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Question 1 Report
(a)(i) List two elements which react with steam at red heat to produce hydrogen.
(ii) Explain why an aqueous solution of potassium bromide turned reddish brown on bubbling chlorine through it.
(iii) Write an equation for the reaction in (a)(ii).
(b)(i) Name two types of chemical industry that use limestone as raw material.
(ii) Give one example of hygroscopic substances.
(iii) Copy and complete the table below.
| Salt to be prepared | Starting material | Method of preparation |
| \(\mathrm{PbSO_4}\) | \(\mathrm{Pb(NO_3)_{2(ag)}}\) | - |
| \(\mathrm{KNO_3}\) | \(\mathrm{KOH}\) | Neutralization |
| \(\mathrm{CaCl_2}\) | \(\mathrm{CaCO_3}\) | - |
| \(\mathrm{FeCl_3}\) | \(\mathrm{Fe_{(s)}}\) | - |
| \(\mathrm{CuSO_4}\) | \(\mathrm{CuO}\) | - |
(c) In the contact process for the manufacture of tetraoxosulphate (VI) acid;
(i) State how sulphur (IV) oxide is obtained;
(ii) Write an equation for the reaction that takes place in the catalyst chamber;
(iii) Give the steps required to convert sulphur (VI) oxide to acid.
(d)(i) List two disadvantages of hard water.
(ii) Mention three methods which can be used to remove both permanent and temporary hardness in water at the same time.
(iii) State the role of alum and chlorine respectively in the purification of water for town supply.
(a)(i) Two elements that react with steam at red heat to give hydrogen: iron (Fe) and zinc (Zn). (Magnesium is also acceptable.)
(a)(ii) Why aqueous potassium bromide turns reddish-brown with chlorine
Chlorine is a stronger oxidising agent (higher in the halogen reactivity/electrochemical series) than bromine, so it displaces bromine from the bromide solution. The reddish-brown colour is the free bromine liberated.
(a)(iii) Equation
\[ \text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2 \](b)(i) Two industries that use limestone as raw material: the cement industry and the glass industry (iron and steel manufacture is also acceptable).
(b)(ii) One example of a hygroscopic substance: concentrated tetraoxosulphate(VI) acid (concentrated H\(_2\)SO\(_4\)). (Quicklime, CaO, is also acceptable.)
(b)(iii) Completed table
| Salt to be prepared | Starting material | Method of preparation |
|---|---|---|
| PbSO\(_4\) | Pb(NO\(_3\))\(_2\)(aq) | Precipitation (double decomposition, adding dilute H\(_2\)SO\(_4\)) |
| KNO\(_3\) | KOH | Neutralisation |
| CaCl\(_2\) | CaCO\(_3\) | Action of dilute hydrochloric acid on the trioxocarbonate(IV) |
| FeCl\(_3\) | Fe(s) | Direct combination (heating iron in dry chlorine) |
| CuSO\(_4\) | CuO | Neutralisation (action of dilute H\(_2\)SO\(_4\) on the base) |
(c) Contact process
(d)(i) Two disadvantages of hard water:
(d)(ii) Three methods that remove both permanent and temporary hardness at once: addition of washing soda (sodium trioxocarbonate(IV)), distillation, and the ion-exchange (permutit) method.
(d)(iii) Roles in town water purification:
Answer Details
(a)(i) Two elements that react with steam at red heat to give hydrogen: iron (Fe) and zinc (Zn). (Magnesium is also acceptable.)
(a)(ii) Why aqueous potassium bromide turns reddish-brown with chlorine
Chlorine is a stronger oxidising agent (higher in the halogen reactivity/electrochemical series) than bromine, so it displaces bromine from the bromide solution. The reddish-brown colour is the free bromine liberated.
(a)(iii) Equation
\[ \text{Cl}_2 + 2\text{KBr} \rightarrow 2\text{KCl} + \text{Br}_2 \](b)(i) Two industries that use limestone as raw material: the cement industry and the glass industry (iron and steel manufacture is also acceptable).
