Ana loda....
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Latsa & Riƙe don Ja Shi Gabaɗaya |
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Danna nan don rufewa |
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Tambaya 1 Rahoto
(a) (i) List two diseases each of plants and animals caused by bacteria.
(ii) State three ways in which bacteria are useful.
(b) State three methods by which mosquitoes can be controlled and state the reason for each method
(c) Describe an experiment to demostrate the presence of bacteria under the finger nails
(a)(i) Two diseases each caused by bacteria
Plants: bacterial wilt of tomato; bacterial soft rot of yam/cassava (bacterial leaf blight of rice is also acceptable).
Animals (including man): tuberculosis; cholera (others: tetanus, gonorrhoea, anthrax, typhoid).
(a)(ii) Three ways in which bacteria are useful
(b) Three methods of controlling mosquitoes and the reason for each
| Method | Reason |
|---|---|
| Draining or filling stagnant water and clearing bushes | Removes the breeding sites where mosquitoes lay eggs and larvae develop |
| Spraying oil or insecticide on stagnant water surfaces | Suffocates the larvae and pupae / kills them, cutting the life cycle |
| Using insecticide-treated nets and closing houses | Prevents adult mosquitoes from biting and spreading the malaria parasite |
(c) Experiment to demonstrate the presence of bacteria under the finger nails
Bayanin Amsa
(a)(i) Two diseases each caused by bacteria
Plants: bacterial wilt of tomato; bacterial soft rot of yam/cassava (bacterial leaf blight of rice is also acceptable).
Animals (including man): tuberculosis; cholera (others: tetanus, gonorrhoea, anthrax, typhoid).
(a)(ii) Three ways in which bacteria are useful
(b) Three methods of controlling mosquitoes and the reason for each
| Method | Reason |
|---|---|
| Draining or filling stagnant water and clearing bushes | Removes the breeding sites where mosquitoes lay eggs and larvae develop |
| Spraying oil or insecticide on stagnant water surfaces | Suffocates the larvae and pupae / kills them, cutting the life cycle |
| Using insecticide-treated nets and closing houses | Prevents adult mosquitoes from biting and spreading the malaria parasite |
(c) Experiment to demonstrate the presence of bacteria under the finger nails
Tambaya 2 Rahoto
(a) Give a brief description of the characteristics of the Northern Guinea Savanna.
(b) Describe how you can estimate the density of a plant species using a quadrat.
(a) Characteristics of the Northern Guinea Savanna
(Any well-explained points describing the tall-grass-with-scattered-trees structure, seasonal drought, bush fires and drought adaptations are credited.)
(b) Estimating the density of a plant species using a quadrat
Bayanin Amsa
(a) Characteristics of the Northern Guinea Savanna
(Any well-explained points describing the tall-grass-with-scattered-trees structure, seasonal drought, bush fires and drought adaptations are credited.)
(b) Estimating the density of a plant species using a quadrat
Tambaya 3 Rahoto
(a) Describe the process of inhalation in man .
(b) Describe briefly the process of gaseous exchange in the shoo: system of flowering plants.
(c) Describe an experiment to demonstrate the effect of distilled water on mammalian red blood cell.
(a) Process of inhalation (breathing in) in man
(b) Gaseous exchange in the shoot system of flowering plants
In the shoot, gaseous exchange takes place mainly through the stomata of the leaves (and through lenticels in woody stems). Gases diffuse in and out through these openings and through the air spaces of the spongy mesophyll. By day, when photosynthesis is faster than respiration, carbon dioxide diffuses in and oxygen diffuses out. At night, when only respiration occurs, oxygen diffuses in and carbon dioxide diffuses out. The exchange is by simple diffusion along concentration gradients across the moist cell surfaces.
(c) Experiment to demonstrate the effect of distilled water on mammalian red blood cells
Bayanin Amsa
(a) Process of inhalation (breathing in) in man
(b) Gaseous exchange in the shoot system of flowering plants
In the shoot, gaseous exchange takes place mainly through the stomata of the leaves (and through lenticels in woody stems). Gases diffuse in and out through these openings and through the air spaces of the spongy mesophyll. By day, when photosynthesis is faster than respiration, carbon dioxide diffuses in and oxygen diffuses out. At night, when only respiration occurs, oxygen diffuses in and carbon dioxide diffuses out. The exchange is by simple diffusion along concentration gradients across the moist cell surfaces.
