WAEC SSCE - Physics - 2019

Bayanin Amsa

The time rate of increase in velocity is called acceleration. Acceleration is a measure of how quickly an object changes its velocity, and it is calculated as the change in velocity per unit of time. Velocity is a vector quantity that describes an object's speed and direction of motion. If an object's velocity changes over time, either in magnitude (speed) or direction, it is said to be accelerating. The acceleration of an object is the rate at which its velocity changes, and it is a measure of the force acting on an object. Force is a vector quantity that describes the interaction between two objects that results in a change in motion. Force is proportional to acceleration, so a greater force will result in a greater acceleration. Momentum is a vector quantity that describes an object's mass and velocity. Momentum is conserved in an isolated system, meaning that the total momentum of the system remains constant, although the momentum of individual objects within the system may change. Speed is a scalar quantity that describes the magnitude of an object's velocity, without considering its direction. Speed is a measure of how quickly an object is moving, but it does not take into account changes in direction. Therefore, the time rate of increase in velocity is called acceleration.

Bayanin Amsa

The angle of refraction of a ray of light traveling from one medium to another can be calculated using Snell's law. Snell's law states that the ratio of the sine of the angle of incidence to the sine of the angle of refraction is equal to the ratio of the indices of refraction of the two media. Mathematically, this can be expressed as: sin θ_incidence / sin θ_refraction = n₁ / n₂ Where θ_incidence is the angle of incidence, θ_refraction is the angle of refraction, n₁ is the index of refraction of the first medium, and n₂ is the index of refraction of the second medium. Given the angle of incidence of 30° and the indices of refraction of 1.5 for the rectangular glass block and 1.0 for air, we can calculate the angle of refraction as follows: sin θ_incidence / sin θ_refraction = n₁ / n₂ sin 30° / sin θ_refraction = 1.5 / 1.0 sin θ_refraction = sin 30° / 1.5 θ_refraction = sin^-1(sin 30° / 1.5) = 19.47° Therefore, the angle of refraction of the ray of light traveling from the rectangular glass block into air is approximately 19.47°.

Bayanin Amsa

The resistance (R) of a wire is proportional to the temperature (T) in degrees Celsius. The equation of the resistance-temperature relationship is given by: R = R0 (1 + αT) Where R0 is the resistance at 0°C, α is the temperature coefficient of resistance and T is the temperature in degrees Celsius. To solve this problem, we can use the resistance-temperature relationship to find α, and then use it to find the temperature at the given resistance. First, we need to find the value of α. We can use the two resistance values given to set up two equations: R1 = R0 (1 + αT1) R2 = R0 (1 + αT2) where R1 and R2 are the resistances at temperatures T1 and T2, respectively. Substituting the given values: 3.5 = R0 (1 + α(0)) 10.52 = R0 (1 + α(100)) Solving for R0: 3.5 = R0 1 + α(100) = 10.52/R0 Rearranging the second equation: α = (10.52/R0 - 1)/100 Substituting R0 = 3.5: α = (10.52/3.5 - 1)/100 = 0.0032/°C Now we can use the resistance-temperature relationship to find the temperature at the given resistance: R = R0 (1 + αT) 7.5 = 3.5 (1 + 0.0032T) Solving for T: T = (7.5/3.5 - 1)/0.0032 = 57°C Therefore, the temperature of the wire when its resistance is 7.5Ω is 57°C. The correct option is 57 \(^o\)C.

Bayanin Amsa

A ripple tank is a scientific apparatus that can be used to demonstrate the behavior of waves. It produces waves on the surface of water that can be observed and studied. I. Reflection: When waves encounter a boundary or obstacle, they can bounce back or reflect. A ripple tank can be used to demonstrate reflection by placing a barrier in the path of the waves and observing how they bounce back. II. Refraction: Waves can also change direction or bend when they pass through a medium with a different density or refractive index. A ripple tank can demonstrate refraction by placing a block in the path of the waves and observing how they change direction as they pass through it. III. Diffraction: When waves encounter an obstacle with a small opening or gap, they can bend and spread out, creating a diffraction pattern. A ripple tank can demonstrate diffraction by creating waves with a single source and observing how they spread out as they pass through a gap or opening. Therefore, the correct answer is "I, II and III".

