JAMB UTME - Physics - 1992 | Green Bridge CBT

Question 1 Report

PQRS is rectangular cell with PQ perpendicular to the magnetic field as shown above. If a current flows in the the direction PQRS in what direction will the coil move

Upwards

Downwards

TOwards The North Pole

Towards The South Pole

Electric Field

Electromagnetic Field (Part 2)

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Question 2 Report

When an object is placed very close to the pole of a concave mirror, the virtual image obtained is

diminished and upright

diminished and inverted

enlarged and inverted

enlarged and upright

Answer Details

When an object is placed very close to the pole of a concave mirror, the virtual image obtained is enlarged and upright. A concave mirror is a mirror that curves inward, and the focal point of the mirror is the point at which all light rays parallel to the axis of the mirror converge. When an object is placed very close to the pole of the mirror, the light rays from the object diverge and do not converge at the focal point. However, the diverging rays appear to originate from a virtual object behind the mirror, and these rays converge at the focal point. As a result, a virtual, enlarged and upright image of the object is formed.

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Reflection Of Light At Plane And Curved Surfaces

Refraction Of Light Through Plane And Curved Surfaces

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Question 3 Report

If the refractive index of a medium in air is 2.0, what is the critical angle for this medium?

30o

42o

45o

50o

Answer Details

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees, meaning that the refracted ray travels along the surface of the medium rather than entering it. The formula for calculating the critical angle is: critical angle = sin⁻¹ (1/n) where n is the refractive index of the medium. In this question, the refractive index of the medium in air is given as 2.0. Plugging this value into the formula, we get: critical angle = sin⁻¹ (1/2.0) Using a calculator, we can find that sin⁻¹ (1/2.0) is approximately 30 degrees. Therefore, the correct option is 30o.

Read lesson note on Refraction Of Light Through Plane And Curved Surfaces (JAMB)

Refraction Of Light Through Plane And Curved Surfaces

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Question 4 Report

In alternating current theory, the units of impedance, r.m.s. voltage and resonance frequency are respectively equal to

volt, ampere and hertz

ohms, volt and hertz

watt, ohms and radian

ohms, hertz and joule

Answer Details

In alternating current (AC) theory, impedance is measured in ohms, r.m.s. voltage is measured in volts, and resonance frequency is measured in hertz. Impedance is the opposition to the flow of electric current in an AC circuit, similar to resistance in a DC circuit. R.m.s. voltage is the equivalent steady DC voltage that produces the same heating effect as the AC voltage. Resonance frequency is the frequency at which an AC circuit exhibits the greatest impedance. Therefore, the correct option is: ohms, volt and hertz.

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Question 5 Report

A stone, Q is thrown with velocity U at an angle of 75o to the horizontal. Another stone R is thrown with the same velocity U but with an angle of 15o to the horizontal. The ranges covered by the stones will be

greater for Q

greater for R

the same for Q and R

greater for the heavier of the two stones

Answer Details

Range =

\frac{U^{2} s i n 2 θ}{g}

RangeQ = $\frac{U^{2} s i n 150}{g}$

RangeR = $\frac{U^{2} s i n 30}{g}$

Since, sin30o = sin150o

therefore, RQ = RR

View Answer

Question 6 Report

What is the least possible error in using a rule graduated in centimeters?

0.1cm

0.5cm

1.0cm

2.0cm

Answer Details

The least count of a measuring instrument is the smallest measurement that can be made with it. The least count of a rule is the distance between two adjacent graduations. A rule graduated in centimeters usually has the smallest graduation of 1 mm or 0.1 cm. Therefore, the least possible error in using a rule graduated in centimeters is 0.1 cm.

Read lesson note on Measurements And Units (JAMB)

Measurements And Units

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Question 7 Report

The diagram above shows a meter bridge in which two of thee arms contain resistances R and 2Ω. A balance point is obtained at 60cm from the left end , calculate the value of R

1.2Ω

1.3Ω

3.0Ω

6.0Ω

Capacitors

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Question 8 Report

Which of the following statements is CORRECT about a long-sighted boy who does not put on glasses?

He cannot see distant objects clearly

Rays of light from a close object are focused in front of his retina

His eye ball is too long

Parallel rays of light are focused behind his retina

Answer Details

The parallel ray is not before the retina, but behind the retina for a long sighted person.

