WAEC SSCE - Physics - 2002 (Objective)

Question 1 Report

A converging lens of focal length 15cm forms a virtual image at a point 10cm from the lens. Calculate the distance of the object from the lens

10.00cm

6.00cm

5.00cm

1.50cm

Reflection Of Light At Plane And Curved Surfaces

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Question 2 Report

In the wave equation y = E_o, sin(299t - \(\pi\)), E_o represents the

amplitude

frequency

period

wavelength

Answer Details

In the given wave equation, y = E_o sin(299t - π), E_o represents the amplitude of the wave. The amplitude of a wave refers to the maximum displacement of a particle from its equilibrium position. In other words, it is the distance between the crest or trough of a wave and the equilibrium point. In this equation, the amplitude is given by E_o. Therefore, E_o represents the maximum displacement of the wave from its equilibrium position.

Read lesson note on Types Of Waves (WAEC)

Types Of Waves

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Question 3 Report

A solid weight 45N and 15N respectively in air and water. Determine the relative density of the solid

0.33

0.50

1.50

3.00

Answer Details

The relative density of a substance is defined as the ratio of its density to the density of a reference substance. In this case, the reference substance is water. When the solid is in air, it experiences a weight of 45N. This means that the weight of the displaced air is also 45N. Therefore, the density of the solid is: density of solid = weight of solid / volume of solid Since the volume of the solid is the same in air and in water, we can write: density of solid in air = weight of solid / volume of solid = weight of displaced air / volume of solid When the solid is in water, it experiences a weight of 15N. This means that the weight of the displaced water is 45N - 15N = 30N. Therefore, the density of the solid is: density of solid in water = weight of solid / volume of solid = weight of displaced water / volume of solid Now, the relative density of the solid is defined as the ratio of the density of the solid to the density of water: relative density of solid = density of solid / density of water We can substitute the expressions we obtained for the densities of the solid in air and in water: relative density of solid = (weight of displaced air / volume of solid) / (weight of displaced water / volume of solid) Simplifying this expression, we get: relative density of solid = weight of displaced air / weight of displaced water Substituting the values we obtained for the weights of displaced air and water, we get: relative density of solid = 45N / 30N = 1.5 Therefore, the relative density of the solid is 1.5. Answer: 1.50

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Motion

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Question 4 Report

Which of the following materials is used to control the rate of neutron production in a nuclear reactor?

boron rods

concrete shield

graphite rods

uranium rods

Answer Details

Boron rods are used to control the rate of neutron production in a nuclear reactor. Boron is a good neutron absorber and it is able to absorb neutrons without itself undergoing fission, so it is used to control the rate of fission in the reactor. By inserting or removing the boron rods from the reactor core, the amount of neutrons available to sustain the fission chain reaction can be controlled, and the reactor's power output can be adjusted accordingly.

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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Question 5 Report

Calculate the inductance L, of the coil in the circuit diagram shown above

3.8H

0.6H

0.4H

0.2H

Capacitors

Simple Harmonic Motion

Simple A.C Circuits

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Question 6 Report

Which of the following is usually used to cause fission in an atomic reactor?

Alpha particles

beta particles

electrons

Neutrons

Answer Details

Neutrons are usually used to cause fission in an atomic reactor. In a nuclear reactor, a neutron is fired at the nucleus of an atom of fuel, usually uranium-235 or plutonium-239. The neutron is absorbed by the nucleus, which becomes unstable and breaks apart into two smaller nuclei, releasing energy and more neutrons. These newly-released neutrons then go on to cause fission in other fuel nuclei, resulting in a chain reaction that releases a large amount of energy in the form of heat. This heat is then used to produce steam, which drives a turbine to generate electricity.