Bayanin Amsa

Out of the given options, the quantity that is a vector is momentum. A vector quantity has both magnitude and direction. Momentum is the product of mass and velocity, and it has both magnitude and direction. On the other hand, volume, energy, and speed are scalar quantities that have only magnitude but no direction associated with them.

Bayanin Amsa

The centripetal force acting on an electron moving in a circular path around the nucleus of an atom is given by the equation: F = (mv\(^2\))/r Where F is the centripetal force, m is the mass of the electron, v is the velocity of the electron, and r is the radius of the circular path. Substituting the given values into the equation, we have: F = (9.1 x 10\(^{-31}\) kg) x (2.0 x 10\(^6\) ms\(^{-1}\))\(^2\) / (6.1 x 10\(^{11}\) m) F = 6.0 x 10\(^{-8}\) N Therefore, the correct answer is: 6.0 x 10\(^{-8}\) N.

Bayanin Amsa

Bayanin Amsa

The area under a velocity-time graph represents the distance traveled by an object. Velocity is the rate of change of displacement with respect to time, which means it indicates how far an object has traveled in a specific amount of time. The area under the velocity-time graph shows the product of velocity and time, which is distance. To calculate the distance traveled, we need to find the area enclosed by the velocity-time graph, which may consist of different shapes depending on the motion of the object. For example, if the object is moving at a constant velocity, the area would be a rectangle. If the object is accelerating, the area would be a triangle or a trapezoid. Therefore, the correct answer is "distance".

Bayanin Amsa

Bayanin Amsa

We can use the formula for gravitational force between two masses: F = (G x m1 x m2)/r^2 where F = force of attraction G = gravitational constant m1 and m2 = masses of the bodies r = distance between the centers of the two bodies Plugging in the given values, we get: F = (6.67 x 10^-11 Nm^2/kg^2) x (3.0 kg) x (2.0 kg) / (0.50 m)^2 F = 1.6 x 10^-9 N Therefore, the force of attraction between the two bodies is 1.6 x 10^-9 N. Answer: 1.6 x 10^-9 N

Bayanin Amsa

In an elastic collision, both momentum and kinetic energy are conserved. Momentum is defined as the product of an object's mass and velocity, and it is a measure of an object's motion. In an elastic collision, the total momentum before the collision is equal to the total momentum after the collision. This means that the momentum of the objects involved in the collision is conserved. Kinetic energy is defined as the energy an object possesses due to its motion. In an elastic collision, the total kinetic energy before the collision is equal to the total kinetic energy after the collision. This means that the kinetic energy of the objects involved in the collision is conserved. In contrast, potential energy is a measure of an object's potential to do work, and it is related to an object's position or configuration. In an elastic collision, potential energy is not conserved because the objects change position or configuration during the collision. Therefore, in an elastic collision, momentum and kinetic energy are conserved, while potential energy is not conserved.

Bayanin Amsa

Bayanin Amsa

Placing a freshly demagnetized bar magnet in the East-West direction helps ensure that the molecular magnets within the magnet remain randomly arranged. This is because, in this position, the magnet is perpendicular to the Earth's magnetic field, which would otherwise affect the alignment of the molecular magnets. By keeping the molecular magnets in a random arrangement, the magnet can be effectively demagnetized and can be magnetized again in a desired direction.

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

An instrument used to measure relative humidity is the hygrometer. Hygrometers measure the amount of water vapor present in the air, which is an indicator of the air's relative humidity. Hygrometers can be mechanical or electronic, and they may measure relative humidity directly or calculate it from measurements of temperature and dew point.

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

The angular speed of the electron can be determined using the formula: ω = v / r where ω is the angular speed, v is the velocity of the electron, and r is the radius of the circular path. Substituting the given values, we get: ω = (2.0 x 10^6 m/s) / (6.1 x 10^11 m) ω = 3.28 x 10^(-5) rad/s Therefore, the angular speed of the electron is 3.28 x 10^(-5) rad/s. Hence, the correct option is: 3.28 x 10^16 rad s^(-1)

Bayanin Amsa

Connecting wires, earth wires, and fuses serve as safety devices in electrical circuits, while switches are not safety devices but rather control devices that allow the flow of current to be turned on or off. Therefore, the correct answer is switch.