(b)(ii) One example of a hygroscopic substance: concentrated tetraoxosulphate(VI) acid (concentrated H\(_2\)SO\(_4\)). (Quicklime, CaO, is also acceptable.)
(b)(iii) Completed table
| Salt to be prepared | Starting material | Method of preparation |
|---|---|---|
| PbSO\(_4\) | Pb(NO\(_3\))\(_2\)(aq) | Precipitation (double decomposition, adding dilute H\(_2\)SO\(_4\)) |
| KNO\(_3\) | KOH | Neutralisation |
| CaCl\(_2\) | CaCO\(_3\) | Action of dilute hydrochloric acid on the trioxocarbonate(IV) |
| FeCl\(_3\) | Fe(s) | Direct combination (heating iron in dry chlorine) |
| CuSO\(_4\) | CuO | Neutralisation (action of dilute H\(_2\)SO\(_4\) on the base) |
(c) Contact process
(d)(i) Two disadvantages of hard water:
(d)(ii) Three methods that remove both permanent and temporary hardness at once: addition of washing soda (sodium trioxocarbonate(IV)), distillation, and the ion-exchange (permutit) method.
(d)(iii) Roles in town water purification:
Question 2 Report
(a)(i) Define allotropy.
(ii) Name the allotrope of carbon used in gas masks.
(iii) Mention two other elements which exhibit allotropy apart from carbon.
(b) List the products of each of the following reactions:
(i) Heating coal in the absence of air.
(ii) Burning of candle wax in plentiful supply of air
(c)(i) State the two properties of carbon (IV) oxide which make it useful in extinguishing fire.
(ii) Write an equation for the reaction of carbon (IV) oxide with lime water
(iii) Calculate the volume of oxygen that was in excess if 150cm\(^3\) of carbon (II) oxide was burnt in 80cm\(^3\) of oxygen according to the following equation: 2CO\(_{(g)}\) + O\(_{2(g)}\) \(\to\) 2CO\(_{2(g)}\).
(d)(i) State how nitrogen can be obtained from ammonia gas.
(ii) Name the gaseous fuels obtained when steam and air are passed over red hot coke.
(iii) Which of the fuels in (d)(ii) has the lower heating ability? Give reason for your answer.
Question 3 Report
(a) The letters R,S,T represent an alkene, an alkene and a terminal alkyne respectively. Which of R, S and T typically undergo(es) the following reactions?
(i) Addition reaction;
(ii) Combustion;
(iii) Substitution reaction.
(b)(i) Name the process by which an alkanol can be converted to an alkene.
(ii) Write the name and structural formula of the third member cf the alkanol series.
(iii) State what would be obtained if a primary alkanol reacted with excess acidified KMnO\(_4\) solution.
(c)(i) Give one chemical test for alkanoic acids.
(ii) Write an equation to show how methanoic acid reacts with ethanol in the presence of mineral acids.
(iii) What is the role of mineral acid in the reaction in (c) ii?
(d) In an experiment, cassava was pressure-cooked to release starch granules, followed by treatment with malt for about 2 hours at 55°C. Yeast was then added and the mixture was left for 2 days at 27°C. An organic product J and a gas H were obtained.
(i) Identify H
(ii) State the class of carbohydrates to which starch belongs and explain what happened to the starch during treatment with malt.
(iii) Draw a labelled diagram of a suitable set-up for obtaining a sample of J from the reaction mixture.
(a)
Taking R as an alkane, S as an alkene and T as a terminal alkyne:
(b)
(c)
The ester formed is ethyl methanoate.
(d)
Yeast subsequently ferments the sugar to ethanol, J, and carbon dioxide:
\[\mathrm{C_6H_{12}O_6 \xrightarrow{yeast} 2C_2H_5OH + 2CO_2}\]Distillation set-up for obtaining ethanol (J)
The fermented mixture is heated gently in a water bath. Ethanol distils over, condenses in the Liebig condenser and is collected as the distillate.
