Consider the following half-cell reactions. Al(s) \(\to\) Al3+(aq) + 3e- Cu2+(aq) + 2e- \(\to\) Cu(s) The overall equation for the reaction is

2Al(s) + 3Cu2+(aq) \(\to\) 3Cu(s) + 2Al3+(aq)

Al(s) + Cu2+(aq) \(\to\) Al3+(aq) + Cu(s)

2Al(s) + Cu2+(aq) \(\to\) 2Al(aq) + Cu(s)

2Al(s) + 3Cu2+(aq) \(\to\) 3Cu(s) + 2Al3+(aq)

3Al(s) + 2Cu2+(aq) \(\to\) Cu(s) + 3Al3+(aq)

WAEC SSCE - Chemistry - 2016 (Objective)

Question 1 Report

The quality of electricity required to discharge 1 mole of univalent ion is

9600C

48250C

96500C Correct answer

193000C

Answer Details

The quality of electricity required to discharge 1 mole of univalent ion is 96500C. This quantity of electricity is known as Faraday's constant, which is equivalent to the charge on one mole of electrons (6.022 x 10^23 electrons). When one mole of an univalent ion is discharged, it means that one mole of electrons is transferred, and therefore, the charge required for this transfer is equal to the charge on one mole of electrons, which is 96500C.






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