of a mineral acid is known as esterification. In this reaction, an ester is formed as a product. The process involves the removal of a water molecule from the carboxylic acid and the alcohol, forming an ester linkage. The mineral acid acts as a catalyst and helps to speed up the reaction. This reaction is commonly used in the production of fragrances, flavors, and plastics.
Ajụjụ 33 Ripọtì
How many unpaired electrons are there in an atom of an element with the following electronic configuration? 1s22s22p6
Akọwa Nkọwa
An atom with the electronic configuration 1s22s22p6 has a completely filled valence shell, which means that all of its electrons are paired. Therefore, the number of unpaired electrons in this atom is zero (0).
Ajụjụ 34 Ripọtì
The by-product of the fermentation of sugar to ethanol is
Akọwa Nkọwa
The by-product of the fermentation of sugar to ethanol is carbon dioxide (CO2). During fermentation, sugar is converted into ethanol and carbon dioxide gas. The carbon dioxide gas is a by-product of the reaction and is responsible for the bubbling seen in the fermentation process.
Ajụjụ 35 Ripọtì
When chlorine is added to slaked lime, the product obtained is
Akọwa Nkọwa
When chlorine is added to slaked lime, the product obtained is bleaching powder. Bleaching powder is a pale yellow powder with the chemical formula CaOCl2. It is used as a bleaching agent, disinfectant, and for water treatment. Chlorine gas reacts with slaked lime (calcium hydroxide) to form calcium hypochlorite, which is the main component of bleaching powder. The reaction can be represented as follows: Ca(OH)2 + Cl2 → CaOCl2 + H2O Hence, the correct option is (a) bleaching powder.
Ajụjụ 36 Ripọtì
Which of the following when heated strongly in air will leave a metal as residue?
Ajụjụ 37 Ripọtì
The use of diamond in abrasives is due ti its
Akọwa Nkọwa
Diamond is used in abrasives due to its hardness. Hardness is the ability of a material to resist scratches and abrasions. Diamond is the hardest naturally occurring substance, meaning that it is extremely difficult to scratch or wear down. Therefore, it is an excellent abrasive material, and it is used in cutting, grinding, and polishing tools.
Ajụjụ 38 Ripọtì
The mass number of an element is the sum of its
Akọwa Nkọwa
The mass number of an element is the sum of its protons and neutrons. This is because protons and neutrons are found in the nucleus of an atom, and together they contribute most of the mass of an atom. Electrons, on the other hand, are found in the electron shells outside of the nucleus and have negligible mass. Therefore, the mass number is determined by the number of protons and neutrons in an atom, and it helps to identify different isotopes of the same element.
Ajụjụ 39 Ripọtì
Element X, with electronic configuration 2, 8, 2 and element Y with electronic configuration 2, 8, 7 are like to combine by
Akọwa Nkọwa
The electronic configuration of an element determines its reactivity and bonding behavior. Element X has two valence electrons in its outermost shell while Element Y has seven valence electrons. To achieve stability, Element X needs to lose its two valence electrons to form a cation with a +2 charge, while Element Y needs to gain one electron to form an anion with a -1 charge. This creates an electrostatic attraction between the oppositely charged ions, resulting in an ionic bond. Therefore, the most likely type of bond that Element X and Y will form is an electrovalent or ionic bond.
Ajụjụ 40 Ripọtì
In linear molecules, the bond angle is
Akọwa Nkọwa
In linear molecules, the bond angle is 180o. Linear molecules are those in which all the atoms attached to the central atom are in a straight line. The bond angle is the angle between the two chemical bonds involving the central atom. Since there is a straight line, the angle between the two bonds is 180o.
Ajụjụ 41 Ripọtì
Which of the substance lettered P to V in the equation below would be left on the filter paper if the reaction mixture were filtered? P (aq) + Q(aq) → V(s) + R(aq) + T(g)
Akọwa Nkọwa
The substance that would be left on the filter paper if the reaction mixture were filtered is V. The letter "s" in the formula V(s) means that it is a solid. During filtration, solids are separated from liquids. The other substances, P, Q, R, and T, are either in aqueous or gaseous form, and they would pass through the filter paper. Therefore, V is the only substance that would be left on the filter paper.
Ajụjụ 43 Ripọtì
Which of the following is an ore of aluminium?
Akọwa Nkọwa
Bauxite is an ore of aluminium. It is a reddish-brown rock that is mainly composed of aluminum hydroxide minerals. Bauxite is the primary source of aluminium metal, which is used in a variety of industrial applications due to its strength, lightness, and resistance to corrosion. Therefore, option D (Bauxite) is the correct answer.
