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Question 1 Report
Fig. 1 shows a quality-control flow chart for a company making sodium chloride for saline solution. Rock salt is crushed and mixed with water. Insoluble sand is removed, then water is evaporated from the salt solution to obtain crystals. Samples from the final batch are checked by measuring melting range and by testing whether a solution of the crystals leaves a residue after evaporation. The company needs a pure compound because impurities could affect the medical use of the saline solution.
(a) Name the substance that passes through the filter in Fig. 1. [2]
(b) Give the reason why sand can be separated from sodium chloride solution by filtration. [2]
(c) Use particle ideas to describe what happens to water particles when the salt solution is evaporated. [4]
(d) Suggest two tests or observations that would show the final sodium chloride crystals are pure. [4]
Question 2 Report
Fig. 1 shows electron-shell diagrams prepared for a lesson on noble gases. Table 1 lists the number of electrons in atoms of helium, neon and argon. The teacher asks the class to use the diagrams to predict their chemical behaviour.
| element | number of electrons | period number |
|---|---|---|
| helium | 2 | 1 |
| neon | 10 | 2 |
| argon | 18 | 3 |
(a) Name the group containing neon. [1]
(b) What does the period number tell you about an atom? [1]
(c) Give one reason why argon is unreactive. [1]
(d) Complete the name of the element with 2 electrons: ______. [1]
The table below shows results from a student who added equal-sized pieces of magnesium, calcium and iron to separate samples of dilute acid. Fig. 1 shows the order of these metals in the student’s reactivity series. The volume of hydrogen was measured after 60 s.
| metal | volume of hydrogen after 60 s / cm3 |
|---|---|
| calcium | 48 |
| magnesium | 31 |
| iron | 4 |
(a) What gas is collected in this reaction? [1]
(b) Use Table 1 to name the metal with the fastest reaction. [1]
(c) Complete the word equation: magnesium + acid → magnesium ______ + hydrogen. [1]
(d) Suggest why the pieces of metal were made the same size. [1]
Noble gases
(a) Neon is in Group 0, also called Group 18 or the noble gases. [1]
(b) The period number gives the number of occupied electron shells in an atom. [1]
(c) Argon is unreactive because it has a full outer electron shell. [1]
(d) The element with two electrons is helium. [1]
Metals with acid
(a) The gas collected is hydrogen. [1]
(b) Calcium reacts fastest because it produces the largest hydrogen volume after the same 60 s, 48 cm3. [1]
(c) magnesium + acid → magnesium salt + hydrogen. [1]
(d) The pieces are the same size to control surface area and make the rate comparison fair. [1]
Noble gases
(a) Neon is in Group 0, also called Group 18 or the noble gases. [1]
(b) The period number gives the number of occupied electron shells in an atom. [1]
(c) Argon is unreactive because it has a full outer electron shell. [1]
(d) The element with two electrons is helium. [1]
Metals with acid
(a) The gas collected is hydrogen. [1]
(b) Calcium reacts fastest because it produces the largest hydrogen volume after the same 60 s, 48 cm3. [1]
(c) magnesium + acid → magnesium salt + hydrogen. [1]
(d) The pieces are the same size to control surface area and make the rate comparison fair. [1]
Question 3 Report
This reaction is used by a water-treatment company to remove ammonia from waste gas. Fig. 1 shows an energy profile for a reaction in which ammonia is oxidised. The products are lower in energy than the reactants.
(a) Name the type of energy change shown. [1]
(b) Give the name for the energy needed to start this reaction. [1]
(c) Use Fig. 1 to describe the energy changes as the reaction takes place. [3]
Question 4 Report
Fig. 1 shows a student using electrolysis to obtain copper from copper sulfate solution. The table records the mass of each electrode before and after a 20-minute run. The student uses graphite electrodes because graphite is a conductor and does not react easily.