Read lesson note on Description Property Of Fields (WAEC)

Description Property Of Fields

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Question 9 Report

A platinum resistance thermometer wire has a resistance of 5 ohms at 0oC and 5.5 ohms at 100oC. Calculate the temperature of the wire when the resistance is 5.2 ohms

80oC

60oC

40oC

10oC

Answer Details

100oC .... 5.5

$θ$ oC .... 5.3

0oC .... 5.0

$\frac{θ - 0}{100 - 0}$ = $\frac{5.5 - 5 .0}{5.5 - 5.0}$

$θ$ = 40oC

Read lesson note on Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

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Question 10 Report

In the diagram above, the hanging mass m2 is adjusted until m1 is on the verge of sliding. The coefficient of static friction between the mass m1 and the table is

m1/m2

m1g/m2

m2/m1

m2g/m1

Friction

Equilibrium Of Forces

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Question 11 Report

In A.C circuit theory, the root means square (r.m.s) current, Irms and the peak (maximum)current Io are related by

Io =

\frac{I_{r} m s}{\sqrt{2}}

Io =

\frac{I_{r} m s}{\sqrt{2}}

Irms =

\frac{\frac{I}{I_{o}}}{\sqrt{2}}

Irms =

\frac{I_{r} m s}{\sqrt{2}}

View Answer

Question 12 Report

A man weight 800N climbs up a stairs to height of 15m in 12.5s. What is the man''s average power output?

667W

810W

960W

15000W

Answer Details

The question is asking about the average power output of a man who climbs a set of stairs. Power is the rate at which work is done or energy is transferred, and it is calculated by dividing the work or energy by the time taken to do it. In this case, the work done is equal to the force exerted by the man (800N) multiplied by the distance he climbs (15m), which is equal to 12,000 joules (J). The time taken to climb the stairs is given as 12.5 seconds. Therefore, the man's average power output is the work done divided by the time taken, which is equal to 960 watts (W). So the answer is 960W.

Read lesson note on Current Electricity (JAMB)

Current Electricity

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Question 13 Report

A machine requires 1000J of work to raise a load of 500N through a vertical distance of 1.5m. Calculate the efficiency of the

80%

75%

50%

33%

Answer Details

\frac{500 \times 1.5}{100.0}

x 100%

= 75%

Read lesson note on Work, Energy And Power (WAEC)

Work, Energy And Power

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Question 14 Report

After three half lifes, the fraction of a radioactive material that has decayed is

1

8

1

3

2

3

7

8

Answer Details

The fraction of a radioactive material that has decayed after three half-lives is represented by the second option:

1

3

Explanation: The half-life of a radioactive material is the amount of time it takes for half of the radioactive atoms to decay. After one half-life, half of the original radioactive material has decayed. After two half-lives, only one-fourth (1/2 x 1/2) of the original radioactive material remains. After three half-lives, only one-eighth (1/2 x 1/2 x 1/2) of the original radioactive material remains, meaning that seven-eighths (1 - 1/8 = 7/8) of the material has decayed. Therefore, the fraction of radioactive material that has decayed after three half-lives is 7/8.

Read lesson note on Electromagnetic Field (Part 2) (WAEC)

Electromagnetic Field (Part 2)

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Question 15 Report

A bridge made of steel is 600m long. What is the daily variation in its length if the night-time and daytime temperatures are 10oC and 35oC respectively. The linear expansivity of steel is 0.000012C-1

0.18cm

1.80cm

18.00cm

1800cm

Answer Details

The variation in the length of the steel bridge can be calculated using the formula: ΔL = LαΔT where ΔL is the variation in length, L is the original length of the bridge, α is the linear expansivity of steel, and ΔT is the difference in temperature. In this case, the bridge is 600m long, the linear expansivity of steel is 0.000012C^-1, and the difference in temperature between night and day is 25°C (35°C - 10°C). Substituting these values into the formula: ΔL = (600m)(0.000012C^-1)(25°C) = 0.18m Therefore, the daily variation in the length of the steel bridge is 0.18m or 18cm. So the correct option is 0.18cm.