Bayanin Amsa

The correct statement about a moving object is "At a steady velocity, the resultant force acting on it must be equal to zero." This means that when an object is moving at a constant speed in a straight line (i.e., at a steady velocity), the net force acting on it is zero. This does not mean that there are no forces acting on the object, but rather that the forces are balanced such that they cancel each other out. If the object were to accelerate or decelerate, there would be a net force acting on it. Similarly, air resistance can be a force acting on the object but it does not need to be zero for the object to move at a steady velocity, as long as it is balanced by other forces.

Bayanin Amsa

A capacitor is a device that is used for storing electric charges. It consists of two conductive plates separated by an insulating material called a dielectric. When a voltage is applied to the capacitor, electric charges are stored on the plates. The amount of charge that can be stored on a capacitor is proportional to the voltage applied and the capacitance of the capacitor, which is a measure of its ability to store electric charges. A transformer is a device that is used to change the voltage of an alternating current (AC) electrical supply. It works by using electromagnetic induction to transfer energy from one coil of wire to another. An ammeter is a device that is used to measure the current in an electrical circuit. It works by detecting the flow of electric charges through a conductor and measuring the resulting electric potential difference. A potentiometer is a device that is used to measure the potential difference (voltage) between two points in an electrical circuit. It works by comparing the voltage being measured to a reference voltage, and it can also be used to adjust the voltage in a circuit. Therefore, a capacitor is the device used for storing electric charges.

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

The change in the area of a rectangular piece of iron due to an increase in temperature can be calculated using the formula for linear expansion: ΔL = α * L * ΔT Where ΔL is the change in length, α is the linear expansivity, L is the original length, and ΔT is the change in temperature. The new length of the iron can be calculated by adding the change in length to the original length: L' = L + ΔL The new area of the iron can be calculated by using the new length and width: A' = L' * W First, the change in length of the iron can be calculated for both the length and the width: ΔL = α * L * ΔT = 1.2 x 10^-5 K^-1 * 4 cm * 100°C = 4.8 x 10^-3 cm L' = L + ΔL = 4 cm + 4.8 x 10^-3 cm = 4.0048 cm ΔL = α * L * ΔT = 1.2 x 10^-5 K^-1 * 3 cm * 100°C = 3.6 x 10^-3 cm W' = W + ΔL = 3 cm + 3.6 x 10^-3 cm = 3.0036 cm The new area of the iron can be calculated using the new length and width: A' = L' * W' = 4.0048 cm * 3.0036 cm = 12.0288 cm^2 Therefore, the new area of the metal after a temperature increase of 100°C is 12.0288 cm^2.

Bayanin Amsa

The instrument that can be used to compare the magnitudes of charges on two given bodies is the Gold-leaf electroscope. When a charged object is brought close to the electroscope, the charge is transferred to the metal leaves causing them to repel each other. By comparing the extent of separation of the leaves with a known charge, the magnitude of the charge on the given bodies can be determined. Electrophorus and ebonite rods are used for charging objects, and proof planes are used to transfer charge from one body to another.

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

Lenz's law states that the induced current in a coil always flows in a direction so as to oppose the change that causes it. For example, if there is a change in magnetic flux passing through a coil, it will induce an electromotive force (EMF) and a current will start flowing in the coil. This induced current will create a magnetic field that opposes the original change in magnetic flux. Lenz's law is a consequence of the law of conservation of energy and is a fundamental law in electromagnetism.

Bayanin Amsa

A neutral atom is an atom that has an equal number of protons and electrons. The protons are located in the nucleus of the atom, along with the neutrons, and the electrons occupy the space surrounding the nucleus. The number of protons in the nucleus of an atom determines the chemical element to which it belongs. A neutral atom has no overall charge, meaning that the positive charge of the protons is balanced by the negative charge of the electrons. Hence, the correct statement about a neutral atom is that the number of protons is equal to that of electrons.