Answer Details
(a)
Taking R as an alkane, S as an alkene and T as a terminal alkyne:
(b)
(c)
The ester formed is ethyl methanoate.
(d)
Yeast subsequently ferments the sugar to ethanol, J, and carbon dioxide:
\[\mathrm{C_6H_{12}O_6 \xrightarrow{yeast} 2C_2H_5OH + 2CO_2}\]Distillation set-up for obtaining ethanol (J)
The fermented mixture is heated gently in a water bath. Ethanol distils over, condenses in the Liebig condenser and is collected as the distillate.
Question 4 Report
(a)(i) Give two differences between a conductor and an electrolyte.
(ii) State three applications of electrolysis.
(iii) Write equation for the reaction at each electrode when a dilute solution of sodium chloride is electrolysed using carbon electrodes.
(b)(i) What is an electrochemical cell?
(ii) Give two examples of primary cells.
(iii) Split the following equation into two balanced hall cell equations. Mte + Fe\(^{2+} \to Mg^{2+} + Fe\).
(c)(i) A current of 0.72 amperes was passed through dilute tetraoxosulphate (VI) acid for 3 hours 20 minutes. Calculate the quantity of electricity that was passed
(ii) If 1 dm\(^3\) of gas evolved at the cathode during the electrolysis of acidified water, what was the volume of gas evolved at the anode?
(d)(i) 20g of copper(II) oxide was warmed with 0.05 mole of tetraoxosulphate (VI) acid. Calculate the mass of copper (II) oxide that was in excess. The equation for the reaction: CuO\(_{(s)}\) + H\(_2\)SO\(_{4(aq)}\) ---> CuSO\(_{4(aq)}\) + H\(_2\)O\(_l\) [0 = 16 ; Cu = 64]
(ii) What type of reaction was involved in (d)(i)?
(a)(i) Differences between a conductor and an electrolyte
| Conductor (metallic) | Electrolyte |
|---|---|
| Conducts by flow of electrons | Conducts by movement of ions |
| Undergoes no chemical change while conducting | Is chemically decomposed while conducting |
| Conducts in the solid state | Conducts only when molten or in aqueous solution |
(a)(ii) Three applications of electrolysis
(a)(iii) Electrode reactions for dilute NaCl (carbon electrodes)
Cathode (reduction): \( 2\text{H}^+_{(aq)} + 2e^- \to \text{H}_{2(g)} \)
Anode (oxidation): \( 4\text{OH}^-_{(aq)} \to \text{O}_{2(g)} + 2\text{H}_2\text{O}_{(l)} + 4e^- \)
(Because the solution is dilute, oxygen, not chlorine, is discharged at the anode.)
(b)(i) An electrochemical cell is a device in which a redox reaction is used to convert chemical energy into electrical energy (or, in electrolysis, electrical energy into chemical energy).
(b)(ii) Primary cells: the Daniell cell and the dry Leclanche (zinc-carbon) cell.
(b)(iii) Half-cell equations for Mg + Fe2+ \(\to\) Mg2+ + Fe
Oxidation: \( \text{Mg} \to \text{Mg}^{2+} + 2e^- \)
Reduction: \( \text{Fe}^{2+} + 2e^- \to \text{Fe} \)
(c)(i) Quantity of electricity
\( t = 3\,\text{h}\,20\,\text{min} = 12000\ \text{s} \)
\[ Q = It = 0.72 \times 12000 = 8640\ \text{C} \]
(c)(ii) At the cathode H2 is evolved, at the anode O2; by the equation \(2\text{H}_2\text{O} \to 2\text{H}_2 + \text{O}_2\) the volume ratio H2:O2 is 2:1. So for 1 dm3 of H2 at the cathode, the anode gives 0.5 dm3 of O2.