Read lesson note on Temperature And Its Measurement (JAMB)

Temperature And Its Measurement

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Question 16 Report

The space between the double glass walls of a thermos flask is evacuated space are silvered. The residual source of heat loss takes place by

convection

radiation from the surface

conduction through the stopper and the glass

conduction across the walls

Heat Transfer

Temperature And Its Measurement

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Question 17 Report

Which of the following factors has no effect on the e.m.f. of a primary cell?

temperature

size of the cell

nature of the plate

nature of the electrolyte

Electric Cells

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Question 18 Report

The maximum permissible current through a galvanometer G of internal resistance $10\ \Omega$ is 0.05A. A resistance R is used to convert G into a voltmeter with a maximum reading of 100V. Find the value of R and how it is connected to G

20,000 ohms in parallel

19,990 ohms in series

1990 ohms in series

100 ohms in series

Answer Details

The question is asking for the value of the resistor R that needs to be connected to a galvanometer G of internal resistance 10 ohms, to convert it into a voltmeter with a maximum reading of 100V. The maximum current that can flow through the galvanometer is given as 0.05A. To convert the galvanometer into a voltmeter, a resistor needs to be connected in series with it. The value of this resistor can be calculated using the formula: R = (Vmax/Ig) - Rg Where R is the value of the resistor to be connected, Vmax is the maximum voltage that the voltmeter can read (in this case, 100V), Ig is the maximum current that can flow through the galvanometer (0.05A), and Rg is the internal resistance of the galvanometer (10 ohms). Substituting the given values, we get: R = (100/0.05) - 10 R = 1990 ohms Therefore, the value of the resistor R that needs to be connected in series with the galvanometer G is 1990 ohms. It should be connected in series with the galvanometer to convert it into a voltmeter. So, the correct answer is "1990 ohms in series".

Read lesson note on Current Electricity (JAMB)

Current Electricity

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Question 19 Report

The equation of a wave is y = 0.005 sin[x(0.5X - 200t)] where x and y are in meters and t is in seconds. What is the velocity of the wave?

4000ms-1

400ms-1

250ms-1

40ms-1

Answer Details

y = 0.005 sin[x(0.5X - 200t)]

compare to Y = A sin(kx - wt)

$λ$ = $\frac{2 π}{k}$ and F = $\frac{w}{2 π}$

V= $λ$ F

= $\frac{2 π}{0.5}$ x $\frac{200}{2 π}$

= 400ms-1

Read lesson note on Types Of Waves (WAEC)

Types Of Waves

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Question 20 Report

Which of the following properties make the convex mirror useful as a driving mirror? i. the image is real. ii. the image is erect. iii. it has a wide field of view. iv. the image is magnified.

i, ii, and iv

i, ii, iii

ii and iii

i and iii

Answer Details

The properties that make a convex mirror useful as a driving mirror are: - The image formed by the mirror is virtual, meaning it is not real, but appears to be behind the mirror. This is the opposite of a real image, which is formed in front of the mirror. So, statement i is incorrect. - The image formed by the mirror is erect, meaning it is not inverted. This is important for a driving mirror because it allows the driver to quickly and easily interpret the image without confusion. So, statement ii is correct. - The mirror has a wide field of view, which means that it can reflect light from a larger area compared to a flat mirror or concave mirror. This allows the driver to see more of the surroundings, making it easier to spot potential hazards. So, statement iii is correct. - The image formed by a convex mirror is smaller than the object itself. This is the opposite of magnification, which would make the image larger. So, statement iv is incorrect. Therefore, the correct answer is option ii and iii.

Read lesson note on Electrostatics (JAMB)

Electrostatics

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Question 21 Report

The circuit diagram above contains four ammeters W, X, Y and Z, Which of the following statements about the ammeter readings is correct

The reading of W is equal to that of Y and twice that of X

The reading of Y is greater than that of Z

The readings of W and Y are equal and each is greater than that of X

The reading of Z is equal to the sum of the readings of Y and W

Current Electricity

Capacitors

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Question 22 Report

Which of the following affects the period of a simple pendulum? i. mass of the pendulum bob. ii. length of the pendulum. iii. acceleration due to gravity.

i, ii, and iii

ii and iii only

i and iii only

i and ii only

Gravitational Field

Equilibrium Of Forces

Measurements And Units

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Question 23 Report

What is the frequency of the sound made by a siren having a disc with 32 holes and making 25 revolution per seconds?

80Hz

600Hz

800Hz

1600Hz

Answer Details

The frequency of the sound produced by a siren is determined by the number of sound waves produced per second, which depends on the number of times the sound source completes a full cycle of motion per second. For a siren with a rotating disc and multiple holes, the frequency of the sound produced is equal to the product of the number of holes on the disc and the number of revolutions per second. In this case, the siren has 32 holes on the disc and makes 25 revolutions per second, so the frequency of the sound produced would be: Frequency = 32 holes/disc * 25 revolutions/second = 800 Hz Therefore, the correct answer is option C) 800Hz.