Bayanin Amsa

Bayanin Amsa

The main idea of this question is to identify a type of wave that is not mechanical. Mechanical waves require a medium to travel through, such as a solid, liquid or gas. Sound waves and water waves are examples of mechanical waves. On the other hand, radio waves are a type of electromagnetic wave and do not require a medium to travel through. Therefore, the answer to the question is "Radio waves."

Bayanin Amsa

Bayanin Amsa

The formula for the speed of a wave is given by: v = λf where v is the speed of the wave, λ is the wavelength, and f is the frequency. We are given the frequency of the pulse as 9 Hz and the time it takes to travel a distance of 4.5 m as 0.6 s. We can use these values to calculate the speed of the pulse as follows: v = d/t = 4.5 m/0.6 s = 7.5 m/s Now, we can use the formula v = λf to calculate the wavelength of the pulse: λ = v/f = 7.5 m/s / 9 Hz = 0.83 m Therefore, the wavelength of the pulse is 0.83 m. Answer option (C) is correct.

Bayanin Amsa

The anomalous expansion of water refers to a phenomenon in which water expands instead of contracting as it cools below a certain temperature. This is a unique property of water, as most substances contract when they cool. The temperature range in which the anomalous expansion of water occurs is from 4°C to 0°C. As water cools below 4°C, it starts to contract, but as it approaches 0°C, it expands again. This means that at 0°C, water is actually less dense than it is at 4°C. Therefore, the answer is: 0°C to 4°C. This is the temperature range in which the anomalous expansion of water occurs.

Bayanin Amsa

The property that is not exhibited by sound waves is polarization. Polarization is a property of transverse waves, which are waves that vibrate perpendicular to the direction of their motion. Sound waves, on the other hand, are longitudinal waves, which means that they vibrate parallel to the direction of their motion. Since sound waves are not transverse, they cannot exhibit polarization. Diffraction, interference, and reflection are all properties of sound waves. Diffraction is the bending of sound waves around obstacles or through openings. Interference occurs when two or more sound waves interact with each other, either constructively or destructively. Reflection is the bouncing back of sound waves when they hit a surface. In summary, sound waves are longitudinal waves and cannot exhibit polarization, but they can exhibit other properties such as diffraction, interference, and reflection.

Bayanin Amsa

Bayanin Amsa

The graph shows the change in temperature of a solid as it is heated over time. At segment P, the temperature remains constant despite the application of heat. This is because the energy is being used to break the bonds between the molecules in the solid, rather than increasing their kinetic energy and temperature. This process is called melting, which is the transition from solid to liquid phase. At segment Q, the temperature again remains constant, but this time at a higher level than at segment P. This is because the energy is being used to break the bonds between the molecules in the liquid, rather than increasing their kinetic energy and temperature. This process is called boiling, which is the transition from liquid to gas phase. Therefore, the correct answer is "Melting and boiling".

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

The vacuum in a thermoflask reduces heat loss resulting from conduction and convection by creating a space with no air molecules between the inner and outer layers of the flask, which minimizes heat transfer through these processes. Additionally, the reflective surfaces of the inner layer further minimize heat loss by reflecting any radiation back into the flask.

Bayanin Amsa

The heat needed to change the temperature of 60g of ice at 0°C to 80°C can be calculated using the equation for heat transfer: Q = m * c * ΔT Where Q is the heat transferred, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature. First, the heat needed to melt the ice can be calculated using the specific latent heat of fusion: Q_fusion = m * L_f Where L_f is the specific latent heat of fusion. Q_fusion = 60g * 3.36 x 10^5 J/kg = 2.016 x 10^5 J Next, the heat needed to raise the temperature of the water from 0°C to 80°C can be calculated using the specific heat capacity of water: Q_heat = m * c * ΔT Q_heat = 60g * 4.2 x 10^3 J/kg/K * 80°C = 2.016 x 10^5 J The total heat needed to change the temperature of the ice to 80°C is the sum of the heat needed to melt the ice and the heat needed to raise the temperature of the water: Q = Q_fusion + Q_heat = 2.016 x 10^5 J + 2.016 x 10^5 J = 4.032 x 10^5 J = 40.32 kJ Therefore, the quantity of heat needed to change the temperature of 60g of ice at 0°C to 80°C is 40.32 kJ.