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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Question 7 Report

a load of mass120kg is raised vertically through a height of 2m in 30s by a machine whose efficiency is 100%. Calculate the power generated by the machine. [g = 10ms^-2]

60W

80W

100W

120W

Answer Details

Power is the rate at which work is done or energy is transferred. It is expressed in watts (W). In this question, we are asked to calculate the power generated by the machine which raised a load of mass 120kg through a height of 2m in 30s. The work done by the machine is given by the formula: work = force x distance In this case, the force is equal to the weight of the load, which is given by: force = mass x acceleration due to gravity force = 120kg x 10m/s² = 1200N The distance the load was raised is 2m. So, the work done by the machine is: work = force x distance = 1200N x 2m = 2400J The time taken to do the work is 30s. Therefore, the power generated by the machine is: power = work / time power = 2400J / 30s = 80W So, the correct answer is 80W.

Read lesson note on Friction (JAMB)

Friction

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Question 8 Report

Which of the following actions will not cause an increase in the frequency of a vibrating string?

increasing the tension of the string

decrease the mass per unit lengthof the string

decrease the length of the string

increasing the cross sectional area of the string

Answer Details

Increasing the cross-sectional area of the string will not cause an increase in the frequency of a vibrating string. This is because the frequency of a vibrating string is determined by its tension, mass per unit length, and length, but not by its cross-sectional area. Increasing the cross-sectional area of the string will only increase its volume and mass, but will not affect its tension or length, which are the factors that determine the frequency of the string. Therefore, this is the correct answer.

Read lesson note on Waves (JAMB)

Read lesson note on Motion (JAMB)

Waves

Motion

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Question 9 Report

Which of the following items can be used to compare the relative magnitudes of electric charges on two bodies?

ebonite rod

gold leaf electroscope

proof plane

the electrophorus

Answer Details

The gold leaf electroscope can be used to compare the relative magnitudes of electric charges on two bodies. An electroscope is a device used to detect the presence of an electric charge. When a charged object is brought near the top of the electroscope, the leaves inside the electroscope will either repel or attract each other, indicating the presence and sign of the charge. By using a charged object to charge the electroscope, and then bringing the object whose charge is being tested close to the top of the electroscope, the relative magnitude of the charges on the two objects can be compared. Therefore, the correct option is the "gold leaf electroscope".

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Question 10 Report

The silver coating on the inside of a vacuum flask reduces heat loss by

conduction

radiation

condensation

convention

Answer Details

The silver coating on the inside of a vacuum flask reduces heat loss by radiation. Heat can be transferred in three ways: conduction, convection, and radiation. In a vacuum flask, the space between the two walls of the flask creates a vacuum which reduces heat transfer by conduction and convection. However, radiation can still occur. The silver coating on the inside of the flask reflects radiant heat back to the liquid, reducing heat loss by radiation. Therefore, the silver coating on the inside of a vacuum flask reduces heat loss by radiation.

Read lesson note on Production And Propagation Of Waves (WAEC)

Read lesson note on Heat Transfer (JAMB)

Production And Propagation Of Waves

Heat Transfer

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Question 11 Report

The ice and steam points of a certain thermometer are -20^o and 100^o respectively. Calculate the Celsius temperature temperature corresponding to 70^o on the thermometer

84.0^o

75.0^o

64.0^o

58.0^o

Temperature And Its Measurement

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Question 12 Report

A transformer has 400 turns and 200 turns in the primary and secondary windings respectively. If the current in the primary and secondary windings are 3A and 5A respectively. calculate the efficiency of the transformer?

85.0%

83.3%

37.5%

30.0%

Capacitors

Simple A.C Circuits

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Question 13 Report

Which of the following actions will not lead to an increase in the induced e.m.f. in a coil of wire rotating between the poles of a magnet? Increasing the

strength of the magnet

number of turns in the coil

speed of location in the coil

gap between the poles of the magnet

Answer Details

Increasing the gap between the poles of the magnet will not lead to an increase in the induced e.m.f. in a coil of wire rotating between the poles of the magnet. This is because the magnetic field is weaker at a greater distance from the magnet, and therefore the rate of change of magnetic flux linking with the coil will be smaller. The induced e.m.f. is directly proportional to the rate of change of magnetic flux, so if the flux linkage decreases, the induced e.m.f. will also decrease. On the other hand, increasing the strength of the magnet, the number of turns in the coil, or the speed of rotation of the coil will all increase the rate of change of magnetic flux and hence increase the induced e.m.f.