(d)(i) Mass of CuO in excess
CuO + H2SO4 \(\to\) CuSO4 + H2O (1 : 1)
\[ n(\text{CuO}) = \frac{20}{64+16} = \frac{20}{80} = 0.25\ \text{mol} \]
Only 0.05 mol reacts (limited by acid), so excess CuO = \(0.25 - 0.05 = 0.20\) mol.
\[ \text{mass in excess} = 0.20 \times 80 = 16\ \text{g} \]
(d)(ii) A neutralization (acid-base) reaction.
Answer Details
(a)(i) Differences between a conductor and an electrolyte
| Conductor (metallic) | Electrolyte |
|---|---|
| Conducts by flow of electrons | Conducts by movement of ions |
| Undergoes no chemical change while conducting | Is chemically decomposed while conducting |
| Conducts in the solid state | Conducts only when molten or in aqueous solution |
(a)(ii) Three applications of electrolysis
(a)(iii) Electrode reactions for dilute NaCl (carbon electrodes)
Cathode (reduction): \( 2\text{H}^+_{(aq)} + 2e^- \to \text{H}_{2(g)} \)
Anode (oxidation): \( 4\text{OH}^-_{(aq)} \to \text{O}_{2(g)} + 2\text{H}_2\text{O}_{(l)} + 4e^- \)
(Because the solution is dilute, oxygen, not chlorine, is discharged at the anode.)
(b)(i) An electrochemical cell is a device in which a redox reaction is used to convert chemical energy into electrical energy (or, in electrolysis, electrical energy into chemical energy).
(b)(ii) Primary cells: the Daniell cell and the dry Leclanche (zinc-carbon) cell.
(b)(iii) Half-cell equations for Mg + Fe2+ \(\to\) Mg2+ + Fe
Oxidation: \( \text{Mg} \to \text{Mg}^{2+} + 2e^- \)
Reduction: \( \text{Fe}^{2+} + 2e^- \to \text{Fe} \)
(c)(i) Quantity of electricity
\( t = 3\,\text{h}\,20\,\text{min} = 12000\ \text{s} \)
\[ Q = It = 0.72 \times 12000 = 8640\ \text{C} \]
(c)(ii) At the cathode H2 is evolved, at the anode O2; by the equation \(2\text{H}_2\text{O} \to 2\text{H}_2 + \text{O}_2\) the volume ratio H2:O2 is 2:1. So for 1 dm3 of H2 at the cathode, the anode gives 0.5 dm3 of O2.
(d)(i) Mass of CuO in excess
CuO + H2SO4 \(\to\) CuSO4 + H2O (1 : 1)
\[ n(\text{CuO}) = \frac{20}{64+16} = \frac{20}{80} = 0.25\ \text{mol} \]
Only 0.05 mol reacts (limited by acid), so excess CuO = \(0.25 - 0.05 = 0.20\) mol.
\[ \text{mass in excess} = 0.20 \times 80 = 16\ \text{g} \]
(d)(ii) A neutralization (acid-base) reaction.
Question 5 Report
(a)(i) State three postulates of the kinetic theory of gases.
(ii) Draw a sketch to illustrate Boyle's law.
(iii) Explain what is meant by "absolute zero of temperature".
(b) Equal volumes of a gas X and oxygen are at the same pressure but temperature of 200 K and 800K respectively.
(i) Giving reason for your answer, state which of the gas samples contains the greater number of molecules.
(ii) If the mass of one molecule of the gas X is \(2.19 x 10^{-22}\) g, determine the molar mass of X. [Avogadro constant = \(6.02 x 10^{-23}\)]
(iii) Hence, state with reason which of X and oxygen will diffuse faster under the same conditions. [O = 16].
(c)(i) Mention two reaction conditions that can increase the yield of ammonia in the reaction represented by the following equation: \(N_{2(g)} + 3H_{2(g)} \rightleftharpoons 2NH_{3(g)}\ \Delta H = -46\text{kJmol}^{-1}\). Draw a labelled energy profile diagram for an endothermic reaction.
(iii) A solid W decomposes on heating according to the following equation: \(W_{(s)} \to Y_{(s)} + Z_{(g)}\) List two factors apart from temperature, which can affect the rate of the reaction.