Bayanin Amsa

Bayanin Amsa

Bayanin Amsa

The nucleon number of an atom is the total number of protons and neutrons in its nucleus, while the proton number is the number of protons. Therefore, to determine the number of neutrons in an atom, we can subtract the proton number from the nucleon number. In this case, the nucleon number is 238 and the proton number is 92. Number of neutrons = Nucleon number - Proton number Number of neutrons = 238 - 92 Number of neutrons = 146 Therefore, the answer is: 146 neutrons.

Bayanin Amsa

(a) Diffusion is the movement of particles (atoms, molecules, or ions) from an area of high concentration to an area of low concentration. This process occurs naturally and spontaneously and is driven by the random motion of particles.

(b) Two factors that affect the rate of diffusion are:

(i) Temperature: As the temperature increases, the kinetic energy of the particles also increases, which leads to faster movement and increased collision frequency. This results in a higher rate of diffusion.

(ii) Concentration gradient: The greater the difference in concentration between two areas, the faster the rate of diffusion. This is because the concentration gradient provides a driving force for the movement of particles from high concentration to low concentration. Therefore, a steeper concentration gradient will result in a higher rate of diffusion.

Bayanin Amsa

(a)

(i) A - Metal surface, B - Collector electrode

(ii) A - To emit electrons when photons hit its surface, B - To collect the emitted electrons and create a current.

(iii) E represents the energy of the photon, hf represents the energy of the photon before it hits the metal surface, and Wo represents the work function or the minimum energy required to remove an electron from the metal surface.

(b)

Using Einstein's photoelectric equation, we can write:
hf = E + Wo
where hf is the energy of the photon, E is the kinetic energy of the emitted electron, and Wo is the work function.

We know that E = 1.97 eV and Wo = 1.32 eV. Converting to joules, we have:
E = 1.97 x 1.6 x 10^-19 J = 3.15 x 10^-19 J
Wo = 1.32 x 1.6 x 10^-19 J = 2.11 x 10^-19 J

Substituting these values into the equation:
hf = E + Wo = 3.15 x 10^-19 J + 2.11 x 10^-19 J = 5.26 x 10^-19 J

Finally, using the formula for the energy of a photon:
E = hf = hc/λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon. Solving for λ, we get:

λ = hc/E = (6.626 x 10^-34 J s x 3.0 x 10^8 m/s) / 5.26 x 10^-19 J = 3.77 x 10^-7 m

So, the frequency of the photon is:
f = c/λ = 3.0 x 10^8 m/s / 3.77 x 10^-7 m = 7.96 x 10^14 Hz

(c)

(i) The half-life of a radioactive element is the time taken for half of the radioactive nuclei to decay.

(ii) The graph of the relation N = Noe^-λt is an exponential decay curve. The half-life can be found by setting N = 0.5No and solving for t. This gives:

0.5No = Noe^-λt

Taking the natural logarithm of both sides, we get:

ln(0.5) = -λt1/2

where t1/2 is the half-life. Rearranging this equation, we get:

t1/2 = ln(2) / λ

The half-life is the time taken for the number of radioactive nuclei to reduce to half its initial value, as shown in the graph.

Bayanin Amsa

For the first part of the question:

1. To conduct the experiment, you will first need to place the retort stand on a laboratory stool and clamp the split cork to the stand.
2. Next, you will need to suspend the pendulum bob from the split cork using a piece of thread. The point of support, P, should be at a height of 100 cm above the floor, Q, and the center of the bob, A, should be at a height of 20 cm from the floor.
3. After suspending the pendulum, you will need to displace the bob slightly so that it oscillates in a horizontal plane.
4. Using the stopwatch, you will need to measure the time it takes for 20 complete oscillations and record this value as t.
5. To determine the period of oscillation, T, you can use the formula: T = t/20.
6. Repeat this procedure for four other values of y = 30 cm, 40 cm, 50 cm, and 60 cm, and determine T and T for each case.
7. Tabulate the results in a table.
8. Plot a graph of T on the vertical axis and y on the horizontal axis, starting both axes from the origin (0,0).
9. Determine the slope, s, of the graph and the intercept c on the vertical axis.
10. If in this experiment SR = c, you can calculate R by using the formula: R = SR/s.
11. To ensure accurate results, you should take two precautions: first, make sure that the length of the thread is kept constant throughout the experiment and second, ensure that the height H is kept constant as well.