| electrode | mass before / g | mass after / g |
|---|---|---|
| negative graphite electrode | 4.20 | 4.38 |
| positive graphite electrode | 4.22 | 4.22 |
(a) Use Table 1 to give the mass increase of the negative electrode. [1]
(b) Name the metal deposited on the negative electrode. [1]
(c) What particle moves to the negative electrode from the solution? [1]
(d) Give one reason why graphite is used for the electrodes. [1]
(e) Suggest why the negative electrode gains mass. [1]
(f) Complete the formula for copper(II) ions: Cu____. [1]
(a) \(4.38 - 4.20 = 0.18\), so the mass increase is 0.18 g. [1]
(b) The metal deposited on the negative electrode is copper. [1]
(c) Copper ions, \(\mathrm{Cu^{2+}}\), move through the solution to the negative electrode. Positive ions are attracted to the negative electrode. [1]
(d) Graphite is used because it conducts electricity. It is also acceptable to state that it is unreactive. [1]
(e) The negative electrode gains mass because copper is deposited on it. Copper ions gain electrons and become copper atoms. [1]
(f) The ion formula is \(\mathrm{Cu^{2+}}\), so the missing charge is 2+. [1]
(a) \(4.38 - 4.20 = 0.18\), so the mass increase is 0.18 g. [1]
(b) The metal deposited on the negative electrode is copper. [1]
(c) Copper ions, \(\mathrm{Cu^{2+}}\), move through the solution to the negative electrode. Positive ions are attracted to the negative electrode. [1]
(d) Graphite is used because it conducts electricity. It is also acceptable to state that it is unreactive. [1]
(e) The negative electrode gains mass because copper is deposited on it. Copper ions gain electrons and become copper atoms. [1]
(f) The ion formula is \(\mathrm{Cu^{2+}}\), so the missing charge is 2+. [1]
Question 5 Report
A student is given a printed inventory for a spacecraft water-recycling unit. The unit uses a small amount of silver compound to reduce microbial growth. Fig. 1 shows a simplified atom model for silver with shells represented by rings. The outer-shell count is not required. The inventory also includes an unknown silver ion detected in the water. The student uses proton and electron numbers to identify its charge.
(a) What is the atomic number of silver? [1]
(b) Give the number of electrons in a neutral silver atom. [1]
(c) Name the particle responsible for the negative charge in an atom. [1]
(d) Use 47 protons and 46 electrons to give the charge on the silver ion. [1]
(e) Complete the ion symbol: Ag___ . [1]
(f) Suggest why the silver ion and silver atom are the same element. [1]
(a) Silver has atomic number 47, equal to its proton number. [1]
(b) A neutral silver atom has 47 electrons, matching its 47 protons. [1]
(c) The negatively charged particle is an electron. [1]
(d) With 47 protons and 46 electrons, there is one more positive charge than negative charge. The ion has charge 1+. [1]
(e) The ion symbol is \(\mathrm{Ag^+}\). [1]
(f) The silver ion and silver atom are the same element because both have 47 protons. Forming an ion changes electrons, not proton number. [1]
(a) Silver has atomic number 47, equal to its proton number. [1]
(b) A neutral silver atom has 47 electrons, matching its 47 protons. [1]
(c) The negatively charged particle is an electron. [1]
(d) With 47 protons and 46 electrons, there is one more positive charge than negative charge. The ion has charge 1+. [1]
(e) The ion symbol is \(\mathrm{Ag^+}\). [1]
(f) The silver ion and silver atom are the same element because both have 47 protons. Forming an ion changes electrons, not proton number. [1]
Question 6 Report
The diagram shows a school laboratory model of ammonia manufacture. Dry nitrogen and dry hydrogen are mixed in the box before being passed over heated iron wool. A student compares the volume of ammonia collected in equal times. Table 1 gives the results when the gas mixture has different nitrogen to hydrogen volume ratios. The gases in the box are measured at the same temperature and pressure.
| Nitrogen : hydrogen volume ratio | Ammonia collected in 5 min / cm3 |
|---|---|
| 1 : 2 | 32 |
| 1 : 3 | 46 |
| 1 : 4 | 44 |
(a) Complete the word equation: nitrogen + hydrogen ⇌ ______. [1]
(b) Use Table 1 to give the ratio that produced most ammonia. [1]
(c) Name the element in the iron wool that acts as a catalyst. [1]
(d) Suggest why the gases are dried before entering the apparatus. [1]
A student investigates the effect of pressure on an equilibrium mixture for ammonia production using a sealed demonstration chamber. Fig. 1 shows a movable piston compressing nitrogen and hydrogen over an iron catalyst. The chamber is allowed to reach equilibrium before each sample is analysed. Table 1 shows the percentage of ammonia in the final gas mixture. Temperature is kept at 450 °C throughout.