(c) Experiment to demonstrate the effect of distilled water on mammalian red blood cells
Tambaya 4 Rahoto
(a) List four characters which can be transmitted from parent to offspring in man.
(b) State two differences between mitosis and meiosis.
(c) Explain briefly the importance of meiosis and fertilization in the reproduction of organisms.
(d) In a monohybrid cross between a pure breeding plant that produces blue flowers and a pure breeding plant that produces white flowers, the F1 generation produced only blue flowers. By means of labelled cross diagrams, state the type of flowers you would expect if the Fl generation is (i) self-pollinated; (ii) cross-pollinated with a pure breeding plant that produces white flowers. Give reasons for your answers in (d) (i) and (ii).
(a) Four characters transmitted from parent to offspring in man
(Others: hair type/colour, ability to roll the tongue, sex.)
(b) Two differences between mitosis and meiosis
| Mitosis | Meiosis |
|---|---|
| Produces two daughter cells | Produces four daughter cells |
| Daughter cells are diploid (2n), same number as parent | Daughter cells are haploid (n), half the parent number |
(c) Importance of meiosis and fertilization
Meiosis halves the chromosome number to produce haploid gametes and, through crossing over and independent assortment, introduces variation among the offspring. Fertilization then restores the full diploid chromosome number when two gametes fuse, and combines genes from two parents, giving new gene combinations. Together they keep the chromosome number constant from generation to generation while ensuring genetic variation.
(d) Monohybrid cross
Let B = allele for blue flowers (dominant) and b = allele for white flowers (recessive). Parents: BB (blue) × bb (white). All F1 = Bb (blue).
(i) F1 self-pollinated: Bb × Bb
| B | b | |
|---|---|---|
| B | BB | Bb |
| b | Bb | bb |
Offspring: 3 blue (BB, Bb, Bb) : 1 white (bb), a ratio of 3 blue : 1 white. Reason: the heterozygotes each carry a hidden recessive b, so a quarter of the offspring are homozygous recessive and show white.
(ii) F1 cross-pollinated with pure white (Bb × bb)
| B | b | |
|---|---|---|
| b | Bb | bb |
| b | Bb | bb |
Offspring: 2 blue (Bb) : 2 white (bb), a ratio of 1 blue : 1 white (a test cross). Reason: half the gametes of the heterozygote carry b, so half the offspring are homozygous recessive white.
Bayanin Amsa
(a) Four characters transmitted from parent to offspring in man
(Others: hair type/colour, ability to roll the tongue, sex.)
(b) Two differences between mitosis and meiosis
| Mitosis | Meiosis |
|---|---|
| Produces two daughter cells | Produces four daughter cells |
| Daughter cells are diploid (2n), same number as parent | Daughter cells are haploid (n), half the parent number |
(c) Importance of meiosis and fertilization
Meiosis halves the chromosome number to produce haploid gametes and, through crossing over and independent assortment, introduces variation among the offspring. Fertilization then restores the full diploid chromosome number when two gametes fuse, and combines genes from two parents, giving new gene combinations. Together they keep the chromosome number constant from generation to generation while ensuring genetic variation.
(d) Monohybrid cross
Let B = allele for blue flowers (dominant) and b = allele for white flowers (recessive). Parents: BB (blue) × bb (white). All F1 = Bb (blue).
(i) F1 self-pollinated: Bb × Bb
| B | b | |
|---|---|---|
| B | BB | Bb |
| b | Bb | bb |
Offspring: 3 blue (BB, Bb, Bb) : 1 white (bb), a ratio of 3 blue : 1 white. Reason: the heterozygotes each carry a hidden recessive b, so a quarter of the offspring are homozygous recessive and show white.
(ii) F1 cross-pollinated with pure white (Bb × bb)
| B | b | |
|---|---|---|
| b | Bb | bb |
| b | Bb | bb |
Offspring: 2 blue (Bb) : 2 white (bb), a ratio of 1 blue : 1 white (a test cross). Reason: half the gametes of the heterozygote carry b, so half the offspring are homozygous recessive white.
Za ka so ka ci gaba da wannan aikin?