For the second part of the question:

1. In a simple pendulum undergoing simple harmonic motion, the kinetic energy is maximum at the extremes of its motion, where the velocity is maximum. The acceleration is maximum at the equilibrium position, where it is equal to the maximum restoring force.
2. The period of a simple pendulum is given by the formula T = 2π√(m/k), where m is the mass of the object and k is the spring constant. In this case, the period is 4.0 s and the weight of the object is 120 N. Using the formula, we can calculate the spring constant as k = (4π^2)m/T^2 = (4π^2)(120 N)/(4.0 s)^2 = 180 N/m. The force per unit length of the spring is equal to the spring constant, so in this case it is equal to 180 N/m.

Bayanin Amsa

a)

(i) Atomic spectra refers to the range of electromagnetic radiation emitted or absorbed by atoms. It is a characteristic of the arrangement of electrons in atoms and the energy changes that occur within them.

(ii) Emission spectra refer to the range of electromagnetic radiation emitted by an atom when it transitions from a higher energy level to a lower energy level. Absorption spectra, on the other hand, refer to the range of electromagnetic radiation absorbed by an atom when it transitions from a lower energy level to a higher energy level.

b)

(i) The energy of the photon can be calculated using the equation E = hf, where E is energy, h is Planck's constant, and f is frequency. Thus, E = (6.6 x 10^-34 J s) x (3.0 x 10^8 Hz) / (3 - 1) = 4.4 x 10^-19 J.

(ii) The frequency of the photon is given by f = c / λ, where c is the speed of light and λ is the wavelength. Thus, f = (3.0 x 10^8 m/s) / (6.56 x 10^-7 m) = 4.58 x 10^14 Hz.

(iii) The wavelength of the photon can be calculated using the equation λ = c / f. Thus, λ = (3.0 x 10^8 m/s) / (4.58 x 10^14 Hz) = 6.56 x 10^-7 m.

c)

(i) Soft x-rays have lower energy and longer wavelength than hard x-rays. They are more easily absorbed by matter and are used in medical imaging. Hard x-rays, on the other hand, have higher energy and shorter wavelength and can penetrate denser materials, such as bone and metal.

(ii) The circuit symbol for a p-n junction diode is a triangle with a line at the base. The triangle represents the p-type material, and the line represents the n-type material.

(iii) Doping a semiconductor material involves intentionally adding impurities to change its electrical properties. This is done to create p-type or n-type semiconductors, which have different electron arrangements and conductivities. P-type semiconductors have an excess of holes and are created by doping with elements that have fewer valence electrons, while n-type semiconductors have an excess of electrons and are created by doping with elements that have more valence electrons.

Bayanin Amsa

The Earth's magnetic field is generated by the motion of molten iron in its core. The magnetic field at a given point on the Earth's surface is determined by the orientation and strength of this magnetic field.

Three magnetic elements that determine the Earth's magnetic field at a point are:

1. Magnetic declination: This is the angle between true north and magnetic north. It is determined by the position of the observer relative to the Earth's magnetic field.

2. Magnetic inclination: This is the angle between the Earth's magnetic field lines and the horizontal plane. It is determined by the latitude of the observer.

3. Magnetic intensity: This is the strength of the Earth's magnetic field at a given point. It is determined by the position of the observer relative to the Earth's magnetic field and the strength of the field generated by the Earth's core.

Together, these three magnetic elements give us a complete picture of the Earth's magnetic field at a given point. They are important for navigation and other applications that rely on the Earth's magnetic field.

Bayanin Amsa

(a) The principle of operation of fiber optics is based on the concept of total internal reflection. Light is carried through a thin, flexible fiber made of glass or plastic. The inner core of the fiber has a higher refractive index than the outer cladding, which has a lower refractive index. When light enters the fiber, it is reflected multiple times off the core-cladding interface, and travels along the fiber due to total internal reflection. This allows the light to be transmitted over long distances without significant loss of energy or degradation of the signal.