| Pressure / atm | Ammonia in equilibrium mixture / % |
|---|---|
| 80 | 14 |
| 150 | 23 |
| 250 | 31 |
(a) Complete the balanced equation: N₂ + 3H₂ ⇌ ______. [1]
(b) Use Table 1 to state the effect of increasing pressure on ammonia percentage. [1]
(c) Explain this effect using the number of gas molecules in the equation. [2]
(d) Give one disadvantage of using very high pressure in an industrial plant. [1]
Ammonia manufacture model
(a) nitrogen + hydrogen \(\rightleftharpoons\) ammonia. [1]
(b) The ratio producing the most ammonia is 1 volume nitrogen : 3 volumes hydrogen, giving 46 cm3 in 5 minutes. [1]
(c) The catalyst element in the iron wool is iron. [1]
(d) The gases are dried to prevent water contaminating the product or affecting the reaction. [1]
Effect of pressure
(a) \(\text{N}_2+3\text{H}_2\rightleftharpoons\)\(2\text{NH}_3\). [1]
(b) The ammonia percentage increases as pressure increases. [1]
(c) The left side contains 4 gas molecules, or moles of gas [1], while the right side contains only 2. Higher pressure favours the side with fewer gas molecules, so it favours ammonia. [1]
(d) Very high pressure requires expensive compression and high energy use, or stronger costly equipment. [1]
Ammonia manufacture model
(a) nitrogen + hydrogen \(\rightleftharpoons\) ammonia. [1]
(b) The ratio producing the most ammonia is 1 volume nitrogen : 3 volumes hydrogen, giving 46 cm3 in 5 minutes. [1]
(c) The catalyst element in the iron wool is iron. [1]
(d) The gases are dried to prevent water contaminating the product or affecting the reaction. [1]
Effect of pressure
(a) \(\text{N}_2+3\text{H}_2\rightleftharpoons\)\(2\text{NH}_3\). [1]
(b) The ammonia percentage increases as pressure increases. [1]
(c) The left side contains 4 gas molecules, or moles of gas [1], while the right side contains only 2. Higher pressure favours the side with fewer gas molecules, so it favours ammonia. [1]
(d) Very high pressure requires expensive compression and high energy use, or stronger costly equipment. [1]
Question 7 Report
Fig. 1 shows a forensic scientist comparing a clear liquid from a damaged battery with a sodium chloride reference solution. Nitric acid and silver nitrate solution are used for both samples.
The battery liquid gives a cream precipitate. The reference gives a white precipitate. The cream precipitate dissolves only slightly in dilute ammonia solution.
(a) Name the halide ion in the battery liquid. [1]
(b) Give the formula of the cream precipitate. [1]
(c) Name the halide ion in the reference solution. [1]
(d) Suggest why nitric acid is used before silver nitrate solution. [1]
(e) Use the ammonia result to support the identification of the cream precipitate. [1]
Table 1 shows tests made on a white powder spilled from a delivery sack at a swimming-pool store. Fig. 1 shows the gas from the acid test being bubbled through limewater.
| test | observation |
|---|---|
| add dilute acid | fizzing |
| pass gas into limewater | limewater turns milky |
| add silver nitrate after nitric acid | no precipitate |
(a) Name the gas made in the first test. [1]
(b) Name the ion identified in the powder. [1]
(c) Complete the word equation: carbonate + acid → salt + water + ______. [1]
(d) Suggest why the silver nitrate result is useful. [1]
(e) Give the formula of the carbonate ion. [1]
Halide-ion tests
Carbonate-ion tests
Halide-ion tests
Carbonate-ion tests
Question 8 Report
A roadside worker uses solid sodium chloride to help melt ice on a footpath. Fig. 1 shows salt crystals spread over the icy surface.
(a) Name the state of sodium chloride before it dissolves. [1]
(b) Give the name of the mixture formed when sodium chloride dissolves in melted water. [1]
(c) Suggest why salt can make ice melt at a temperature below 0 degrees C. [2]
(d) Give one reason why workers should use only the amount of salt needed. [1]
(e) What happens to the arrangement of water particles when ice becomes liquid water? [1]
(a) Before dissolving, sodium chloride is a solid [1].
(b) The mixture made is a salt solution, or sodium chloride solution [1]. A solution is formed when a solute dissolves in a solvent.
(c) Dissolved salt lowers the freezing point of water [1]. Therefore, ice can change to liquid water at temperatures below \(0\degree\text{C}\) [1].
(d) Using only the necessary salt reduces waste, cost, or possible damage to plants and soil [1].
(e) On melting, water particles change from a regular, fixed arrangement to a random arrangement in which they can move past one another [1].
(a) Before dissolving, sodium chloride is a solid [1].
(b) The mixture made is a salt solution, or sodium chloride solution [1]. A solution is formed when a solute dissolves in a solvent.
(c) Dissolved salt lowers the freezing point of water [1]. Therefore, ice can change to liquid water at temperatures below \(0\degree\text{C}\) [1].
(d) Using only the necessary salt reduces waste, cost, or possible damage to plants and soil [1].
(e) On melting, water particles change from a regular, fixed arrangement to a random arrangement in which they can move past one another [1].
Question 9 Report
Fig. 1 shows a molecular model of iodine. At a coastal laboratory, iodine crystals are warmed gently to make iodine vapour for a test of starch in seaweed samples. The crystals change directly to a purple gas without forming a liquid. The scientist compares this change with melting sodium chloride.