Read lesson note on Electric Field (WAEC)

Electric Field

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Question 14 Report

The magnitude of the force required to make an object of mass, m move with speed, v in a circular of radius r is given by the expression

\(\frac{mr}{v}\)

\(\frac{mr^2}{v}\)

\(\frac{mv^2}{r}\)

\(\frac{mv}{r^2}\)

Answer Details

The expression that gives the magnitude of the force required to make an object of mass, m move with speed, v in a circular of radius r is given by the formula: \(\frac{mv^2}{r}\). This formula is known as the centripetal force formula. It states that the force required to keep an object moving in a circular path is directly proportional to the mass of the object, the square of its velocity and inversely proportional to the radius of the circular path. So, if we increase the mass of the object, the force required to keep it moving in a circular path will also increase. If we increase the velocity of the object, the force required will increase by a factor equal to the square of the velocity. Finally, if we increase the radius of the circular path, the force required will decrease.

Read lesson note on Scalars And Vectors (JAMB)

Read lesson note on Motion (JAMB)

Scalars And Vectors

Motion

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Question 15 Report

What type of motion does the skin of a 'talking' drum perform when it is struck with a drum stick?

Random

Rational

Translational

vibratory

Answer Details

The skin of a 'talking' drum performs vibratory motion when it is struck with a drumstick. This is because the drumstick striking the skin creates a disturbance that travels as a wave through the skin. The skin then vibrates back and forth in a periodic motion, producing sound waves in the air. This vibratory motion is what produces the unique sound of the 'talking' drum.

Read lesson note on Newton’s Laws Of Motion (WAEC)

Read lesson note on Motion (JAMB)

Newton’s Laws Of Motion

Motion

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Question 16 Report

In a compound microscope, the image formed by the objective lens is at a distance of 3.0cm from the eye lens. Calculate the focal length of the eye lens

0.3cm

2.7cm

3.4cm

8.3cm

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Question 17 Report

Which of the following statements correctly defines quantitatively the work done by a force? the product of the force and the distance moved

parallel to the line of action of the force from a reference point

perpendicular to the line of action of the force from a reference point

on a line through the reference point

by the object

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Question 18 Report

Local actions is normally prevented in a simple electric cell by

introducing an oxidizing agent in the acid

not drawing current continously for long period

amalgamating the surface of the zinc plate

using a porous pot to isolate the zinc plate from the acid

Answer Details

Local actions in a simple electric cell are caused by impurities on the surface of the zinc plate. When impurities on the surface of the zinc plate react with the acid, they form a small cell and cause the zinc to dissolve locally. To prevent local actions, the surface of the zinc plate is amalgamated (i.e. coated with mercury), which provides a uniform surface for the reaction with the acid. This prevents the formation of small cells and ensures that the current flows evenly through the cell. Therefore, the correct option is "amalgamating the surface of the zinc plate".

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Read lesson note on Gravitational Field (JAMB)

Electric Cells

Gravitational Field

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Question 19 Report

A pulse of a sound is transmitted from a ship and the reflection from the sea bed is recorded after 0.2s. Calculate the depth of the sea. [Take speed of sound in sea water = 1560ms^-1]

312.0m

156.0m

78.0m

31.2m

Answer Details

The time taken by the pulse of sound to travel from the ship to the sea bed and back to the ship is 0.2 seconds. This time includes the time taken by the pulse to travel from the ship to the sea bed and the time taken by the reflected pulse to travel back from the sea bed to the ship. Let's assume that the depth of the sea is 'd'. So, the total distance travelled by the sound is twice the depth of the sea or 2d. From the formula, distance = speed × time, we can write: 2d = speed of sound × 0.2 Substituting the value of speed of sound in sea water as 1560ms^-1, we get: 2d = 1560 × 0.2 2d = 312 Therefore, the depth of the sea is 312/2 = 156 meters. Hence, the correct option is: - 156.0m

Read lesson note on Sound Waves (WAEC)

Read lesson note on Speed And Velocity (WAEC)

Read lesson note on Propagation Of Sound Waves (JAMB)

Sound Waves

Speed And Velocity

Propagation Of Sound Waves

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Question 20 Report

An object is released from rest at a height of 25m. Calculate the time it takes to fall to the ground. [g = 10ms^-2]

25.00s

10.00s

2.50s

2.24s

Answer Details

The time taken for an object to fall freely from a height h can be calculated using the formula: t = sqrt(2h/g) Where t is the time taken, h is the height and g is the acceleration due to gravity. Substituting the values given, we get: t = sqrt(2 x 25 / 10) = sqrt(5) = 2.24s Therefore, the time it takes to fall to the ground is 2.24s. The correct option is (d).