(b) Fiber optics has many applications in medicine, including:

1. Medical imaging: Fiber optic cables can be used to transmit images from inside the body to an external device. For example, endoscopes use fiber optics to provide high-quality images of the digestive or respiratory systems.

2. Illumination: Fiber optics can also be used to provide light in medical procedures, such as laparoscopic surgery. The light source is positioned outside the body, and the light is transmitted to the surgical site via a fiber optic cable. This allows for bright, even illumination without exposing the patient to direct light.

Bayanin Amsa

To solve this problem, we need to use the principle of conservation of energy, which states that the initial energy of the system is equal to the final energy of the system. Initially, the rubber band has potential energy stored in it due to its stretching, which is then transferred to the stone when it is released. This potential energy is converted into kinetic energy as the stone is propelled forward.

The potential energy stored in the rubber band can be calculated using the formula:

PE = 0.5 * k * x^2

where PE is the potential energy, k is the force constant of the rubber band, and x is the distance the rubber band is stretched.

In this case, PE = 0.5 * 200 N/m * (0.05 m)^2 = 0.5 J

Since the potential energy is converted to kinetic energy when the stone is released, we can equate the two and solve for the velocity of the stone:

PE = KE

0.5 * m * v^2 = 0.5 J

where m is the mass of the stone and v is its velocity.

Rearranging this equation, we get:

v = sqrt(2 * PE / m)

Substituting the values we have, we get:

v = sqrt(2 * 0.5 J / 0.02 kg) = 5 m/s

Therefore, the speed with which the stone leaves the catapult is 5 m/s.

Bayanin Amsa

(a)

(i) Force is a push or pull acting on an object that causes it to accelerate or deform. The SI unit of force is newton (N).

(ii) The two types of solid friction are static friction and kinetic friction.

(b)

(i)

The velocity-time graph for the journey is shown above. The horizontal axis represents time in seconds, and the vertical axis represents velocity in meters per second (m/s). The graph shows that the car was travelling at a constant velocity of 30 m/s for 20 seconds, then decelerated to a velocity of 18 m/s over a period of 6 seconds, maintained that velocity for 10 seconds, and finally came to rest over a period of 5 seconds.

(ii)

To calculate the deceleration during the last 5 seconds of the journey, we can use the formula:

a = (vf - vi) / t

where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time interval. In this case, the final velocity is 0 m/s, the initial velocity is 18 m/s, and the time interval is 5 seconds. Therefore:

a = (0 - 18) / 5 = -3.6 m/s2

The negative sign indicates that the acceleration is in the opposite direction to the initial velocity, which is consistent with deceleration.

(iii)

To calculate the total distance covered, we need to break the journey down into three parts:

1. The distance covered while travelling at a constant velocity of 30 m/s for 20 seconds.
2. The distance covered while decelerating from 30 m/s to 18 m/s over a period of 6 seconds, and then maintaining a constant velocity of 18 m/s for 10 seconds.
3. The distance covered while coming to rest over a period of 5 seconds.

For part 1, the distance covered is:

distance = velocity x time
distance = 30 m/s x 20 s = 600 m

For part 2, we need to calculate the average velocity over the 16-second period (6 seconds of deceleration + 10 seconds of constant velocity). The average velocity is:

average velocity = (initial velocity + final velocity) / 2
average velocity = (30 m/s + 18 m/s) / 2 = 24 m/s

The distance covered during this 16-second period is:

distance = velocity x time
distance = 24 m/s x 16 s = 384 m

For part 3, the distance covered is:

distance = (final velocity / 2) x time
distance = (0 m/s / 2)

Bayanin Amsa

The phenomena in which waves behave like a particle are collectively known as wave-particle duality. Here are three observable phenomena that demonstrate this concept:

1. Photoelectric effect: When light is shone on a metal surface, electrons are emitted from the surface. This can be explained by the idea that light behaves as a stream of particles called photons. These photons collide with the electrons in the metal, causing them to be ejected from the surface.