(a)(i) Postulates of the kinetic theory of gases
(a)(ii) Boyle's law
At constant temperature, the pressure of a fixed mass of gas is inversely proportional to its volume: \(P \propto \frac{1}{V}\), or \(PV=\text{constant}\).
(a)(iii) Absolute zero
Absolute zero is the lowest theoretically attainable temperature, \(0\text{ K}\) or approximately \(-273^\circ\text{C}\), at which the volume of an ideal gas would theoretically become zero and molecular motion is at its minimum.
(b)(i)
Gas X contains the greater number of molecules. For equal volumes at the same pressure,
\[n=\frac{PV}{RT}\]
Hence, \(n\propto \frac{1}{T}\). Since X is at \(200\text{ K}\), whereas oxygen is at \(800\text{ K}\), X has more molecules.
(b)(ii)
Mass of one molecule of X \(=2.19\times10^{-22}\text{ g}\).
\[M=2.19\times10^{-22}\times6.02\times10^{23}\]
\[M=(2.19\times6.02)\times10=131.8\text{ g mol}^{-1}\]
Therefore, the molar mass of X is approximately \(132\text{ g mol}^{-1}\).
(b)(iii)
\[M(\mathrm{O_2})=2(16)=32\text{ g mol}^{-1}\]
By Graham's law, rate of diffusion is inversely proportional to the square root of molar mass. Since \(32<132\), oxygen diffuses faster than X.
(c)(i) Conditions for increasing the equilibrium yield of ammonia
Continuous removal of ammonia as it is formed also increases its yield.
(c)(ii) Labelled energy profile diagram for an endothermic reaction
(c)(iii)
Two factors, apart from temperature, which affect the rate of decomposition of W are:
Answer Details
(a)(i) Postulates of the kinetic theory of gases
(a)(ii) Boyle's law
At constant temperature, the pressure of a fixed mass of gas is inversely proportional to its volume: \(P \propto \frac{1}{V}\), or \(PV=\text{constant}\).
(a)(iii) Absolute zero
Absolute zero is the lowest theoretically attainable temperature, \(0\text{ K}\) or approximately \(-273^\circ\text{C}\), at which the volume of an ideal gas would theoretically become zero and molecular motion is at its minimum.
(b)(i)
Gas X contains the greater number of molecules. For equal volumes at the same pressure,
\[n=\frac{PV}{RT}\]
Hence, \(n\propto \frac{1}{T}\). Since X is at \(200\text{ K}\), whereas oxygen is at \(800\text{ K}\), X has more molecules.
(b)(ii)
Mass of one molecule of X \(=2.19\times10^{-22}\text{ g}\).
\[M=2.19\times10^{-22}\times6.02\times10^{23}\]
\[M=(2.19\times6.02)\times10=131.8\text{ g mol}^{-1}\]
Therefore, the molar mass of X is approximately \(132\text{ g mol}^{-1}\).
(b)(iii)
\[M(\mathrm{O_2})=2(16)=32\text{ g mol}^{-1}\]
By Graham's law, rate of diffusion is inversely proportional to the square root of molar mass. Since \(32<132\), oxygen diffuses faster than X.
(c)(i) Conditions for increasing the equilibrium yield of ammonia
Continuous removal of ammonia as it is formed also increases its yield.
(c)(ii) Labelled energy profile diagram for an endothermic reaction
(c)(iii)
Two factors, apart from temperature, which affect the rate of decomposition of W are:
Question 6 Report
a)(i) State three differences between covalent compounds and electrovalent compounds.
(ii) Two elements represented as K and L have atomic numbers of 12 and 8 respectively. Write their electronic structures and state the group to which each belongs in the Periodic Table.
(iii) If an alkali metal M exists naturally as the oxide, state with reason whether or not M can be extracted by reduction of the oxide with coke.
(b)(i) What is meant by the half-life of a radioactive element?