Read lesson note on Gravitational Field (JAMB)

Gravitational Field

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Question 21 Report

A nuclide X is produced by bombarding a nitrogen(N) nucleus with an alpha(\alpha\) particle with the release of heavy hydrogen(D) nucleus as shown by the following nuclear equation, \(\alpha + ^{14}_{7}N \to ^p_qX + ^2_1D\). Determine the values of p and q in the equation

12 and 6

14 and 7

16 and 8

19 and 8

Structure Of The Atom (Nigeria Only)

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Question 22 Report

A boy travels 8 km eastward to a point B and then 6km northward to another point C. Determine the difference between the magnitude of displacement of the boy and distance travelled by him

2.0km

4.0km

10.0km

13.0km

Answer Details

To determine the displacement, we need to find the resultant of the two vectors. Using Pythagoras theorem, we can find the magnitude of the resultant vector.

Let's draw a diagram to represent the situation. Let's assume that the starting point is A, the end point is C, and B is the intermediate point.

From the diagram, we can see that the boy has travelled a total distance of 8km + 6km = 14km.

To find the displacement, we can use the Pythagorean theorem:

displacement² = (8km)² + (6km)²

displacement² = 64km² + 36km²

displacement² = 100km²

displacement = 10km

Therefore, the magnitude of the displacement is 10km.

The difference between the magnitude of displacement and distance travelled is:

difference = displacement - distance travelled

difference = 10km - 14km

difference = -4km

Since the displacement is greater than the distance travelled, the boy has some amount of displacement left after travelling the distance. Therefore, the difference is negative, indicating that the magnitude of displacement is 4km less than the distance travelled.

So the answer is -4.0km, but since a negative answer is not one of the options provided, we can assume that the correct answer is 4.0km.

Read lesson note on Rectilinear Acceleration (WAEC)

Read lesson note on Position, Distance And Displacement (WAEC)

Rectilinear Acceleration

Position, Distance And Displacement

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Question 23 Report

A man was moving round a circular path continuously for 4 minutes and covered the following distances in the times stated :
Distance (in metres) 200, 400, 600, 300
Time(in minutes) : 1, 2, 3, 4 respectively. Which of the following statements is correct about the motion of the man?

the man was moving without uniform velocity

the speed was changing constantly

the velocity was uniform

it was an instance of motion in which both speed and velocity are the same

Motion

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Question 24 Report

One common characteristics of solids, liquids and gasses is that?

all the three has fixed volume

their molecule have the same size

their molecules are always in motion

all the three have the same inter molecular forces

Answer Details

The correct answer is: their molecules are always in motion. Solids, liquids and gases are the three main states of matter, and they all share the characteristic that their molecules are always in motion. However, the motion of the molecules varies between the three states. In solids, the molecules are packed tightly together and vibrate around fixed positions. In liquids, the molecules have more freedom of movement and can slide past each other. In gases, the molecules move freely and randomly in all directions. None of the other options are correct. Solids and liquids have a fixed volume, but gases do not. The size of the molecules varies between the three states. The intermolecular forces also vary between the states; solids have the strongest intermolecular forces, followed by liquids and then gases.

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Read lesson note on Pressure (JAMB)

Read lesson note on Structure Of Matter And Kinetic Theory (JAMB)

Reflection Of Light At Plane And Curved Surfaces

Pressure

Structure Of Matter And Kinetic Theory

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Question 25 Report

The refractive index of a medium relative to air is 1.8. Calculate to the nearest degree, the critical angle for the medium

68^o

56^o

34^o

18^o

Answer Details

The critical angle is the angle of incidence where the angle of refraction is 90 degrees, and the refracted ray emerges along the boundary between the two media. It can be calculated using the formula: sin(critical angle) = 1/n where n is the refractive index of the medium relative to air. Therefore, sin(critical angle) = 1/1.8 = 0.5556 Using a scientific calculator or a trigonometric table, we can find that the angle whose sine is 0.5556 is approximately 34 degrees. Thus, the critical angle for the medium is 34^o.