Read lesson note on Propagation Of Sound Waves (JAMB)

Propagation Of Sound Waves

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Question 24 Report

In an experiment to determine Young's Modulus for a wire, several loads are attached to the wire and the corresponding extension measured. The tensile stress in each case depends on the

load and the extension

load and the radius of the wire

radius of the wire and the extension

extension and the original length of the wire

Temperature And Its Measurement

Elasticity

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Question 25 Report

A 5-v battery is connected across the plates of a $2.0\,\mu\text{F}$ uncharged parallel plate capacitor. The charge on the capacitor after a long time is

2.5

μ

C

10.0

μ

C

20.0

μ

C

50.0

μ

C

Answer Details

The charge stored in a capacitor is given by the formula Q = CV, where Q is the charge, C is the capacitance, and V is the voltage across the capacitor. Initially, the capacitor is uncharged, so Q = 0. When the 5-volt battery is connected to the plates of the capacitor, the voltage across the capacitor becomes 5 V. Therefore, the charge on the capacitor becomes: Q = CV = (2.0 μF)(5 V) = 10.0 μC The charge on the capacitor will not change after a long time because a capacitor is an ideal device that stores charge without dissipating it. Therefore, the correct answer is 10.0μC.

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Question 26 Report

How much heat is absorbed when a block of copper of mass 0.05kg and specific heat capacity 390Jkg-1K-1 is heated from 20oC to 70oC?

39 . 98 x 10-1J

9.75 x 102J

3.98 x 103J

9.75 x 103J

Answer Details

The amount of heat absorbed by the copper block can be calculated using the formula: Q = mcΔT where Q is the amount of heat absorbed, m is the mass of the block, c is the specific heat capacity of copper, and ΔT is the change in temperature. Substituting the given values, we have: Q = (0.05 kg)(390 J/kg.K)(70°C - 20°C) Q = (0.05 kg)(390 J/kg.K)(50°C) Q = 975 J Therefore, the amount of heat absorbed by the copper block is 975 J. So, the correct option is: - 9.75 x 102J

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Heat Energy

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Question 27 Report

A note is the octave of another note if it has

a frequency twice that of the first note

frequency half that of the first note

the same fundamental frequency as the first one

a frequency frequency eight times that of the first note

Answer Details

In music, the term "octave" refers to the interval between two notes where the frequency of one note is double the frequency of the other. So, in the sentence, "A note is the octave of another note if it has," the correct option is "a frequency twice that of the first note." This means that if one note has a certain frequency, the note that is an octave higher will have a frequency that is exactly double that of the first note. For example, if one note has a frequency of 440 Hz, the note that is an octave higher will have a frequency of 880 Hz.

Read lesson note on Characteristics Of Sound Waves (JAMB)

Characteristics Of Sound Waves

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Question 28 Report

A concave mirror has a radius of curvature of 36cm. At what distance from the mirror should an object be placed to give a real image three times the size of the object?

12cm

24cm

48cm

108cm

Answer Details

F =

\frac{u v}{u + v}

v = 3u

18 = $\frac{3 u \times u}{3 u + u}$

u = 24cm

Read lesson note on Reflection Of Light At Plane And Curved Surfaces (JAMB)

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Reflection Of Light At Plane And Curved Surfaces

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 29 Report

The heat produced in a conductor carrying an electric current is

inversely proportional to the current and the resistance

directly proportional to the current, resistance and the time

inversely proportional to of the resistance, current and the time

directly proportional to the square of the current, the resistance and the time

Current Electricity

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Question 30 Report

The figure above shows the heights of two liquids X and Y when some air is sucked out of the apparatus through the pump P. The diameter of the table in X is twice That of the Tube In Y. What is the relative density of the liquid X with respect to liquid Y

1/3

2/3

3

6

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Question 31 Report

The speed of light in air is 3 x 108ms-1. What is the speed in glass with a refractive index of 1.50?