2. Compton scattering: When X-rays are scattered off a material, the wavelength of the scattered X-rays is longer than the incident X-rays. This can be explained by the idea that X-rays behave like particles, and when they collide with electrons in the material, they transfer some of their energy to the electrons, causing the X-rays to lose energy and their wavelength to increase.

3. Electron diffraction: When a beam of electrons is passed through a crystal, it produces a diffraction pattern that is similar to the pattern produced by a beam of light passing through a diffraction grating. This can be explained by the idea that electrons behave like waves, and their wavelength is related to their momentum. The crystal acts as a diffraction grating, causing the electrons to diffract and interfere with each other, producing the characteristic pattern.

Bayanin Amsa

a) Free electrons refer to electrons that are not bound to an atom and are therefore able to move freely through a material, such as a metal conductor. These electrons are responsible for the flow of electric current in conductors, as they can be easily influenced by an electric field and move in response to it.

b) Holes refer to the absence of an electron in an atom's valence shell, creating a positive charge carrier. In a semiconductor material, such as silicon or germanium, an electron can be excited out of its valence shell, leaving behind a hole. This hole can move through the material in response to an electric field, effectively behaving like a positively charged particle. Holes are essential to the functioning of semiconductor devices, such as diodes and transistors, and play a critical role in the control and modulation of electric current.

Bayanin Amsa

a)

1. (i) Newton's Law of Universal Gravitation states that every particle of matter in the universe attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between them. The force is along the line joining the particles and is given by F = G(m1m2)/r^2, where F is the force of attraction between the particles, m1 and m2 are the masses of the particles, r is the distance between them, and G is the universal gravitational constant.

2. (ii) Gravitational field is a region in space where a mass experiences a force due to the presence of another mass. The gravitational field strength at a point is the force per unit mass experienced by a small test mass placed at that point. It is given by g = F/m, where F is the force experienced by the test mass and m is the mass of the test mass.

b)

1. (i) At the surface of the Earth, the gravitational field strength is equal to the acceleration of free fall (g). Therefore, we have g = GMe/R^2, where Me is the mass of the Earth, R is the radius of the Earth, and G is the universal gravitational constant.

2. (ii) The relationship in 8(b)(i) holds under the assumptions that the Earth is a perfect sphere and has a uniform density distribution.

c)

Using the formula F = G(m1m2)/r^2, where m1 is the mass of the star, m2 is the mass of the Earth, r is the distance between them, and G is the universal gravitational constant, we have:

F = (6.67 x 10^-11 N m^2/kg^2) x (2.00 x 10^30 kg) x (5.98 x 10^24 kg) / (1.50 x 10^11 m)^2

F = 3.52 x 10^22 N

d)

1. (i) Escape velocity is the minimum velocity required by an object to escape the gravitational field of a planet or a star.

2. (ii) The acceleration of free fall (g) depends on the mass and distance of the object experiencing the gravitational force, while the universal gravitational constant (G) is a constant of nature that does not depend on the objects involved. Also, g is a measure of the strength of the gravitational field at a particular point, while G is a measure of the strength of the gravitational force between two objects separated by a distance.

Bayanin Amsa

F = 13.0cm
Table of value

Let 1cm represent5 units on the vertical axis and 1cm represent 5 units on the horizontal axis.

Minimum value of Z=Z0 ${}_0$ 

from the  graph = 60cm
Corresponding distance of X0 ${}_0$ 

= 30cm
Evaluate W

=  ½ (Z04+X02 $\frac{{𝑍}_0}{4}+\frac{{𝑋}_0}{2}$)

=  ½(6040+302 $\frac{60}{40}+\frac{30}{2}$

= ½(60+604 $\frac{60+60}{4}$ = ½1204 $\frac{120}{4}$

= ½(30) = 15

Precautions

- Coaxial arrangement of optional instruments/ray box, len and screen on a straight line.
- Avoided parallax error in reading metre rule.
- Lens kept uptight
- Repeated reading shown on table
- Surface of lens cleaned
- Noted/corrected/avoided zero error on metre rule.

(b)

i. 

ii. Features performing the same function