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Refraction Of Light Through Plane And Curved Surfaces

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Question 26 Report

A block and tackle system has 6 pulleys. If the efficiency of the machine is 60%, determine its mechanical advantages

12.0

10.0

3.6

1.8

Work, Energy And Power

Simple Machines

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Question 27 Report

Water of mass 120g at 50oC is added to 200g of water at 10oC and the mixture is well stirred. Calculate the temperature of the mixture. [Neglect heat losses to the surrounding]

60^oC

40^oC

25^oC

10^oC

Answer Details

To solve this problem, we need to use the principle of conservation of energy, which states that energy cannot be created or destroyed, only transferred from one form to another. When the hot water is mixed with the cold water, heat energy flows from the hot water to the cold water until they reach the same temperature. We can use the equation: Q = mCΔT where Q is the amount of heat energy transferred, m is the mass of the water, C is the specific heat capacity of water, and ΔT is the change in temperature. Let's start by finding the amount of heat energy transferred from the hot water to the cold water: Q₁ = (0.12 kg) * (4186 J/kg°C) * (50°C - T) where T is the final temperature of the mixture. We use 4186 J/kg°C as the specific heat capacity of water. Similarly, the amount of heat energy gained by the cold water is: Q₂ = (0.2 kg) * (4186 J/kg°C) * (T - 10°C) Since energy is conserved, we know that Q₁ = Q₂. Therefore: (0.12 kg) * (4186 J/kg°C) * (50°C - T) = (0.2 kg) * (4186 J/kg°C) * (T - 10°C) Solving for T, we get: T = 25°C Therefore, the temperature of the mixture is 25°C. Option (C) is correct. Note: It is important to keep in mind that this calculation neglects any heat losses to the surroundings, which may affect the actual temperature of the mixture in a real-world scenario.

Read lesson note on Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

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Question 28 Report

The magnitude of the gravitational attraction between the earth and a particle is 40N. If the mass of the particle is 4kg. Calculate the magnitude of the gravitational field intensity of the earth on the particle

10.0N kg^-1

12.6N kg^-1

25.0N kg^-1

160.0N kg^-1

Answer Details

The gravitational attraction between two objects depends on their masses and the distance between them. The formula for calculating gravitational force is: F = G(m1m2)/r^2 Where F is the force, G is the gravitational constant, m1 and m2 are the masses of the objects, and r is the distance between them. We are given that the gravitational force between the earth and the particle is 40N, and the mass of the particle is 4kg. The mass of the earth is much larger than the mass of the particle, so we can assume that the distance between them is the radius of the earth. The gravitational field intensity at a point is defined as the force per unit mass experienced by a test particle placed at that point. So, the gravitational field intensity of the earth on the particle can be calculated by dividing the gravitational force by the mass of the particle: g = F/m Substituting the given values, we get: g = 40N/4kg g = 10.0N kg^-1 Therefore, the magnitude of the gravitational field intensity of the earth on the particle is 10.0N kg^-1. This is.

Read lesson note on Gravitational Field (JAMB)

Gravitational Field

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Question 29 Report

Two spheres of masses 100kg and 90kg respectively have their centres separated by a distance of 1.0m. Calculate the magnitude of the force of attraction between them. [G = 6.70 x 10^-11Nm^-2kg^-2]

6.70 x 10^-11N

6.70 x 10^-10N

6.03 x 10^-11N

6.03 x 10^-7N

Gravitational Field

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Question 30 Report

A freely-suspended magnet swinging in a horizontal plane comes to rest with its axis pointing approximately

north-south

south-west

north-east

south-east

Answer Details

A freely-suspended magnet will come to rest with its axis pointing approximately north-south. This is because the magnet aligns itself with the Earth's magnetic field, which runs approximately north-south at most locations on the planet. As the magnet swings, it experiences a torque due to the magnetic field, which causes it to align itself with the field and come to rest with its axis pointing in the direction of the field.