Ajụjụ 45 Ripọtì
Radon is used as a tracer in medical research because it
Akọwa Nkọwa
Radon is used as a tracer in medical research because it is radioactive. Radon is a noble gas and has a complete valence shell, but its radioactivity makes it useful as a tracer. Radioactive substances can be traced and monitored through the body, which can be useful in medical research to study biological processes or diagnose certain medical conditions. Radon is also advantageous because it is a gas and can easily flow through small spaces, allowing it to be easily inhaled or ingested by the patient being studied.
Ajụjụ 46 Ripọtì
Which of the following ions will migrate to the cathode during electrolysis?
Akọwa Nkọwa
During electrolysis, positively charged ions (cations) migrate towards the negative electrode (cathode), whereas negatively charged ions (anions) migrate towards the positive electrode (anode). Therefore, the ion that will migrate to the cathode depends on the nature of the electrolyte solution and the electrode potential. Out of the options given, zinc ions (Zn²⁺) and tetraoxosulphate (VI) ions (SO₄²⁻) are both cations, which means they will migrate towards the cathode during electrolysis. Chloride ions (Cl⁻), sulphide ions (S²⁻), and trioxonitrate (V) ions (NO₃⁻) are all anions and will move towards the anode during electrolysis. Therefore, the answer to the question is either Zinc ions (Zn²⁺) or Tetraoxosulphate (VI) ions (SO₄²⁻), depending on the specific electrolyte solution and conditions of the electrolysis.
Ajụjụ 47 Ripọtì
How much heat will be liberated if 8g of hydrogen burns in excess oxygen according to the following equation? 2H2 + O2→ 2H2O,∆H = -571.7KJ (H = 1)
Akọwa Nkọwa
Ajụjụ 48 Ripọtì
If the atomic number of an element X is 11 and that of nitrogen is 7, the most likely formula of the nitride of X is
Ajụjụ 49 Ripọtì
(a)(i) List three characteristic properties of transition metals
(ii) 0.45g of a metal M was deposited when a current of 1.8 amperes was passed for 12.5 minutes through a solution containing M\(^{2+}\). Calculate the relative atomic mass of M. [1 Faraday = 96500 C]
(iii) Give the reason why copper-plated iron corrodes easily when the surface is scratched.
(b)(i) State the law of definite proportions (constant composition).
(ii) Describe in outline, an experimental procedure for determining the proportion of oxygen in a given sample of copper(II) oxide.
(iii) Write an equation to show how copper (II) oxide can be obtained directly from copper (II) trioxonitrate (V)
None
Akọwa Nkọwa
None
Ajụjụ 50 Ripọtì
(a) Mention three chemical properties of chlorine
(b) What type of reaction is represented by each of the following equations?
(i) Mg\(_{(s)}\) + 2HCI\(_{(aq)}\) --> Mg\(_2\)Cl\(_{2(aq)}\) + H\(_{2(g)}\)
(ii) Ag\(^+_{aq}\) + Cl\(^-\)\(_{(aq)}\) ----> AgCl\(_{(s)}\)
Akọwa Nkọwa
None
Ajụjụ 51 Ripọtì
(a) Give one example of a metal which:
(i) can displace hydrogen from cold water
(ii) at red-heat, reacts reversibly with steam
(iii) does not react with dilute hydrochloric acid
(b) When dry hydrogen was passed over lead (II) oxide, a greyish solid J was obtained.
(i) Identify J
(ii) What type of reaction was involved in the formation of J from lead (II) oxide?
Akọwa Nkọwa
None
Ajụjụ 52 Ripọtì
(a)(i) List two reactants for the laboratory preparation of ammonia
(ii) State three physical properties of ammonia
(iii) Describe in outline, the manufacture of ammonia by the Haber process.
(b) Write an equation in each case to show the:
(i) reaction between ammonia gas and heated copper (II) oxide
(ii) action of heat on ammonium trioxocarbonate (IV)
(c)(i) Which industrial process is used for convey ammonia to trioxonitrate (V) acid?
(ii) Give the reason why electropositive metals do not generally are off hydrogen with dilute trioxonitrate (V) acid
(d) Give one example in each case, to show how trioxonitrate (V) acid reacts generally with: (i) bases (ii) non-metals.
Ajụjụ 53 Ripọtì
(a) State two properties of alkalis
(b)(i) Why is tetraoxosulphate (VI) acid able to produce two types of salt?
(ii) Write an equation for the reactior involved on heating sodium trioxosulphate (IV) with hydrochloric acid.