(a) Name the type of bonding between the two iodine atoms. [1]
(b) What is the name of the change from solid iodine directly to gas? [1]
(c) Suggest why iodine has a low melting point compared with sodium chloride. [2]
(d) Give the number of iodine atoms in five iodine molecules. [1]
Fig. 1 shows a model of a water molecule. A water company uses activated carbon to remove some dissolved compounds from drinking water. The chemist reminds a student that water itself is a simple molecular substance, whereas the carbon filter has a giant structure. The water is boiled before a sterile sample is taken.
(a) What is the formula of water? [1]
(b) Name the type of bonding inside a water molecule. [1]
(c) Suggest why boiling water does not break the O-H bonds. [2]
(d) Give one property that makes activated carbon useful in a filter. [1]
Iodine
Water and activated carbon
Iodine
Water and activated carbon
Question 10 Report
The diagram shows a school laboratory flow chart for identifying ions in an unknown white solid. A student dissolves a small mass of the solid in water before splitting the solution between the tests.
The white precipitate dissolves in dilute ammonia. The warmed tube produces ammonia gas.
(a) Name the negative ion identified by the left-hand route. [1]
(b) Name the positive ion identified by the right-hand route. [1]
(c) Give the formula of the unknown compound. [1]
(d) Suggest why the solid is dissolved before testing. [1]
(e) Use the flow chart to name the reagent that is added before silver nitrate. [1]
A coach brings three unlabeled drinks powders to a sports-science laboratory. Powder A is known to contain sodium chloride. Powder B gives a yellow flame and a white precipitate when acidified silver nitrate is added. Powder C gives no flame colour but gives a white precipitate with barium chloride after acidification.
(a) Name the positive ion in powder B. [1]
(b) Name the negative ion in powder B. [1]
(c) Give the formula of the compound in powder B. [1]
(d) Name the negative ion in powder C. [1]
Unknown white solid
Drinks powders
Unknown white solid
Drinks powders
Question 11 Report
Fig. 1 shows a laboratory test in which chlorine water is shaken with colourless potassium bromide solution. A stopper is fitted before the test tube is shaken. A second tube contains bromine water and potassium chloride solution. The student uses the colour change to compare the reactivity of halogens.
(a) Name the type of reaction taking place when chlorine is added to potassium bromide solution. [1]
(b) Complete the ionic equation.
Cl2 + 2Br- → 2Cl- + ______ [1]
(c) Suggest the colour seen if bromine is formed. [1]
(d) Use the results to state which is more reactive, chlorine or bromine. [2]
Fig. 1 shows a sealed food packet flushed with nitrogen before it is closed. Nitrogen is not a Group 0 element, but the company is considering using argon instead. Both gases reduce the amount of oxygen around the food. The packet contains crisps made with vegetable oil.
(a) Name the Group 0 gas that could be used instead of nitrogen. [1]
(b) Suggest why oxygen is removed from the packet. [1]
(c) Give one property of argon that makes it appropriate for this use. [1]
(d) What name is given to reactions in which a substance combines with oxygen? [2]
Halogen displacement
Food packet
Halogen displacement
Food packet
Question 12 Report
Fig. 1 shows a particle model of carbon dioxide released when a carbonate tablet is placed in water. Each circle represents one molecule. A student compares samples containing different numbers of molecules. Avogadro constant is 6.02 × 1023 molecules per mole. The particle model is not drawn to scale.
(a) Name the element represented by the central atom in each carbon dioxide molecule. [1]
(b) Use the formula CO2 to calculate its Mr. Ar values are C = 12 and O = 16. [2]
(c) Use Avogadro constant to calculate the number of molecules in 0.50 mol of carbon dioxide. [2]
(d) Give the number of oxygen atoms in 0.50 mol of carbon dioxide. [1]
(a) The central atom in each carbon dioxide molecule is carbon. [1]
(b) \[M_r(\text{CO}_2)=12+(2\times16)=44\] [2]
(c) \[0.50\times6.02\times10^{23}=3.01\times10^{23}\] There are \(3.01\times10^{23}\) molecules in \(0.50\text{ mol}\) of carbon dioxide. [2]
(d) Each \(\text{CO}_2\) molecule has two oxygen atoms, so: \[2\times3.01\times10^{23}=6.02\times10^{23}\] Number of oxygen atoms = \(6.02\times10^{23}\). [1]
(a) The central atom in each carbon dioxide molecule is carbon. [1]
(b) \[M_r(\text{CO}_2)=12+(2\times16)=44\] [2]
(c) \[0.50\times6.02\times10^{23}=3.01\times10^{23}\] There are \(3.01\times10^{23}\) molecules in \(0.50\text{ mol}\) of carbon dioxide. [2]
(d) Each \(\text{CO}_2\) molecule has two oxygen atoms, so: \[2\times3.01\times10^{23}=6.02\times10^{23}\] Number of oxygen atoms = \(6.02\times10^{23}\). [1]
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