Read lesson note on Magnets And Magnetic Fields (JAMB)

Magnets And Magnetic Fields

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Question 31 Report

In the diagram above, AB represents a uniform rod of length 1.50m which is in equilibrium on a pivot at P, If AP = 40cm, calculate the mass of the rod. [g = 10ms^-2]

0.280kg

0.400kg

0.613kg

0.800kg

Equilibrium Of Forces

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Question 32 Report

The size of the hole of a pin hole camera is increased. The resultant image formed becomes

sharper

reduced in size

enlarged

blurred

Answer Details

When the size of the hole in a pinhole camera is increased, the image formed becomes blurred. This is because a larger hole allows more light to enter the camera and hit different parts of the film or image sensor, resulting in a less focused image. The pinhole camera works by allowing light to pass through a tiny aperture, which then projects an inverted image onto the opposite side of the camera. The smaller the aperture, the sharper the image, as the light is more focused and only travels in straight lines. By increasing the size of the hole, the light waves scatter more, resulting in a less clear image.

Read lesson note on Light (JAMB)

Light

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Question 33 Report

A spiral spring of natural length 30.0cm and force constant of 20Nm^-1 is compressed to 20.0cm. Calculate the energy stored in the spring

0.1J

1.0J

10.0J

100.0J

Answer Details

When a spring is compressed or stretched from its natural length, it stores potential energy. The potential energy stored in a spring is given by the formula: U = 1/2 kx^2 where U is the potential energy stored, k is the force constant of the spring and x is the displacement of the spring from its natural length. In this case, the natural length of the spring is 30.0 cm, and it is compressed to a length of 20.0 cm, so its displacement is: x = 30.0 cm - 20.0 cm = 10.0 cm = 0.1 m The force constant of the spring is given as 20 Nm^-1. Therefore, the potential energy stored in the spring is: U = 1/2 (20 Nm^-1) (0.1 m)^2 = 0.1 J Therefore, the energy stored in the spring is 0.1 J.

Read lesson note on Elasticity (JAMB)

Elasticity

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Question 34 Report

Three capacitors each of capacitance 18\(\mu F\) are connected in series. Calculate the effective capacitance of the capacitors

54.00\(\mu F\)

18.00\(\mu F\)

6.00\(\mu F\)

0.17\(\mu F\)

Answer Details

When capacitors are connected in series, the effective capacitance of the combination is given by: \[\frac{1}{C_{\text{eff}}}=\frac{1}{C_1}+\frac{1}{C_2}+...\frac{1}{C_n}\] where \(C_1\), \(C_2\)...\(C_n\) are the individual capacitances of the capacitors connected in series. In this case, we have three capacitors, each with capacitance 18\(\mu F\), connected in series. So we have: \[\frac{1}{C_{\text{eff}}}=\frac{1}{18\mu F}+\frac{1}{18\mu F}+\frac{1}{18\mu F}=\frac{3}{18\mu F}\] Simplifying the right-hand side, we get: \[\frac{1}{C_{\text{eff}}}=\frac{1}{6\mu F}\] Taking the reciprocal of both sides, we get: \[C_{\text{eff}}=6\mu F\] Therefore, the effective capacitance of the three capacitors in series is 6\(\mu F\). Hence, the answer is: 6.00\(\mu F\)

Read lesson note on Capacitors (JAMB)

Capacitors

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Question 35 Report

An object A is held in equilibrium as illustrated in the diagram above. Using the data on the diagram determine the magnitude, W of the weight of

23N

17N

7N

5N

Answer Details

To determine the weight of object A, we need to consider the forces acting on it. In this case, there are two forces acting on object A: the tension in the string and the weight of object A. The tension in the string is equal and opposite to the weight of the hanging object B. We know that the weight of object B is 17 N, so the tension in the string is also 17 N. Since object A is in equilibrium, the net force acting on it is zero. Therefore, the weight of object A must be equal and opposite to the tension in the string, which is also 17 N. Therefore, the magnitude of the weight of object A is 17 N. is the correct answer.