(ii) Mention the radioactive isotope used in dating archaeological specimens.
(iii) Balance the following equation and identify Q,
\(^{28}_{13}Al\) —> \(^{24}_{13}Si + \(^{0_1Q\)
(c)(i). Give three chemical properties of metals.
(ii) State two reasons why duralumin preferred to steel in aircraft manufacture.
(iii) What term is used to describe the ability of metals to be hammered into thin sheets?
(iv) Calculate the number of mole of electrons involved in the oxidation of 2.8g of iron filings to iron (II) ions. [Fe = 56].
(a)(i) Differences between covalent and electrovalent compounds
| Covalent compounds | Electrovalent (ionic) compounds |
|---|---|
| Formed by sharing of electrons | Formed by transfer of electrons |
| Usually have low melting/boiling points | Usually have high melting/boiling points |
| Do not conduct electricity (non-electrolytes) | Conduct electricity when molten or in solution (electrolytes) |
| Generally soluble in organic solvents | Generally soluble in water |
(a)(ii) Electronic structures and groups
(a)(iii) No. An alkali metal is very electropositive and reactive; it holds oxygen far more strongly than carbon does, so its oxide cannot be reduced by coke (carbon). Such metals are extracted by electrolysis of their molten salts.
(b)(i) Half-life: the time taken for half of the atoms (nuclei) in a given sample of a radioactive element to decay.
(b)(ii) Carbon-14 (\(^{14}_{6}\text{C}\)).
(b)(iii) Balancing mass and charge numbers, aluminium-28 decays by beta emission to silicon-28:
\[ ^{28}_{13}\text{Al} \to\ ^{28}_{14}\text{Si} + ^{\ \ 0}_{-1}\text{Q} \]
Q is a beta particle (electron), \(^{\ \ 0}_{-1}e\).
(c)(i) Three chemical properties of metals
(c)(ii) Duralumin is light (low density) yet strong, and it is resistant to corrosion.
(c)(iii) Malleability.
(c)(iv) Moles of electrons
\[ n(\text{Fe}) = \frac{2.8}{56} = 0.05\ \text{mol} \]
Fe \(\to\) Fe2+ + 2e-, so:
\[ n(e^-) = 2 \times 0.05 = 0.10\ \text{mol} \]
Answer Details
(a)(i) Differences between covalent and electrovalent compounds
| Covalent compounds | Electrovalent (ionic) compounds |
|---|---|
| Formed by sharing of electrons | Formed by transfer of electrons |
| Usually have low melting/boiling points | Usually have high melting/boiling points |
| Do not conduct electricity (non-electrolytes) | Conduct electricity when molten or in solution (electrolytes) |
| Generally soluble in organic solvents | Generally soluble in water |
(a)(ii) Electronic structures and groups
(a)(iii) No. An alkali metal is very electropositive and reactive; it holds oxygen far more strongly than carbon does, so its oxide cannot be reduced by coke (carbon). Such metals are extracted by electrolysis of their molten salts.
(b)(i) Half-life: the time taken for half of the atoms (nuclei) in a given sample of a radioactive element to decay.
(b)(ii) Carbon-14 (\(^{14}_{6}\text{C}\)).
(b)(iii) Balancing mass and charge numbers, aluminium-28 decays by beta emission to silicon-28:
\[ ^{28}_{13}\text{Al} \to\ ^{28}_{14}\text{Si} + ^{\ \ 0}_{-1}\text{Q} \]
Q is a beta particle (electron), \(^{\ \ 0}_{-1}e\).
(c)(i) Three chemical properties of metals
(c)(ii) Duralumin is light (low density) yet strong, and it is resistant to corrosion.
(c)(iii) Malleability.
(c)(iv) Moles of electrons
\[ n(\text{Fe}) = \frac{2.8}{56} = 0.05\ \text{mol} \]
Fe \(\to\) Fe2+ + 2e-, so:
\[ n(e^-) = 2 \times 0.05 = 0.10\ \text{mol} \]
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