1.5 x 108ms-1

3.0 x 108ms-1

2.0 x 108ms-1

6.0 x 108ms-1

Answer Details

The speed of light changes as it passes through different media with different refractive indices. The refractive index of a medium is the ratio of the speed of light in a vacuum to the speed of light in that medium. The formula for finding the speed of light in a medium is: Speed of light in a medium = (Speed of light in a vacuum) / (Refractive index of the medium) In this question, the speed of light in air is given as 3 x 10^8 ms^-1, and the refractive index of the glass is given as 1.50. So, we can use the formula to find the speed of light in glass: Speed of light in glass = (Speed of light in air) / (Refractive index of glass) = (3 x 10^8) / 1.50 = 2 x 10^8 ms^-1 Therefore, the answer is option C, 2.0 x 10^8 ms^-1.

Read lesson note on Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum (WAEC)

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

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Question 32 Report

A boy sits in a train moving with uniform speed on a straight track. If from his outstretched palm he gently tosses his coin upwards, the coin will fall

in front of his palm

behind his palm

beside his palm

into his palm

Scalars And Vectors

Motion

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Question 33 Report

A uniform light rod is kept in horizontal equilibrium under the influence of fore forces as shown above, which of the following equations correctly represents the condition of equilibrium for the rod

F1 + F2 = F3 + F4

F1 + F2 - F3 + F = 0

(F1 + F2)ab = (F3 + F4)cd

F1a + F2b - F3c - F4d = 0

Simple A.C Circuits

Equilibrium Of Forces

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Question 34 Report

A capacitor of 10µF is connected across a cell of 12 volts as shown above, calculate the energy stored in the capacitor

7.2 x 10-4J

1.4 x 10-3J

1.2 x 10-2J

Answer Details

The energy stored in a capacitor is given by the formula: E = 1/2 * C * V^2 where E is the energy stored, C is the capacitance and V is the voltage across the capacitor. From the given information, the capacitance is 10µF and the voltage across the capacitor is 12V. Substituting these values in the formula, we get: E = 1/2 * 10µF * (12V)^2 E = 1/2 * 10^-5F * 144V^2 E = 7.2 x 10^-4 J Therefore, the energy stored in the capacitor is 7.2 x 10^-4 J. The option closest to this value is 7.2 x 10-4J.

Read lesson note on Capacitors (JAMB)

Capacitors

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Question 35 Report

The diagram above represents the field pattern obtained by bringing the poles of two magnets together.The poles must be

S-S poles

S-N poles

N-S poles

N-N poles

Magnetic Field (Part 2)

Electric Field

Magnets And Magnetic Fields

Electromagnetic Field (Part 2)

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Question 36 Report

Which of the following arrangements of the components of electromagnetic spectrum is in ascending order of wavelengths?

Gamma rays, ultraviolet rays, X- rays, infra - red rays

Gamma rays, X-rays, ultraviolet rays, infra-red rays

infra-red rays, ultraviolet rays, X-rays, gamma rays

Gamma rays, ultraviolet rays, infra-red rays, X-rays

Electromagnetic Waves: Types Of Radiation In Electromagnetic Spectrum

Electric Field

Light Waves

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Question 37 Report

Which of the following apparatus will require the smallest fuse rating for its protection?

60W, 240V

60W, 40V

40W, 12V

40W, 5V

Answer Details

I =

\frac{P}{V}

=

\frac{60}{240}

= 0.25A

I = $\frac{P}{V}$ = $\frac{60}{40}$ = 1.5A

I = $\frac{P}{V}$ = $\frac{40}{12}$ = 3.3A

I = $\frac{P}{V}$ = $\frac{40}{5}$ = 8A

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Read lesson note on Electrical Energy And Power (JAMB)

Current Electricity

Electrical Energy And Power

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Question 38 Report

One of the most important applications of bi-metallic strip is found in the construction of

a thermostat

an altimeter

a thermocouple

a hydrometer

Answer Details

Bi-metallic strips are made of two different metals bonded together, with different coefficients of thermal expansion. When the strip is heated, the two metals expand at different rates, causing the strip to bend. This bending action can be used to control a switch, which is the basis for a thermostat. As the temperature changes, the bi-metallic strip bends, causing the switch to turn on or off, controlling the heating or cooling system. Therefore, the correct answer is "a thermostat".

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Elasticity

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Question 39 Report

Calculate the force acting on an electron of charge 1.6 x 10-19C placed in an electric field of intensity 108Vm-1

1.6 x 10-11N

1.6 x 10-14N

1.6 x 10-16N

1.0 x 10-16N

Answer Details

The force (F) acting on an electron in an electric field is given by the equation F = qE, where q is the charge of the electron and E is the electric field intensity. Substituting the given values, we have: F = (1.6 x 10^-19 C) x (10^8 V/m) F = 1.6 x 10^-11 N Therefore, the force acting on the electron is 1.6 x 10^-11 N, which is option (A). Note that the force is very small due to the small charge of the electron and the relatively weak electric field intensity.