Read lesson note on Equilibrium Of Forces (JAMB)

Read lesson note on Equilibrium Of Forces (WAEC)

Equilibrium Of Forces

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Question 36 Report

Calculate the energy required to vapourise 50g of water initially at 80^oC.[specific heat capacity of water = 2260Jg^-1K^-1][specific latent heat of vaporisation of water = 2260Jg^-1]

113,000J

117,200J

234,400J

420,000J

Quantity Of Heat

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Question 37 Report

A slinky spring fixed at one end is placed horizontally on a table. The free end is displaced parallel to the table and then released. The resultimg wavelength is

transverse

longitudinal

stationary

electromagnetic

Answer Details

The type of wave produced when the slinky spring is displaced parallel to the table and released is a longitudinal wave. This is because the particles of the slinky move parallel to the direction of propagation of the wave. As the wave travels through the slinky, the coils of the spring compress and stretch alternately, forming areas of high and low pressure. These pressure changes travel along the length of the slinky, causing the wave to propagate. The wavelength of the wave will depend on the frequency of the wave and the speed of propagation, which in turn depend on the properties of the slinky, such as its mass per unit length and tension. The options "transverse", "stationary", and "electromagnetic" do not accurately describe the wave produced by the slinky spring in this scenario.

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Question 38 Report

If a radioactive atom emits a beta particle, Its mass number

increases by one

remains the same

decreases by one

increases by two

Answer Details

When a radioactive atom emits a beta particle, a neutron in the nucleus is converted into a proton and an electron. The electron is emitted as a beta particle, while the proton remains in the nucleus. Therefore, the atomic number increases by one, as the nucleus now has one more proton. The mass number, which is the sum of the protons and neutrons in the nucleus, remains the same, since the neutron is converted into a proton, and the mass of a proton is approximately equal to that of a neutron. So, the correct answer is: "remains the same".

Read lesson note on Structure Of The Atom (Nigeria Only) (WAEC)

Structure Of The Atom (Nigeria Only)

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Question 39 Report

Which of the following instruments is not a wind instrument?

clarinet

saxophone

trumpet

xylophone

Answer Details

The xylophone is not a wind instrument. It is a percussion instrument that produces sound when wooden bars are struck with mallets. In contrast, the clarinet, saxophone, and trumpet are all wind instruments that produce sound through the vibration of air within the instrument.

Read lesson note on Work, Energy & Power (JAMB)

Work, Energy & Power

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Question 40 Report

A radio wave has a wavelength of 150m. If the velocity of radio waves is free spaces is 3 x 10\(^8\) ms\(^{-1}\), calculate the frequency of the radio wave

4.50 x 10¹⁰Hz

5.0 x 10⁹Hz

4.5 x 10⁹Hz

2.0 x 10⁶Hz

Answer Details

The velocity of a wave is given by the product of its frequency and wavelength, i.e., velocity = frequency x wavelength Rearranging this equation, we get: frequency = velocity / wavelength Substituting the given values, we get: frequency = (3 x 10^8 m/s) / (150 m) frequency = 2 x 10^6 Hz Therefore, the frequency of the radio wave is 2.0 x 10^6 Hz. Answer: Option D.

Read lesson note on Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

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Question 41 Report

Which of the following actions will improve the efficiency of the pulley system?

reducing the mass of the pulley

increasing the friction force between the string and the pulley

increasing the mass per unit length of the string of the pulley

increasing the mass of the pulley

Answer Details

To improve the efficiency of the pulley system, the action required is to reduce the mass of the pulley. This is because the efficiency of a pulley system is determined by the mechanical advantage, which is the ratio of output force to input force. The output force is the weight of the load being lifted, while the input force is the force applied to the string to lift the load. When the mass of the pulley is reduced, the input force required to lift the load is also reduced, resulting in a higher mechanical advantage and hence, a more efficient pulley system. Increasing the friction force between the string and the pulley, increasing the mass per unit length of the string or increasing the mass of the pulley will have the opposite effect of reducing the mechanical advantage and therefore reducing the efficiency of the pulley system.