Akọwa Nkọwa
None
Ajụjụ 54 Ripọtì
(a)(i) State the two main processes involved in the manufacture of oxygen from air
(ii) Name the type of chemical bonding which exists between oxygen atoms in a molecule of oxygen
(b) What term is used to describe the relationship between oxygen and ozone (O\(_3\))?
None
Akọwa Nkọwa
None
Ajụjụ 55 Ripọtì
(a)(i) Define entropy
(ii) What term is used to describe a reaction in which heat is absorbed from the surrounding?
(b) State two conditions that can lead to ineffective collisions during a chemical reaction.
Akọwa Nkọwa
None
Ajụjụ 56 Ripọtì
(a) State Gay Lussac's law of combining volumes
(b) Hydrogen reacts with oxygen according to the following equation;
2H\(_{2(g)}\) + O\(_{2(g)}\) ---> 2H\(_2\)O\(_{(g)}\). If 50cm\(^3\) of hydrogen were sparked with 30cm\(^{3}\) of oxygen, calculate the volume of unused oxygen after cooling to the initial temperature and pressure.
Ajụjụ 57 Ripọtì
(a)(i) State two general methods of preparing soluble salts.
(ii) Mention three pieces of apparatus required for determining the solubility of a salt at a given temperature.
(b) The solubilities of two salts represented as K and L were determined at various temperatures. The results are shown in the table below:
| Temperature (\(^o\)C) | 0 | 20 | 40 | 60 | 80 | 90 |
| Solubility of K (mol. dm\(^{-3}\)) | 0.38 | 0.46 | 0.54 | 0.62 | 0.69 | 0.73 |
| Solubility of L (mol. dm\(^{-3}\)) | 0.12 | 0.34 | 0.64 | 1.08 | 1.64 | 2.00 |
(i) Plot the solubility curves of K and L on the same graph. Use the curves to answer questions (ii) - (iv) below.
(ii) What is the solubility of K at 50°C?
(iii) At what temperature is the solubility of L equal to 1.0mol. dm\(^{-3}\)?
(iv) Over what temperature range is K more soluble that L?
(v) Given that the molar mass of L is 101g, determine whether a solution containing 3.4g of L per 250cm\(^3\) at 20°C is saturated or unsaturated.
Ajụjụ 58 Ripọtì
(a)(i) What is meant by cracking of petroleum fractions?
(ii) Write an equation for the laboratory preparation of ethene from ethanol.
(iii) Give one chemical test to distinguish between ethane and ethene.
(b)(i) Name the class of carbohydrates to which starch and cellulose belong.
(ii) What process is used for isolating ethanol from the other products of fermentation of sugar?
(iii) Name the organic product of the reaction between ethanol and sodium
(iv). Write the structural formula of 2-chloroethanol.
(c) State the reason why:
(i) benzene produces more soot than ethene on burning in excess air;
(ii) ethanoic acid has a higher boiling point than methanoic acid;
(iii) sodium chloride is used during the manufacture of soap.
(d) Give one use of: (i) ethyne (ii) coal (iii) carbon black
Akọwa Nkọwa
None
Ajụjụ 59 Ripọtì
Consider the reaction represented by the following Q equation: N\(_2\)O\(_{4(g)}\) \(\rightleftharpoons\) 2NO\(_{2(g)}\) \(\Delta\)H = +57.2KJmol\(^{-1}\)
(a) When is the reaction said to be at equilibrium?
(b) Mention two conditions that can favour the forward reaction
(c) Name the principle involved in (b) above.
Ajụjụ 60 Ripọtì
(a) List two products obtained when crude oil is refined
(b)(i) What is the general formula for alkanols?
(ii) State the type of reaction involved in the conversion of ethanol to ethanoic acid
(iii) Write an equation to show how ethanoic acid reacts with sodium trioxocarbonate (IV).
Akọwa Nkọwa
None
Ajụjụ 61 Ripọtì
(a) List two industrial uses of concentrated tetraoxosulphate (VI) acid
(b) The diagram below represents the set-up for the electrolysis of dilute tetraoxosulphate (VI) acid. Use it to answer Questions (i) to (iii).
(i) Which letter on the diagram represents the battery?
(ii) Write an equation for the reaction occurring at the cathode
(iii) What product does V represent?
Akọwa Nkọwa
None
Ajụjụ 62 Ripọtì
(a) List two properties of alpha particles.
(b) X is an element which exists as an isotopic mixture containing 90% of \(^{39}_{19} X\) and 10% of \(^{41}_{19}X\).
(i) How many neutrons are present in the isotope \(^{41}_{19}X\)?
(ii) Calculate the mean relative atomic mass of X.
None
Akọwa Nkọwa
None