Read lesson note on Electric Field (WAEC)

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Electric Field

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 40 Report

At constant pressure, the density of a fixed mass of gas is

constant with temperature

proportional to its volume

inversely proportional to its temperature

independent of its volume

Answer Details

When the pressure of a gas is kept constant, the density of the gas will only be affected by changes in its temperature and volume. As the temperature of the gas increases, the density decreases, since the gas molecules move faster and take up more space. As the volume of the gas increases, the density decreases, since the same mass of gas is spread over a larger volume. Therefore, the correct option is: "inversely proportional to its temperature."

Read lesson note on Gas Laws (JAMB)

Read lesson note on Temperature And Its Measurement (JAMB)

Gas Laws

Temperature And Its Measurement

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Question 41 Report

The threshold of frequency for photoelectric effect depends on the

intensity of incident light

frquency of incident light

material of the photocathode

potential difference between the cathode and the anode

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 42 Report

A wire of length $15\text{ m}$ made of a material of resistivity $1.8 \times 10^{-6}\ \Omega\text{m}$ has a resistance of $0.27\ \Omega$. Determine the area of the wire

1.5 x 10-4m2

1.0 x 10-4m2

2.7 x 10-5m2

7.3 x 10-6m2

Answer Details

Resistivity =

\frac{Resiatance x Area}{l e n g t h}

1.6 x 10-6 = $\frac{15 \times A r e a}{0.27}$

Area = 1.0 x 10-4m2

View Answer

Question 43 Report

The angle between the direction of the earth's magnetic field and the horizontal is called the

angle of deviation

magnetic declination

magnetic meridian

angle of dip

Answer Details

The angle between the direction of the earth's magnetic field and the horizontal is called the "angle of dip". This angle is also known as the inclination angle and it measures the vertical angle between the Earth's magnetic field lines and the horizontal plane. The angle of dip changes depending on the location on Earth and it is used to determine the latitude of the location.

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Magnets And Magnetic Fields

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Question 44 Report

Which of the following characteristics of a wave is used in the measurement of the depth of the sea?

diffraction

interference

refraction

reflection

Production And Propagation Of Waves

Refraction Of Light Through Plane And Curved Surfaces

Properties Of Waves: Reflection, Refraction, Diffraction

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Question 45 Report

A body starts from rest and moves with uniform acceleration of 6ms-2. What distance does it cover in the third seconds

15m

18m

27m

30m

Motion

Speed And Velocity

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Question 46 Report

A block of ice floats on water inside a container. If the block of ice gets completely melted, the level of water in the container will

increase

remain the same

decrease

first decrease and then increase

Answer Details

When the block of ice floats on water, a part of it is submerged in the water and the remaining part is above the water. When the ice melts, it turns into water, and its volume decreases. However, the mass of the ice is equal to the mass of the water produced after melting. Therefore, the water produced from the melting of the ice will occupy the same volume as the submerged part of the ice. As a result, the water level in the container will remain the same after the ice melts, and so the correct answer is "remain the same".

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Fluid At Rest

Change Of State

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Question 47 Report

When an ebolite rod is rubbed with fur, it has

no charge at all

a negative charge

a positive charge

negative and positive charges

Answer Details

When an ebolite rod is rubbed with fur, it gains extra electrons from the fur, which causes the rod to have a surplus of negative charges, making it negatively charged. Therefore, the correct answer is "a negative charge".

Read lesson note on Properties Of Waves: Reflection, Refraction, Diffraction (WAEC)

Read lesson note on Electrostatics (JAMB)

Properties Of Waves: Reflection, Refraction, Diffraction

Electrostatics

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Question 48 Report

If a plastic sphere floats in water (density = 1000kgm3) with 0.5 of its volume submerged, and floats in oil with 0.4 of its volume submerged the density of the oil is

800kgm3

1200kgm3

1250kgm3

2000kgm3

Answer Details

R.d =

\frac{0.4}{0.5}

= 0.8

0.8 = $\frac{Density of oil}{Density of water}$

0.8 = $\frac{Density of oil}{1000}$

Density of oil = 800kgm3

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