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Question 42 Report

The force between the molecules of a liquid in contact with that of a solid is

adhesive

cohesive

magnetic

repulsive

Answer Details

The force between the molecules of a liquid in contact with that of a solid is adhesive. Adhesive force refers to the attractive force between two different substances, such as the force that causes a liquid to "stick" to a solid surface. The adhesive force is due to intermolecular forces, such as hydrogen bonding, that occur between the molecules of the liquid and the molecules of the solid. This force is responsible for phenomena such as capillary action, in which a liquid will "climb" up a narrow tube, and wetting, in which a liquid will spread out over a surface.

Read lesson note on Electromagnetic Field (Part 2) (WAEC)

Read lesson note on Thermal Expansion (JAMB)

Electromagnetic Field (Part 2)

Thermal Expansion

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Question 43 Report

The lead-acid accumulator consists of a

lead as the positive electrode

lead ocide as the negative electrode

hydrochloric acid as the electrolyte

tetraoxosulphate(VI) acid as the electrolyte

Electric Cells

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Question 44 Report

A reservoir is filled with a liquid of density 2000kgm^-3. Calculate the depth at which the pressure in the liquid will equal to 9100Nm^-2 [g = 10ms^-2]

0.262m

0.455m

0.664m

0.819m

Answer Details

To calculate the depth at which the pressure in the liquid will equal to 9100Nm^-2, we can use the formula: pressure = density * gravity * height where density is the density of the liquid, gravity is the acceleration due to gravity, and height is the depth of the liquid. Rearranging this formula to solve for height, we get: height = pressure / (density * gravity) Substituting the given values, we get: height = 9100 / (2000 * 10) = 0.455m Therefore, the depth at which the pressure in the liquid will equal to 9100Nm^-2 is 0.455m. So, the answer is.

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Pressure

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Question 45 Report

When two notes of nearly equal frequencies are sounded together, a periodic rise and fall in sound intensity can be heard. This phenomenon can be called

beats

diffraction

overtones

resonance

Answer Details

The phenomenon described in the question is called "beats". Beats occur when two sound waves of nearly the same frequency interfere with each other. The interference causes the sound intensity to periodically increase and decrease, creating a pulsing or beating sound. The frequency of the beats is equal to the difference between the frequencies of the two sound waves.

Read lesson note on Sound Waves (WAEC)

Sound Waves

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Question 46 Report

An object is acted upon by a system of parallel forces causing the object to be in static equilibrium. Which of the following statements is not correct?

The resultant of the parallel force is zero

the algebraic sum of the moment of the forces is zero

all the parallel forces must be equal in magnitude and in direction

the sum of the forces in one direction must be equal to the sum of forces in the opposite direction

Equilibrium Of Forces

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Question 47 Report

A car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration

1.25ms^-2

1.60ms^-2

4.00ms^-2

8.00ms^-2

Answer Details

The acceleration of an object is given by the formula: a = (v - u) / t where, a = acceleration v = final velocity u = initial velocity t = time Here, the car starts from rest, which means its initial velocity (u) is zero. The car covers a distance of 80m in a time of 10s. We can use the formula of distance to find the final velocity of the car. s = ut + (1/2)at^2 where, s = distance u = initial velocity t = time a = acceleration As the car starts from rest, its initial velocity is zero, so we can simplify the equation to: s = (1/2)at^2 Rearranging the formula to get acceleration (a), we have: a = 2s / t^2 Substituting the given values, we get: a = 2 x 80m / (10s)^2 = 1.6ms^-2 Therefore, the magnitude of the car's acceleration is 1.6ms^-2. The answer is.

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Motion

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Question 48 Report

In a model of the hydrogen atom, the energy levels W_n are given by the formula W_n = -\(\frac{R}{n^2}\), where n is an integer and R is a constant. Determine the energy released in the transition from n = 3 to n = 2.

\(\frac{R}{5}\)

-\(\frac{R}{4}\)

\(\frac{5R}{36}\)

\(\frac{-5R}{36}\)

Structure Of The Atom (Nigeria Only)

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